23.3Solid-State Electronics
Transistors, Logic Gates and Integrated Circuits — American System Physics Revision Notes & Topical Questions
10 min read 7 parts Lesson 5 of 5 1 quiz
Describe the structure of an npn transistor and use β = IC/IB.Current gain = collector current ÷ base currentβ = IC/IB (no unit).Emitter current = collector current + base current: IE = IC + IB (A).Potential divider outputVout = Vin × R2/(R1 + R2) (V), where R2 is the resistor th…
- Base resistor
- Logic gates
- Bipolar junction transistor (BJT)
- Base current (IB)
- Current gain (β)
- Transistor as a switch
Section 1 of 7Transistors, Logic Gates and Integrated Circuits
Section 2 of 7Process & sequence
- Swap the LDR and resistor to make a light-activated switch instead.
Transistor dark-activated switch sequencewrite these steps in this order; each step is a marking point.
Section 3 of 7Compare
| A | B | AND | OR | NAND | NOR |
|---|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 1 | 1 |
| 0 | 1 | 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 1 | 1 | 0 |
| 1 | 1 | 1 | 1 | 0 | 0 |
NOT gate
- one input;
- output is the opposite (0 → 1, 1 → 0).
- NAND = AND followed by NOT;
- NOR = OR followed by NOT.
| Use | How it operates | Example |
|---|---|---|
| Switch | Base p.d. above/below 0.7 V turns collector current on/off | Automatic night light with an LDR |
| Amplifier | Small changes in IB give large changes in IC | Microphone amplifier, hearing aid |
| Logic | Combinations of transistors act as gates | Computer processors, memory |
Section 4 of 7Worked examples
- IC = βIB = 150 × 40 × 10−6 = 6.0 × 10−3 A (6.0 mA). IE = IC + IB = 6.0 mA + 0.040 mA = 6.04 mA (6.0 × 10−3 A).
- Vout = 6.0 × 2.0/(10 + 2.0) = 6.0 × 0.167 = 1.0 V. This exceeds 0.7 V, so the transistor is on.
- Output = A AND (NOT B). Rows: A=0,B=0 → 0; A=0,B=1 → 0; A=1,B=0 → 1; A=1,B=1 → 0. Only one row gives 1.
Section 5 of 7Key terms
Section 6 of 7Command terms
Section 7 of 7Exam technique
Keywords the mark scheme looks for in this lesson
How to get full marks (examiner guidance)
Words to avoid
Instant feedbackCheck yourself
Q1. A transistor has β = 100 and base current 0.20 mA. The collector current is
- A. 0.002 mA
- B. 20 mA
- C. 2.0 mA
- D. 200 mA
Show answer
B. IC = 100 × 0.20 mA = 20 mA.
Q2. Which gate outputs 1 only when both inputs are 0?
- A. NOR
- B. NAND
- C. AND
- D. OR
Show answer
A. NOR is the inverse of OR, so 1 only when no input is 1.
Q3. A NAND gate has inputs A = 1, B = 1. The output is
- A. 1
- B. Cannot be determined
- C. 2
- D. 0
Show answer
D. AND gives 1, then NOT gives 0.
Q4. Why is a digital signal less affected by noise than an analogue one?
Show answer
C. Only two levels need to be distinguished, so it can be regenerated.
Q5. A silicon transistor switches on when its base–emitter p.d. exceeds about
- A. 0.7 V
- B. 0.07 V
- C. 7 V
- D. 70 V
Show answer
A. The base–emitter junction is a silicon diode.
Q6. In a temperature alarm using an NTC thermistor, as the temperature rises the thermistor's resistance
Show answer
B. NTC: more carriers when hot, lower resistance.
Marked practiceQuizzes for this lesson
Last updated:
