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4.6.2Core Organic Chemistry

Synthetic Routes

5 min read 6 parts Lesson 25 of 29 Virtual lab

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Part 1 of 6Key Conversions

4.6.2 Synthetic Routes

A synthesis route is a sequence of reactions that converts a starting material into a target compound.

Alkane to haloalkane
  • Chlorine or bromine with UV light substitutes a hydrogen atom by a halogen.
Alkene to haloalkane
  • Hydrogen halide adds across the C=C bond at room temperature.
Alkene to alcohol
  • Steam with a phosphoric acid catalyst adds water across the double bond.
Haloalkane to alcohol
  • Warming with aqueous sodium hydroxide substitutes OH for the halogen.
Alcohol to alkene
  • Heating with concentrated sulfuric or phosphoric acid dehydrates the alcohol.

Part 2 of 6More Conversions

More Conversions
Primary alcohol to aldehyde
  • Distil with acidified potassium dichromate to remove the aldehyde as it forms.
Primary alcohol to acid
  • Reflux with excess acidified potassium dichromate to give the carboxylic acid.
Secondary alcohol to ketone
  • Heat with acidified dichromate to give the ketone.
Haloalkane to nitrile
  • Heating with ethanolic KCN adds a carbon atom and gives a nitrile.
Haloalkane to amine
  • Heating with excess ammonia in ethanol gives a primary amine.
FromToReagents and conditions
HaloalkaneAlcoholNaOH(aq), heat
AlkeneAlcoholSteam, H₃PO₄, 300 °C, 60–70 atm
AlcoholAlkeneConc. H₂SO₄ or H₃PO₄, heat
Primary alcoholCarboxylic acidK₂Cr₂O₇/H₂SO₄, reflux
HaloalkaneNitrileKCN in ethanol, reflux

Part 3 of 6Planning a Route

1
Identify the functional group in the starting material and in the target compound.
2
Work backwards from the target to find a reaction that makes that functional group.
3
Continue until you reach the starting material, listing reagents and conditions for each step.
4
Check that each intermediate is correct, and that conditions such as reflux or distillation are right for the product.
5
Write balanced equations for each step if required, using [O] for oxidations.

Part 4 of 6Overall Yield

Lost material
  • Each step loses some product through side reactions, incomplete reactions and losses during purification.
Overall yield
  • The overall percentage yield is found by multiplying the fractional yields for each step.
Many steps
  • A long route with several steps can have a low overall yield even if each step is efficient.
Atom economy
  • Routes with fewer steps and addition reactions waste fewer atoms and are often chosen in industry.

Part 5 of 6Worked Example

Question Suggest a two-step route from 1-bromopropane to propanoic acid, and find the overall yield if step 1 gives 80% and step 2 gives 70%.

  1. Step 1: heat 1-bromopropane with aqueous NaOH to give propan-1-ol: CH₃CH₂CH₂Br + OH⁻ → CH₃CH₂CH₂OH + Br⁻.
  2. Step 2: heat propan-1-ol under reflux with acidified potassium dichromate to give propanoic acid: CH₃CH₂CH₂OH + 2[O] → CH₃CH₂COOH + H₂O.
  3. Overall fractional yield = 0.80 × 0.70 = 0.56.
  4. Convert to a percentage.

Answer Overall yield = 56%

Part 6 of 6Exam Checklist & Tips

4.6.2 – Key Points for the Exam

  • Synthetic route A sequence of reactions that converts a starting material into a target compound.
  • Reflux Heating with a condenser so that volatile liquids return to the reaction flask.
  • Percentage yield Actual yield divided by theoretical yield, expressed as a percentage.
  • Intermediate A compound formed in one step of a synthesis and used in the next.

Common Mistakes

  • Giving 'heat' without naming the reagents, which loses marks in synthesis questions.
  • Confusing distillation and reflux for oxidation of primary alcohols.
  • Adding yields from separate steps instead of multiplying them.
  • Choosing a reaction that fails for the functional group present, such as oxidising a tertiary alcohol.
Try it in the virtual labIdentifying organic compounds \n