2.1.2Topic 2 · Genes and Health
Fick’s Law of Diffusion — Edexcel A Level Biology A (SNAB) 9BI0 Revision Notes & Topical Questions
5 min read 9 parts Lesson 4 of 35 1 quiz
2.1.2 Fick's Law of Diffusion — Edexcel A Level Biology A (SNAB) 9BI0 notes: State Fick's law and use it to predict how changes in surface area, concentration difference and membrane thickness affect the rate of diffusion.Fick's law describes the rate of diffusion across an exchange surface.
- rate of diffusion is proportional to (surface area × concentration difference) ÷ thickness of membrane
- pulmonary fibrosis
- Exam-style question 1
- Exam-style question 2
- Exam-style question 3
- Diffusion distance
Part 1 of 7Statement of the law
Fick's law describes the rate of diffusion across an exchange surface. It states that the rate of diffusion is directly proportional to the surface area and to the difference in concentration across the surface, and inversely proportional to the thickness of the exchange surface (the diffusion distance).
Written as a relationship:
rate of diffusion is proportional to (surface area × concentration difference) ÷ thickness of membrane
This is a proportionality rather than an equation with fixed constants at A Level, but it lets you reason quantitatively. Doubling the surface area doubles the rate; halving the diffusion distance doubles the rate; doubling the concentration difference doubles the rate.
Part 2 of 7Applying each variable
Surface area. Biological exchange surfaces are folded or branched to increase area: microvilli on epithelial cells, alveoli in lungs, lamellae on gill filaments, and root hair cells that extend the absorbing surface of the root.
Concentration difference. This is kept as large as possible by constantly removing the diffusing substance on one side and supplying it on the other. In lungs, ventilation keeps alveolar oxygen high and carbon dioxide low, while circulation removes oxygen and brings carbon dioxide. In fish, counter-current flow keeps the gradient favourable along the whole length of the lamella.
Thickness. Short diffusion distances are achieved by flattened, single-layer cells. The alveolar wall and the capillary wall are each one cell thick, and the two are closely pressed together.
Part 3 of 7Comparison table
| Factor | Change | Effect on rate | Biological example |
|---|---|---|---|
| Surface area | Increase | Increases | Alveoli, villi, root hairs |
| Concentration difference | Increase | Increases | Ventilation; blood flow |
| Membrane thickness | Decrease | Increases | Squamous epithelium |
| Surface area | Decrease | Decreases | Emphysema destroys alveolar walls |
| Thickness | Increase | Decreases | Fibrosis thickens alveolar wall; fluid in lungs |
Part 4 of 7Using the law with disease
Lung diseases make Fick's law visible.
Exercise has the opposite effect on the gradient: faster, deeper breathing and a higher cardiac output remove oxygen from the alveoli into the blood more quickly and renew it from the air, so the concentration difference is larger and gas exchange speeds up.
Part 5 of 7Interpreting data
If a question gives rates of diffusion for models of different sizes, look for the pattern in relation to the SA:V ratio.
When asked to evaluate an adaptation, always link it to one of the three variables in the law and say whether it raises or lowers the rate.
Part 6 of 7Worked reasoning with Fick's law
Questions often present a scenario and ask you to predict a change in rate.
Now consider a cell membrane in which the cell grows to twice its diameter.
Part 7 of 7Exam-style questions
State Fick's law of diffusion. [2]2 marks
The rate of diffusion is proportional to the surface area × the concentration difference [1], divided by the thickness (diffusion distance) of the exchange surface [1].
A patient has fibrosis of the lungs. Use Fick's law to explain why the patient has low blood oxygen levels. [3]3 marks
Fibrosis thickens the alveolar wall with scar tissue [1], increasing the diffusion distance for oxygen [1]. By Fick's law the rate of diffusion is inversely proportional to thickness, so less oxygen crosses into the blood per unit time [1].
Cell A has a surface area of 40 µm2 and a membrane 8 nm thick. Cell B has a surface area of 80 µm2 and a membrane 8 nm thick. The concentration difference is the same. Compare the rate of diffusion. [2]2 marks
Surface area of B is twice that of A and thickness is unchanged [1], so the rate of diffusion is twice as fast in B (2:1) [1].
Key terms
| Term | Meaning |
|---|---|
| Fick's law | The rate of diffusion is proportional to surface area and concentration difference, and inversely proportional to the thickness of the exchange surface. |
| Diffusion distance | The thickness of the barrier or distance molecules must cross. |
| Counter-current flow | Flow of two fluids in opposite directions, keeping a concentration gradient along the whole exchange surface. |
| Fibrosis | Thickening and scarring of lung tissue which lengthens the diffusion pathway. |
| Emphysema | Lung disease in which alveolar walls break down, reducing surface area. |
| Microvilli | Tiny folds of the cell surface membrane that increase surface area. |
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