1.1.5Forces and Their Effects
Investigating Force and Extension — Oxford AQA International GCSE Combined Science - Physics Revision Notes & Topical Questions
5 min read 7 parts Lesson 6 of 16
Part 1 of 5Aim and variables
| Item | Detail |
|---|---|
| Aim | To investigate the relationship between the force applied to a spring and its extension |
| Independent variable | Force, F, produced by the weight of the hanging masses (N) |
| Dependent variable | Extension of the spring, e (cm or m) |
| Control variables | The same spring, so the spring constant stays constant; the same ruler and starting point; same temperature |
| Resolution of ruler | 1 mm |
Part 2 of 5Equipment and its job
Support
- Support A clamp and stand hold the spring vertically and give an upward force on it.
Loads
- Loads Five 100 g masses and a mass hanger provide the downward force, added one at a time.
Measuring
- Measuring A ruler measures length, and a pointer attached to the bottom of the spring makes it easier to read the position accurately.
Part 3 of 5Method
1
Hang the spring from the clamp and place a ruler beside it; line up the pointer with a mark on the ruler and record the original length with no load.
2
Add the 100 g mass hanger and wait for the spring to stop moving.
3
Record the mass in kg and read the new position from the ruler.
4
Add another 100 g mass, wait until stationary, and record the new position.
5
Continue until all the masses have been added, then remove them.
6
Repeat the whole process two more times and calculate an average position for each load.
Part 4 of 5Processing the results
1Force
- Force The force is the weight of the masses: W = m × g, with g = 9.8 N/kg. For 0.1 kg the force is 0.98 N.
2Extension
- Extension Extension = final length − original length, so a spring that grows from 10.0 cm to 12.5 cm has e = 2.5 cm.
3Graph
- Graph Plot force against extension and draw a line of best fit.
4Conclusion
- Conclusion Where the graph is a straight line through the origin, force is directly proportional to extension, so F = k × e.
Part 5 of 5Errors, accuracy and safety
Evaluating the investigation
Systematic error
- Systematic error Read the ruler at eye level to avoid parallax error, and make sure it is vertical.
Random error
- Random error Wait for the spring to stop bouncing, measure from the same point at the bottom of the spring each time,
- and use a pointer to improve precision.
Limit of proportionality
- Limit of proportionality Do not overload the spring;
- beyond the limit of proportionality the graph curves and the spring may not return to its original length.
Safety
- Safety Wear eye protection in case the spring snaps, and keep feet clear of falling masses.
Key terms
| Term | Meaning |
|---|---|
| Extension | The increase in length of a spring compared with its original length. |
| Spring constant | A measure of the stiffness of a spring, in N/m, from F = k × e. |
| Limit of proportionality | The point beyond which the extension is no longer directly proportional to the force. |
| Parallax error | A reading error caused by viewing a scale from the wrong angle. |
| Resolution | The smallest change in a quantity that a measuring instrument can detect. |
Avoid these mistakes
1
Plotting the total length of the spring instead of the extension, so the line does not pass through the origin.
2
Using the mass in grams as the force instead of converting the mass to kg and calculating the weight.
3
Saying the spring obeys proportionality at all loads; a line that curves shows it has passed the limit of proportionality.
4
Taking readings while the spring is still bouncing.
5
Describing the relationship as 'directly proportional' for a straight line that does not go through the origin.
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