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4.1.2Unit 4. Rates, Equilibria and Further Organic Chemistry

Rate Equations and Orders — IAL Edexcel Linear (Chemistry) Revision Notes & Topical Questions

5 min read 6 parts Lesson 11 of 56 Unit quiz

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Curriculum Equation Key معادلة تفاعل تكوين الإستر (الأسترة) - Esterification Reaction EquationFast Exam Solution
R-COOH + R2-OH ⇌ (conc. H₂SO₄) R-COO-R2 + H₂O
Word Equation & Conditions: حمض كربوكسيلي + كحول (في وجود حمض الكبريتيك المركز كعامل حفاز ونازع للماء) ⇌ إستر + ماء
Location & Specifications: الكيمياء العضوية للثانوية العامة والتحصيلي و Edexcel Chemistry.
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Part 1 of 6The Rate Equation

A rate equation shows how the rate depends on the concentration of each species.

Form
  • Form For A + B → products, rate = k[A]ᵐ[B]ⁿ, where m and n are the orders with respect to A and B.
Rate constant
  • Rate constant The constant k links rate to concentrations and is specific to one reaction at one temperature.
Overall order
  • Overall order This is the sum of the individual orders, m + n.
Experimental only
  • Experimental only The orders can only be found by experiment and cannot be read from the coefficients of the balanced equation.

Part 2 of 6Meaning of Order

Meaning of Order
Zero order
  • Zero order Changing the concentration has no effect on the rate, so the species does not appear in the rate equation.
First order
  • First order Doubling the concentration doubles the rate, because the rate is directly proportional to the concentration.
Second order
  • Second order Doubling the concentration increases the rate by a factor of four.
Catalysts
  • Catalysts A catalyst or an acid that does not appear in the stoichiometric equation can still appear in the rate equation.
OrderConcentration × 2Rate changes by
0× 2× 1
1× 2× 2
2× 2× 4
1× 3× 3

Part 3 of 6Units of k

1
Rearrange the rate equation to make k the subject, k = rate ÷ (concentration terms).
2
Substitute the units: rate is mol dm⁻³ s⁻¹ and concentration is mol dm⁻³.
3
Cancel the units algebraically, keeping the powers of each unit.
4
A first-order reaction gives k in s⁻¹ and a second-order reaction gives dm³ mol⁻¹ s⁻¹.
5
A third-order reaction gives dm⁶ mol⁻² s⁻¹, and a zero-order reaction gives mol dm⁻³ s⁻¹.

Part 4 of 6Using the Equation

Calculating rate
  • Calculating rate Substitute the concentrations and k into the rate equation to predict the rate of reaction.
Calculating k
  • Calculating k Use known concentrations and a measured rate and rearrange to find k.
Temperature
  • Temperature k increases with temperature, which is why rate rises as the mixture is heated.
Interpretation
  • Interpretation The order shows how many particles of a species are involved in the rate-determining step.

Part 5 of 6Worked Example

Question

  • The rate equation for a reaction is rate = k[A][B]².
  • When [A] = 0.20 mol dm⁻³ and [B] = 0.10 mol dm⁻³ the rate is 4.0 × 10⁻⁴ mol dm⁻³ s⁻¹.
  • Find k with units, then the rate when [A] = 0.40 and [B] = 0.20 mol dm⁻³.

  1. k = rate ÷ ([A][B]²) = 4.0 × 10⁻⁴ ÷ (0.20 × 0.10²) = 4.0 × 10⁻⁴ ÷ 2.0 × 10⁻³ = 0.20.
  2. Unitsmol dm⁻³ s⁻¹ ÷ (mol dm⁻³)³ = dm⁶ mol⁻² s⁻¹.
  3. New rate = 0.20 × 0.40 × 0.20² = 0.20 × 0.40 × 0.040 = 3.2 × 10⁻³ mol dm⁻³ s⁻¹.

Answer

  • k = 0.20 dm⁶ mol⁻² s⁻¹;
    • new rate = 3.2 × 10⁻³ mol dm⁻³ s⁻¹

Part 6 of 6Exam Checklist & Tips

4.1.2 – Key Points for the Exam

  • Rate equation An expression relating rate to the concentrations of reactants, each raised to its order.
  • Order of reaction The power to which the concentration of a species is raised in the rate equation.
  • Overall order The sum of the orders with respect to all species in the rate equation.
  • Rate constant The constant k in the rate equation, which depends on temperature.
  • Zero order A species whose concentration does not affect the rate.

Common Mistakes

  • Taking the orders from the coefficients in the balanced equation instead of from experiment.
  • Giving the units of k without working them out from the order of the reaction.
  • Forgetting that k changes with temperature, so it is not constant across different temperatures.
  • Including a zero-order reactant in the rate equation.

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