5.2Kinetics
Introduction to Rate Law — AP CHEMISTRY Revision Notes & Topical Questions
5 min read 9 parts Lesson 5 of 14 1 quiz
Lesson summary
5.2 Introduction to Rate Law — AP CHEMISTRY notes: Write rate laws, state reaction orders and the rate constant, and determine orders from initial-rate data.Rate law — an equation relating the rate to reactant concentrations: rate = k[A]m[B]nWhat the symbols mean: rate (mol dm−3 …
- Rate constant k
- Order with respect to a reactant
- Overall order
- Units of k
- First-order case
- Concentration doubled and rate doubled
Section 1 of 9The rate law
Rate law
- Rate law an equation relating the rate to reactant concentrations: rate = k[A]m[B]nWhat the symbols mean: rate (mol dm−3 s−1) · k = rate constant · [ ] = concentration (mol dm−3) · each power is the order with respect to that reactant
- (units depend on the overall order)
- k is the rate constant and m and n are the orders with respect to A and B.
- Rate laws are found only by experiment, because they depend on the mechanism.
- Intermediates do not appear in the experimental rate law.
Rate constant k
- Rate constant k the proportionality constant linking rate to concentration
- Its value depends on temperature and on the reaction, not on concentration.
Section 2 of 9Reaction order
| Order | Effect of doubling [A] | Appears in rate law? | Units of k (per second) |
|---|---|---|---|
| Zero | No change in rate | No | M s-1 |
| First | Rate doubles | Yes, [A] | s-1 |
| Second | Rate increases fourfold | Yes, [A]2 | M-1 s-1 |
Section 3 of 9Overall order and units of k
Overall order and units of k
Order with respect to a reactant
- Order with respect to a reactant the power to which its concentration is raised in the rate law
Overall order
- Overall order the sum of the orders of all reactants in the rate law
Units of k
- Units of k found by rearranging rate = k[A]m
- Units of k = units of rate ÷ (units of concentration)overall order.
- The units of k therefore reveal the overall order.
Section 4 of 9Rate against concentration data
- First-order case
- a plot of rate against [D] is a straight line through the origin
- Rate = k[D], so doubling [D] doubles the rate.
- The gradient of the line equals k.
Section 5 of 9Determining orders from initial-rate data
1
Choose two experiments in which only one reactant concentration changes.
2
State how that concentration changed.
3
State how the initial rate changed.
4
Use (change in concentration)order = change in rate to find the order.
5
Repeat for each reactant, then write the rate law and calculate k from any experiment.
Section 6 of 9Reading the order from the exponent
Reading the order from the exponent
Concentration doubled and rate doubled
- Concentration doubled and rate doubled first order, since 21 = 2
Concentration doubled and rate quadrupled
- Concentration doubled and rate quadrupled second order, since 22 = 4
Concentration doubled and no rate change
- Concentration doubled and no rate change zero order, so the reactant is left out of the rate law
Section 7 of 9More from the specification
1Empirical rate law and reaction order
- Empirical rate law and reaction order measuring initial reaction rates across varied concentrations provides an experimental means to formulate rate laws.
2Hydrogen
- A gas that gives a squeaky pop with a lighted splint.
3Activation energy
- The minimum energy colliding particles need to react.
4Successful collision
- A collision with the correct orientation and enough energy to react.
5Catalyst
- A substance that speeds up a reaction and is not used up.
6Half-life
- The time for the concentration of a reactant to halve.
7Product
- A substance formed in a reaction.
8Decomposition
- A reaction where one compound breaks down into simpler substances.
Section 8 of 9Key terms
| Term | Meaning |
|---|---|
| Rate law | Equation relating reaction rate to reactant concentrations. |
| Rate constant (k) | Proportionality constant in the rate law, constant at a given temperature. |
| Reaction order | Exponent of a reactant concentration in the rate law. |
| Overall order | Sum of all individual orders in the rate law. |
| Initial rate | Rate measured at the start of a reaction before concentrations change appreciably. |
Section 9 of 9Exam technique
1
Writing the rate law from the balanced overall equation — orders must be found from experiment, not from coefficients.
2
Including zero-order reactants in the rate law — a zero-order reactant has no effect on rate, so it is omitted.
3
Thinking k changes with concentration — k depends on temperature (and catalyst) only.
4
Changing two concentrations at once when finding an order — only one concentration may change between the two experiments compared.
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