1.1A Physics Toolkit
Mathematics and Physics — American System Physics Revision Notes & Topical Questions
10 min read 7 parts Lesson 3 of 5 1 quiz
Use SI base and derived units and metric prefixes correctly.Speedspeed = distance ÷ time, v = d/t; distance in m, time in s, speed in m/s.Densitydensity = mass ÷ volume, ρ = m/V; kg/m3 (or g/cm3; 1 g/cm3 = 1000 kg/m3).Converting unitsmultiply by a conversion factor equal to 1, e.g.
- Area units square the conversion
- Multiplying powers of ten
- Dimensional check example
- Dimensional analysis
- The scientific method is cyclic
- A car travels at 90 km/h. Express this speed in m/s
Part 1 of 7Key ideas
Part 2 of 7Learning objectives
Part 3 of 7Essential knowledge
Part 4 of 7Process & sequence
Converting units with dimensional analysiswrite these steps in this order; each step is a marking point.
Part 5 of 7Worked examples
- 90 km/h × (1000 m / 1 km) × (1 h / 3600 s) = 90 000 m / 3600 s = 25 m/s.
- (Check: 90 ÷ 3.6 = 25.) Units km and h cancel, leaving m/s.
- Convertm = 540 g = 0.540 kg; V = 200 cm3 = 200 × 10−6 m3 = 2.00 × 10−4 m3. ρ = m/V = 0.540 / 2.00 × 10−4 = 2.70 × 103 kg/m3 (3 s.f.; this is aluminium).What the symbols mean: ρ = density (kg m−3 or g cm−3) · m = mass (kg) · V = volume (m3)
- Check540/200 = 2.70 g/cm3 × 1000 = 2700 kg/m3.
- Divide the numbers4.2 / 1.5 = 2.8.
- Divide powers103 / 10−2 = 103−(−2) = 105.
- Answer = 2.8 × 105 m/s .
- (2 s.f., because both data values have 2 s.f.)
Part 6 of 7Summary
Part 7 of 7Compare: Compare
| Prefix | Symbol | Multiplier | Example |
|---|---|---|---|
| giga | G | 109 | 1 GHz = 1 × 109 Hz |
| mega | M | 106 | 1 MJ = 1 × 106 J |
| kilo | k | 103 | 1 km = 1000 m |
| centi | c | 10−2 | 1 cm = 0.01 m |
| milli | m | 10−3 | 1 mm = 0.001 m |
| micro | μ | 10−6 | 1 μs = 1 × 10−6 s |
| nano | n | 10−9 | 1 nm = 1 × 10−9 m |
Capital M (mega) and lower-case m (milli) differ by a factor of 109 — always check the case.
| Rule | Example | Sig. figs |
|---|---|---|
| All non-zero digits count | 4.72 m | 3 |
| Zeros between non-zero digits count | 2.05 kg | 3 |
| Leading zeros never count | 0.0036 s | 2 |
| Trailing zeros after a decimal point count | 5.40 cm | 3 |
| Multiply/divide: answer has fewest sig. figs of the data | 2.5 × 3.14 = 7.9 | 2 |
| Add/subtract: answer has fewest decimal places of the data | 12.1 + 0.25 = 12.4 | 1 d.p. |
Key terms
Command terms
Exam technique
Keywords the mark scheme looks for in this lesson
How to get full marks (examiner guidance)
Words to avoid
Instant feedbackCheck yourself
Q1. Which is an SI base unit?
- A. newton
- B. joule
- C. kilogram
- D. watt
Show answer
C. The kilogram is one of the seven base units; the others listed are derived units.
Q2. How many significant figures are in 0.004050 m?
- A. 3
- B. 4
- C. 6
- D. 7
Show answer
B. Leading zeros do not count; 4, 0, 5 and the trailing 0 after the decimal point count: 4 s.f.
Q3. What is 36 km/h in m/s?
- A. 3.6 m/s
- B. 10 m/s
- C. 36 m/s
- D. 130 m/s
Show answer
B. 36 ÷ 3.6 = 10 m/s.
Q4. An equation gives a result with units m·s. The quantity is supposed to be a speed. What does this show?
Show answer
C. Speed must come out in m/s; mismatched units reveal an algebra error.
Q5. 5.0 × 104 × 3.0 × 10−6 equals
Show answer
A. 5.0 × 3.0 = 15; 104 × 10−6 = 10−2; 15 × 10−2 = 1.5 × 10−1.
Q6. Which statement best describes a scientific theory?
Show answer
B. Theories explain observations, are well supported, but remain open to revision.
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