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1-1 (c) Parametric differentiation

1-1 (c) Parametric differentiation

Point 3 of 8 — Implicit Differentiation, Parametric Differentiation and Higher DerivativesQuestion bank: 0 questions (0 with pictures)

03 1-1 (c) Parametric differentiation

Parametric curves

  • If x=f(t) and y=g(t) with the same domain, the pair of equations describes one curve, and t is the parameter.
  • Each value of t gives one point (x,y) of the curve.

The rule

  • If f and g are differentiable in t and dxdt≠0, then dydx=dy/dtdx/dt
  • This is just the chain rule: dydt=dydx⋅dxdt.
  • Horizontal tangent: dydt=0 and dxdt≠0.
  • Vertical tangent: dxdt=0 and dydt≠0.
✍️ Worked examples

Example 6: For x=t2+1 and y=t3−3t find dydx when t=2.

Solution:

  • dxdt=2t and dydt=3t2−3.
  • dydx=3t2−32t.
  • At t=2: 12−34=94.

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