1.12Physical Chemistry
Equilibrium Constant Kp for Homogeneous Systems — Oxford AQA International A Level Chemistry Revision Notes & Topical Questions
5 min read 8 parts Lesson 12 of 13
Lesson summary
Complete PDF with figures and original page layoutPage 1 Oxford AQA International Your notes A Level (IAL) Chemistry Equilibrium Constant Kp for Homogeneous Systems Contents Equilibrium Constant Kp for Homogeneous Systems Kp Calculations …
Part 1 of 6K<sub>p</sub> expressions
1Gaseous equilibria
- Gaseous equilibria for aA(g) + bB(g) ⇌ cC(g) + dD(g), Kp = p(C)c p(D)d ÷ (p(A)a p(B)b)What the symbols mean: Kp = equilibrium constant in terms of partial pressures · p = partial pressure of each gas at equilibrium (Pa or kPa) · powers come from the balanced equation
2Terms
- Terms a, b, c and d are the coefficients, and p are equilibrium partial pressures in kPa
3Phases
- Phases solids and liquids are ignored
4Temperature
- Kp is constant and changes only if the temperature changes
5Notation
- Notation do not use square brackets, as they imply concentration and therefore Kc
| Equilibrium | Kp expression | Units |
|---|---|---|
| N2 + 3H2 ⇌ 2NH3 | p(NH3)2 ÷ (p(H2)3 p(N2)) | kPa-2 |
| N2O4 ⇌ 2NO2 | p(NO2)2 ÷ p(N2O4) | kPa |
| 2SO2 + O2 ⇌ 2SO3 | p(SO3)2 ÷ (p(SO2)2 p(O2)) | kPa-1 |
Part 2 of 6Effect of conditions on K<sub>p</sub>
Le Chatelier
- Le Chatelier it applies to gaseous equilibria as to aqueous ones, predicting the position and the value of Kp
Temperature
- Exothermic forward reactionheating shifts the equilibrium left, the ratio of products to reactants falls, so Kp decreases.
- Endothermic forward reactionheating shifts right, the ratio rises, so Kp increases.
Pressure
- Kp is unaffected by pressure.
- A pressure change shifts the position to a new position that restores the value of Kp.
Catalyst
- Kp is unaffected because the forward and reverse reactions are sped up equally.
- A catalyst only makes equilibrium be reached faster.
Part 3 of 6Partial pressure and mole fraction
Partial pressure and mole fraction
Why Kp
- Why Kp for gas mixtures it is easier to measure pressure than concentration
Partial pressure = the pressure a gas would have if it were alone in the container
Total pressure
- Ptotal = PA + PB + PC + …
Mole fraction = moles of one gas ÷ total moles of all gases
Equation
- Equation partial pressure = mole fraction × total pressure
Checks
- Checks mole fractions add up to 1, and partial pressures add up to the total pressure
Part 4 of 6Mole fractions and partial pressures with an ICE table
Mole fractions and partial pressures with an ICE table
Example
- 0.25 mol N2 and 0.75 mol H2 react, leaving 0.16 mol N2 at 75 kPa
Moles
- N2 changes by −0.09, H2 by −0.27 and NH3 by +0.18, so equilibrium moles are 0.16, 0.48 and 0.18, totalling 0.82
Mole fractions
- 0.195, 0.585 and 0.220
Partial pressures
- 14.625, 43.875 and 16.5 kPa, which add to 75 kPa
Part 5 of 6Calculating K<sub>p</sub> from partial pressures
Calculating K<sub>p</sub> from partial pressures
Write the Kp expression.
Substitute the equilibrium partial pressures.
Work out the units from the expression.
- Example
- 2SO2 + O2 ⇌ 2SO3 with partial pressures 1.0 × 106, 7.0 × 106 and 8.0 × 106 Pa gives Kp = 9.1 × 10-6 Pa-1
Part 6 of 6Calculating K<sub>p</sub> from moles and total pressure
1
Find the equilibrium moles of every gas.
2
Calculate the mole fractions.
3
Calculate the partial pressures.
4
Write the Kp expression.
5
Calculate Kp and its units.
Example
- H2 + I2 ⇌ 2HI with 1.71 × 10-3, 2.91 × 10-3 and 1.65 × 10-2 mol at 100 kPa has mole fractions 0.0810, 0.1378 and 0.7813, partial pressures 8.10, 13.78 and 78.13 kPa,
- and Kp = 54.7 with no units
Full question
- Full question it gives initial moles, equilibrium moles of at least one gas and total pressure,
- so the equilibrium moles of all gases must be deduced first
Mole fraction approach
- Mole fraction approach if H2 and Br2 are in a 1 : 1 ratio, their mole fractions are equal, and the mole fraction of HBr is the remainder up to 1
Key terms
| Term | Meaning |
|---|---|
| Kp | The equilibrium constant in terms of partial pressures of gases. |
| Partial pressure | The pressure a gas would exert if it were alone in the container. |
| Mole fraction | The moles of one gas divided by the total moles of gas. |
| Homogeneous equilibrium | An equilibrium in which all species are in the same phase. |
Avoid these mistakes
1
Using square brackets in Kp — use p for partial pressure.
2
Including solids or liquids in Kp — leave them out.
3
Thinking pressure changes Kp — only temperature does.
4
Using total pressure instead of partial pressures — convert with mole fractions.
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