4.6.4Electrons, Waves and Photons
Graphical Representations of Transverse and Longitudinal Waves — OCR A Level Physics A H556 Revision Notes & Topical Questions
5 min read 5 parts Lesson 45 of 62 Unit quiz
Curriculum Equation Key Wave Speed & Doppler Effect FormulasFast Exam Solution
v = f × λ | f_obs = f × (v ± v_o) / (v ∓ v_s) | T = 1 / f
Part 1 of 5Two Types of Graph

The same wave can be plotted against distance or against time, and the two graphs reveal different quantities.
Displacement-distance
- This graph is a snapshot of all points along the wave at one instant; its repeat distance is the wavelength.
Displacement-time
- This graph follows one point as time passes; its repeat time is the period.
Amplitude
- On both graphs the amplitude is the maximum height of the curve above the equilibrium (zero) line.
Shape
- A single-frequency wave gives a sinusoidal curve in either graph.
Part 2 of 5Longitudinal Waves on a Graph
Longitudinal Waves on a Graph
Displacement meaning
- Positive displacement means a particle has moved in the direction of wave travel and negative means the opposite direction.
Graph shape
- Plotting displacement against distance gives the same sinusoidal curve as for a transverse wave.
Compressions
- Compressions occur where neighbouring particles are displaced towards each other, not at the peaks of the graph.
Rarefactions
- Rarefactions occur where neighbouring particles move apart, so the particles are spread widest there.
Part 3 of 5Reading the Graphs
1
Read the amplitude as the vertical distance from the zero line to a peak, remembering the units on the axis.
2
Read the wavelength from the horizontal distance between two successive peaks on the displacement-distance graph.
3
Read the period from the horizontal time between two successive peaks on the displacement-time graph.
4
Calculate the frequency from f = 1/T and then the wave speed from v = fλ.
5
Combine data from both graphs only when they describe the same wave.
Part 4 of 5Worked Example
Question
- A displacement-time graph shows 4 complete cycles in 0.020 s.
- A displacement-distance graph of the same wave has a wavelength of 0.50 m.
- Find the frequency and wave speed.
- Period T = 0.020 / 4 = 0.0050 s.
- Frequency f = 1/T = 1 / 0.0050 = 200 Hz.
- Wave speed v = fλ = 200 × 0.50 = 100 m s⁻¹.
Answer f = 200 Hz and v = 100 m s⁻¹.
Part 5 of 5Exam Checklist & Tips
4.6.4 – Key Points for the Exam
- Displacement-distance graph A graph of displacement against position along the wave at one instant.
- Displacement-time graph A graph of displacement of one point against time.
- Equilibrium position The position of a particle when no wave is present.
- Sinusoidal Having the smooth repeating shape of a sine or cosine curve.
Common Mistakes
- Reading wavelength from a displacement-time graph, where the repeat is the period.
- Assuming the peak of a longitudinal graph is a compression.
- Measuring amplitude from peak to trough instead of from the equilibrium line.
- Using the wrong graph to calculate frequency.
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