CHEMISTRY · Stage 9 · Chapter 12: Chemical Reactions 3 and Rates
Chemistry 12.2 Writing symbol equations — Balancing Chemical Equations
5 min read 6 parts Lesson 2 of 13
Lesson summary
12.2 Writing symbol equations — Balancing Chemical Equations — Alhussan International Academy — Chemistry (Stages 7–9) notes: Write balanced symbol equations with formulae and state symbols.Symbol equation — it shows the reactants and products, their chemical formulae, the relati…
- Precipitation example
- Balancing numbers
- Never change subscripts
- Lowest ratio
- Zinc and acid
- Start with
Section 1 of 6What a symbol equation shows
- Symbol equation
- it shows the reactants and products, their chemical formulae, the relative numbers of particles and the states.
- Formulae
- replace each name in the word equation with its formula, and never guess a formula but look it up.
- Diatomic elements are H2, N2, O2, F2, Cl2, Br2 and I2.
- Common formulae: water H2O, carbon dioxide CO2, methane CH4, magnesium oxide MgO, sodium chloride NaCl, hydrochloric acid HCl and sulfuric acid H2SO4.
- Precipitation example
- silver nitrate + potassium iodide → silver iodide + potassium nitrate: KI(aq) + AgNO3(aq) → AgI(s) + KNO3(aq).
- (yellow precipitate)
- It needs no balancing numbers because each element has the same number of atoms on both sides.
- silver nitrate + potassium iodide → silver iodide + potassium nitrate: KI(aq) + AgNO3(aq) → AgI(s) + KNO3(aq).
Section 2 of 6State symbols
- (s)
- solid.
- (l)
- liquid.
- (g)
- gas.
- (aq)
- aqueous, meaning dissolved in water.
- Placement
- write one state symbol to the right of each formula, in lower case.
Section 3 of 6Balancing method
- Write the word equation with the chemical formula under each substance.
- Count the atoms of each element on both sides.
- Add a big number in front of a formula to balance one element, usually leaving hydrogen and oxygen to the end.
- Recount all the elements and adjust.
- Check the final equation and add state symbols.
- Balancing numbers
- a big number applies to every atom in the formula that follows it, so 2MgO means two magnesium atoms and two oxygen atoms.
- Never change subscripts
- changing a small number changes the substance, for example MgO to MgO2.
- Lowest ratio
- the numbers should be in the lowest whole-number ratio.
- Brackets
- in Ca(OH)2 the number outside multiplies everything inside, giving one calcium, two oxygen and two hydrogen atoms.
Section 4 of 6Balanced equations
| Reaction | Balanced equation |
|---|---|
| Magnesium + oxygen | 2Mg(s) + O2(g) → 2MgO(s) |
| Zinc + hydrochloric acid | Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) |
| Hydrogen + oxygen | 2H2 + O2 → 2H2O |
| Methane burning | CH4 + 2O2 → CO2 + 2H2O |
| Magnesium + acid | Mg + 2HCl → MgCl2 + H2 |
| Sodium + water | 2Na + 2H2O → 2NaOH + H2 |
| Propane burning | C3H8 + 5O2 → 3CO2 + 4H2O |
| Aluminium + hydrochloric acid | 2Al + 6HCl → 2AlCl3 + 3H2 |
| Lithium + oxygen | 4Li + O2 → 2Li2O |
| Nitrogen + oxygen | N2 + O2 → 2NO |
Section 5 of 6Balancing magnesium and oxygen step by step
- Mg + O2 → MgO has two oxygen atoms on the left and one on the right.
- Put 2 in front of MgO: Mg + O2 → 2MgO, which balances oxygen.
- Now magnesium needs balancing: 2Mg + O2 → 2MgO.
- Add state symbols: 2Mg(s) + O2(g) → 2MgO(s).
- Zinc and acid
- one hydrogen on the left and two on the right means 2HCl, which gives one Zn, two H and two Cl on each side.
Section 6 of 6Strategies for harder equations
- Start with
- an element that appears in the fewest places, such as carbon in propane.
- Propane
- three carbon atoms need 3CO2, eight hydrogen atoms need 4H2O, and 3 × 2 + 4 = 10 oxygen atoms need 5O2.
- Even numbers
- if a diatomic molecule such as H2 forces odd and even counts, double the other coefficients.
- Check table
- list atom counts for left and right to avoid errors.
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