2.11Unit 2. Energetics, Group Chemistry, Halogenoalkanes and Alcohols
Organic Chemistry: Halogenoalkanes — IAL Edexcel Modular (Chemistry) Revision Notes & Topical Questions
5 min read 12 parts Lesson 10 of 12 2 quizzes
Lesson summary
2.11 Organic Chemistry: Halogenoalkanes — IAL EDEXCEL MODULAR (CHEMISTRY) notes: Name and classify halogenoalkanes, describe their reactions with OH⁻, CN⁻, NH₃ and ethanolic hydroxide, explain the nucleophilic substitution mechanism and compare hydrolysis rates.Prefixes — fluoro-…
- Repeated halogens
- Polar bond
- Nucleophile
- With aqueous hydroxide
- With water
- With cyanide
Section 1 of 12Naming halogenoalkanes
Prefixes
- Prefixes fluoro-, chloro-, bromo- and iodo- are added to the alkane name
Position
- Position a number shows which carbon carries the halogen, and substituents are listed alphabetically
- CH3CH2CH2Br is 1-bromopropane and CH3CH(Br)CH3 is 2-bromopropane.
- CH3CH(Cl)CH2Br is 1-bromo-2-chloropropane.
Repeated halogens
- Repeated halogens di- and tri- are used for identical halogens
Section 2 of 12Classifying halogenoalkanes
Classifying halogenoalkanes
Primary
- Primary the carbon bearing the halogen is attached to one other alkyl group
Secondary
- Secondary the carbon bearing the halogen is attached to two other alkyl groups
Tertiary
- Tertiary the carbon bearing the halogen is attached to three other alkyl groups
Polar bond
- Polar bond the C–X bond is polar because halogens are more electronegative, so the carbon is δ+ and open to nucleophilic attack
Section 3 of 12Nucleophiles and substitution
1Nucleophile
Nucleophile an electron-pair donor that is attracted to positively charged or δ+ species
- Examples are OH-, CN- and NH3.
2Nucleophilic substitution
- Nucleophilic substitution a nucleophile attacks the δ+ carbon and replaces the halogen
- The C–X bond breaks heterolytically, releasing X-.
Section 4 of 12Reactions of halogenoalkanes
With aqueous hydroxide
- With aqueous hydroxide forms an alcohol, in a hydrolysis reaction
- CH3CH2Br + OH- → CH3CH2OH + Br-.
- Warm aqueous NaOH or KOH is used, with ethanol as a co-solvent, and water must be the main solvent.
- Hydroxide is a better nucleophile than water because it has a full negative charge.
With water
- With water forms an alcohol much more slowly: RX + H2O → ROH + H+ + X-
- Silver nitrate in ethanol shows the halide ions as they form: Ag+ + X- → AgX.
With cyanide
- With cyanide forms a nitrile when heated under reflux with ethanolic KCN
- Bromoethane forms propanenitrile.
- The carbon chain is lengthened by one carbon atom.
With ammonia
- With ammonia forms a primary amine when heated under pressure with excess ethanolic ammonia
- Bromoethane forms ethylamine.
- Excess ammonia prevents further substitution because the amine product is more reactive than ammonia.
With ethanolic hydroxide
- With ethanolic hydroxide heated with ethanolic NaOH, hydrogen halide is eliminated to form an alkene
- CH3CH2Br + OH- → CH2=CH2 + H2O + Br-.
- Water as the main solvent gives substitution, but ethanolic conditions give elimination.
Section 5 of 12The nucleophilic substitution mechanism
1
The carbon of the polar C–X bond is δ+, so the lone pair of the nucleophile is attracted to it.
2
A curly arrow goes from the lone pair to the carbon, forming a new bond.
3
A second curly arrow goes from the C–X bond to the halogen.
4
The C–X bond breaks heterolytically and X- leaves, giving the substituted product.
- Ammonia
- reacts in two steps, with a second NH3 removing H+ from the intermediate
- CH3Cl + NH3 → [CH3NH3]+Cl-.
- [CH3NH3]+Cl- + NH3 → CH3NH2 + NH4+Cl-.
Section 6 of 12SN1 and SN2 (A-level extension)
SN2
- SN2 typical of primary halogenoalkanes: one step, with the nucleophile attacking from the side opposite the halogen
- It passes through a transition state with partial bonds.
- The rate is k[RX][OH−].
SN1
- SN1 typical of tertiary halogenoalkanes: the C–X bond breaks first to form a carbocation
- The carbocation is stabilised by electron-releasing alkyl groups, and bulky groups hinder backside attack.
- The rate is k[RX].
Section 7 of 12Measuring the rate of hydrolysis
Measuring the rate of hydrolysis
Set up test tubes in a 50 °C water bath, each with ethanol and acidified silver nitrate.
Add a few drops of a chloroalkane, a bromoalkane and an iodoalkane, and start a stopwatch.
Time how long each precipitate takes to appear.
1Results
- Results iodoalkane gives a yellow precipitate fastest, then bromoalkane (cream), with chloroalkane (white) slowest
- Fluoroalkanes do not react, because silver fluoride is soluble.
2Primary, secondary and tertiary
- Primary, secondary and tertiary with the same halogen and formula, tertiary reacts quickest and primary slowest
- 1-chlorobutane, 2-chlorobutane and 2-chloro-2-methylpropane can be compared.
Section 8 of 12Why bond enthalpy decides the trend
Bond enthalpy order
- C–F > C–Cl > C–Br > C–I
- The C–I bond is the weakest and is easiest to break, so iodoalkanes react fastest.
Polarity
- Polarity decreases down the group but is a less important factor than bond strength
- Polarity alone would predict fluoroalkanes to be the quickest to react.
Bond enthalpy, not polarity, decides the rate of hydrolysis
Section 9 of 12More on this topic
1Reactions with nucleophiles
- Reactions with nucleophiles the C–X bond is polar, so halogenoalkanes undergo nucleophilic substitution
- Aqueous hydroxide substitutes to give the alcohol.
2
Using polarity to explain the halogenoalkane rate order — bond enthalpy is the deciding factor
Section 10 of 12More from the specification
- Nucleophilic substitution in alcoholic solution
- heating halogenoalkanes with ethanolic potassium hydroxide solution produces alkenes via base-induced beta elimination.
Section 11 of 12Key terms
| Term | Meaning |
|---|---|
| Halogenoalkane | An alkane in which one or more hydrogens are replaced by halogen atoms. |
| Nucleophile | An electron-pair donor attracted to δ+ carbon atoms. |
| Nucleophilic substitution | Replacement of an atom or group by a nucleophile. |
| Hydrolysis | Breakdown of a compound by water or aqueous hydroxide. |
| Elimination | Removal of a small molecule such as HBr from a molecule to form a C=C bond. |
| Primary halogenoalkane | One where the C–X carbon is attached to one other alkyl group. |
| Carbocation | A positive ion with a positively charged carbon atom. |
Section 12 of 12Exam technique
1
Explaining the rate order by polarity — C–I is least polar but reacts fastest because its bond is weakest
2
Using ethanolic hydroxide and expecting substitution — ethanolic conditions give elimination to an alkene
3
Starting a curly arrow at the nucleophile's charge rather than at the lone pair
4
Using a limited amount of ammonia and expecting only a primary amine — excess ammonia is needed
5
Forgetting acidified silver nitrate in the hydrolysis test — halide ions must be detected as they form
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