We need x − 2 ≥ 0, so x ≥ 2. The domain is [2, ∞[.
Example 3: domain of a rational function
Find the domain of f(x) = 1 / (x² − 9).
Solution The denominator must not be zero, so x² − 9 ≠ 0. Factoring gives (x − 3)(x + 3) ≠ 0, so x ≠ 3 and x ≠ −3. The domain is all real numbers except −3 and 3.
Example 4: a function with two conditions
Find the domain of f(x) = √(6 − 2x) / (x + 1).
Solution First condition: 6 − 2x ≥ 0, so 2x ≤ 6 and x ≤ 3. Second condition: x + 1 ≠ 0, so x ≠ −1. The domain is ]−∞, 3] with the value −1 removed.
Example 5: finding x from a known output
Comparison aspect
Main idea
Keywords
•
If f(x) = x² − 4x and f(x) = −3
find the value of x
findvalue
Solution
Write x² − 4x = −3
so x² − 4x + 3 = 0. Then (x − 1)(x − 3) = 0
which gives x = 1 or x = 3
WriteThengives
Check
f(1) = 1 − 4 = −3 and f(3) = 9 − 12 = −3. Both values are correct
Bothvaluescorrect
Real Functions · 4 / 6
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