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Kinetics

Reaction Rates — AP CHEMISTRY Revision Notes & Topical Questions

5 min read 10 parts Lesson 3 of 14 Unit quiz

📚 AP CHEMISTRY Hub / Topical Revision
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Reaction Rates — AP CHEMISTRY notes: Measure reaction rate, relate rate to stoichiometry, determine rate laws and orders, use integrated rate laws and half-life, and explain catalysis.Rate of reaction = change in concentration of a reactant or product per unit time, in M s−1.By c…

  • Instantaneous rate
  • For aA + bB → cC + dD, rate
  • Pressure of gases
  • Temperature
  • Surface area of solids
  • Zero order

Section 1 of 10Measuring rate

Rate of reaction
Rate of reaction change in concentration of a reactant or product per unit time, in M s−1.
By convention the rate is positive.
  • For a product, rate = Δ[product]/Δt.
  • For a reactant, rate = −Δ[reactant]/Δt.
On a concentration-time graph the steeper the gradient the faster the rate.
Instantaneous rate
Instantaneous rate the gradient of a tangent drawn to the curve at that time.
Reactant graphs need the sign changed so the rate is positive.

Section 2 of 10Stoichiometry and rate

1For aA + bB → cC + dD, rate
−(1/a)Δ[A]/Δt = −(1/b)Δ[B]/Δt = (1/c)Δ[C]/Δt = (1/d)Δ[D]/Δt.
2
This gives one positive rate that is independent of the substance used to measure it.

Section 3 of 10Factors affecting rate

Concentration
  • Concentration more particles in the same volume give more successful collisions.
Pressure of gases
  • Pressure of gases particles occupy less space, so collisions are more frequent.
Temperature
  • Temperature particles have more kinetic energy, so more collisions are successful.
Surface area of solids
  • Surface area of solids more particles are available to collide.
Catalyst
  • Catalyst an alternative path with lower activation energy.
These factors change only the rate, not the amount of product or reactant consumed.

Section 4 of 10Rate law and order

1
Rate law
  • Rate = k[A]m[B]n, where m and n are orders found only by experiment.
2
Intermediates do not appear in rate equations.
3
Zero order
  • Zero order changing the concentration has no effect on rate, so it is left out.
4
First order
  • First order rate is proportional to concentration, so doubling the concentration doubles the rate.
5
Second order
  • Second order doubling the concentration increases the rate by a factor of 4.
6
Overall order
Overall order sum of the individual orders.
7
Method of initial rates
  • Method of initial rates compare experiments where one concentration changes at a time and use order = change in rate.
    • (change in concentration)
8
Units of k follow from the overall order: M s−1 (zero), s−1 (first) and M−1 s−1 (second).

Section 5 of 10Concentration-time graphs

1Zero order
  • [A] against t is a straight line going down with slope −k.
2First order
  • [A] against t is a curve that falls and levels out.
3Second order
  • [A] against t falls more steeply, then levels out.
OrderIntegrated lawStraight-line plotSlopeIntercept
Zero[A]t = −kt + [A]0[A] against t−k[A]0
Firstln[A]t = −kt + ln[A]0ln[A] against t−kln[A]0
Second1/[A]t = kt + 1/[A]01/[A] against tk1/[A]0
Concentration-time graphs
The plot that gives a straight line identifies the order.
The integrated laws for first and second order are given in the AP equations sheet.

Section 6 of 10Half-life

1Half-life (t1/2)
Half-life (t1/2) time for the concentration of a reactant to fall to half its initial value.
2First order
  • First order t1/2 = 0.693/k, constant throughout the reaction and independent of initial concentration.
3
Radioactive decay is first order; uranium-238 has a very long half-life so it decays slowly.
4
Zero and second order half-lives depend on initial concentration (zero: [A]0/2k; second: 1/k[A]0); the AP course description specifically covers only first-order half-life.

Section 7 of 10Catalysts

1
A catalyst increases the rate without being consumed overall.
2
It provides an alternative mechanism with lower activation energy, so a greater fraction of collisions are effective and k increases.
3
It may also improve orientation, increasing the frequency factor A.
4
A catalyst does not change ΔH, the energies of reactants and products, the kinetic energy of molecules, the yield or the equilibrium position.
5
It speeds forward and reverse reactions equally.
6
In a mechanism a catalyst is consumed in an early step and regenerated in a later one, and it can appear in the rate law.

Section 8 of 10More from the specification

More from the specification
Initial rate determination from tangents
  • Initial rate determination from tangents calculating the gradient of concentration curves provides a graphical means to evaluate initial chemical reaction rates.
Decomposition
  • A reaction where one compound breaks down into simpler substances.
Hydrogen
  • A gas that gives a squeaky pop with a lighted splint.

Section 9 of 10Key terms

TermMeaning
Reaction rateChange in concentration per unit time.
Rate lawEquation relating rate to reactant concentrations.
Order of reactionPower of a concentration in the rate law.
Rate constantProportionality constant k in the rate law.
Half-lifeTime for a reactant concentration to halve.
Integrated rate lawEquation relating concentration to time.

Section 10 of 10Exam technique

1
Giving the rate of a reactant as a negative value — the rate is positive by convention
2
Writing orders from the balanced overall equation — they must come from experiment
3
Saying temperature changes the order — it changes k only
4
Saying a catalyst changes the yield or ΔH — it only lowers the activation energy

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