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1.4.5Motion, Forces and Energy

Hooke’s Law — Cambridge IGCSE Co-ordinated Sciences 0654 - Physics Revision Notes & Topical Questions

5 min read 9 parts Lesson 18 of 36

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Section 1 of 9Hooke's law

For a spring (or wire) stretched within its limit of proportionality, the extension is directly proportional to the force applied:

F = k x

What the symbols mean: F = force (N) · k = spring constant (N m−1) · x or e = extension (m)

F is the force in newtons (N), x is the extension in metres (m) and k is the spring constant in N/m. A larger k means a stiffer spring. The law applies equally to compression, where x is the decrease in length.

Hooke's law is a statement about a material, not a universal law: it describes the behaviour of springs and many metal wires only while the stretching is small.

Hooke's law
Engineers use it to design suspension springs, weighing machines and the force sensors in electronic scales,
  • where a measured extension is converted into a force reading.
The idea also tells us that if a spring is stretched twice as far, it pulls back twice as hard.

Section 2 of 9The force–extension graph

With force on the y-axis and extension on the x-axis:

The force–extension graph
Straight line through the origin
the initial part is a straight line through the origin; its gradient is k;
Limit of proportionality
beyond the limit of proportionality the line curves, so extension grows faster than the force;
Elastic limit
beyond the elastic limit the material no longer returns to its original length when the load is removed; it has been plastically deformed.

For many springs these two limits are very close together.

The spring constant depends on the material and construction of the spring: thicker wire, fewer coils and a smaller coil radius all make a spring stiffer.

The force–extension graph
For a graph drawn with extension on the y-axis, the gradient is 1/k, so always check which axis is which before reading off k.
Looking at two springs on the same graph, the steeper force–extension line is the stiffer one.

Section 3 of 9Elastic and plastic behaviour

In elastic deformation the object returns to its original shape when the force is removed. In plastic deformation some extension remains. A spring overloaded beyond its elastic limit becomes longer and weaker.

Metal wires obey Hooke's law at small loads and then show a yield point and plastic flow. Materials used for car crumple zones are chosen to deform plastically and absorb energy, while materials for trampoline springs are chosen to stay elastic. Whether an object is elastic or plastic depends on how far it is stretched.

Section 4 of 9Energy stored (Supplement)

Work is done when a spring is stretched, and this is stored as elastic potential energy. It equals the area under the force–extension graph. For a spring within the limit of proportionality the area is a triangle:

E = ½ F x = ½ k x2

What the symbols mean: E = elastic potential energy stored (J) · k = spring constant (N m−1) · x = extension (m) · F = force (N)

E is in joules (J). If the extension is doubled, the stored energy increases by four times.

When a spring is stretched, the work done by the force is the average force times the extension.

Energy stored (Supplement)
The average of a force rising steadily from 0 to F is F/2, so work = ½Fx.
With F = kx, this becomes ½kx2.
This energy is released when the spring is let go, for example in a toy dart gun, and it appears as kinetic energy of the dart.

Section 5 of 9Other materials

A rubber band does not obey Hooke's law: its force–extension graph is an S-shaped curve, and it takes a different path on unloading (hysteresis). A copper wire behaves like a spring at small loads but shows plastic stretching earlier.

To find the spring constant from experimental data, choose two points far apart on the straight part of the graph and use k = ΔF/Δx, which also removes the effect of any zero error in the measurement of the original length. Quote the result to a sensible number of significant figures, and give the unit, N/m.

Section 6 of 9Combining springs

Two identical springs side by side share the load, so the system is twice as stiff. Two identical springs end to end each carry the full force, so the total extension doubles and the system is half as stiff. These ideas appear in suspensions, trampolines and weighing scales.

Section 7 of 9Worked examples

  1. A spring of constant 80 N/m is stretched by 0.15 m. Find the force.

  2. A 5.0 N load extends a spring by 8.0 cm. What extension is produced by 7.5 N, assuming the limit is not exceeded?

  3. Find the energy stored in a spring of k = 200 N/m stretched by 0.10 m (Supplement).

Section 8 of 9Key terms

TermMeaning
Hooke's lawExtension is proportional to force up to the limit of proportionality.
Spring constantk = F/x, in N/m.
Elastic limitGreatest force after which the object returns to original shape.
Elastic potential energyEnergy stored in a stretched spring.
Plastic deformationPermanent change in shape.

Section 9 of 9Exam technique

1
Using the length of the spring instead of the extension in F = kx.
2
Leaving the extension in cm when k is in N/m.
3
Applying Hooke's law beyond the limit of proportionality.
4
Saying that the gradient of an extension–force graph is k (it is 1/k).
5
Assuming rubber obeys Hooke's law.

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