Point 6 of 12 — Differentiation and Integration of Vector Functions and Newton’s Laws of MotionQuestion bank: 0 questions (0 with pictures)
06Vector functions in the plane
Differentiation component by component
If the position vector is r(t) = x(t) i + y(t) j, its derivative is found by differentiating each component: v = dr/dt = ẋ i + ẏ janda = dv/dt = ẍ i + ÿ j.
The magnitude of velocity is |v| = √(ẋ² + ẏ²); the magnitude of acceleration is found the same way.
Integration is also done component by component, and each component needs its own constant — together they form aconstant vector.
Worked example
A particle moves so that r = (t³ − 3t) i + 2t² j. Then v = (3t² − 3) i + 4t j and a = 6t i + 4 j. At t = 2: v = 9 i + 8 j and a = 12 i + 4 j.
|v| = √(81 + 64) = √145 ≈12.04 m/s.
Path elimination: from x = t³ − 3t and y = 2t² the trajectory can be studied by eliminating t; differentiating is usually far quicker than finding the cartesian path.
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