Skip to content
Dabour HubLEARN · PRACTICE · EXPLORESign inStudent

3.1.6Stoichiometry

Practical- Investigating Temperature Changes — Cambridge IGCSE Chemistry 0620 Revision Notes & Topical Questions

5 min read 5 parts Lesson 19 of 28 Unit quiz

🩺
100% Curriculum Specification Match Lesson Doctor Verified
The only platform with 100% curriculum specification match and verified interactive question banks.
Curriculum Equation Key قوانين المول والحسابات الكيميائية - Moles & Stoichiometry FormulasFast Exam Solution
n = m / M_r | N = n × N_A (6.022 × 10²³) | M = n / V | V_gas = n × 22.4 L (STP)
Word Equation & Conditions: عدد المولات = الكتلة بالجرام ÷ الكتلة المولية | عدد الجسيمات = عدد المولات × عدد أفوجادرو
Location & Specifications: كيمياء التحصيلي وثانوي وبكالوريا و Cambridge IGCSE Chemistry.
0%read

Part 1 of 5Method

The same simple calorimeter is used for each process, with only the chemicals changed.

1
Place a fixed volume of the first solution into an insulated container with a lid, and measure its initial temperature.
2
Add the measured amount of the second substance, such as a fixed mass of iron powder or ammonium nitrate, and stir continuously.
3
Record the highest temperature reached for a rise, or the lowest temperature reached for a fall.
4
Calculate the temperature change and classify the process: a rise is exothermic and a fall is endothermic.

Part 2 of 5Example Processes

Three processes are commonly investigated with this method.

Neutralisation
  • Neutralisation Hydrochloric acid added to sodium hydroxide in the calorimeter gives a temperature rise, showing an exothermic reaction.
Displacement
  • Displacement Iron added to copper(II) sulfate solution gives a temperature rise, because a displacement reaction releases energy.
Dissolving
  • Dissolving Ammonium nitrate dissolving in water gives a temperature fall, showing that the process is endothermic.
Control
  • Control Only the chemicals being investigated should change between runs, so that the results can be compared fairly.
ProcessExpected temperature changeClassification
Neutralisation of HCl and NaOHRiseExothermic
Iron and copper(II) sulfateRiseExothermic
Ammonium nitrate dissolvingFallEndothermic

Part 3 of 5Improving the Investigation

Improving the Investigation
Lid
  • Lid A lid reduces heat transfer to the surroundings and gives a more accurate maximum or minimum temperature.
Same volumes
  • Same volumes Using the same volume and concentration of solution allows fair comparison between processes.
Stirring
  • Stirring Continuous stirring makes sure the temperature is uniform throughout the solution.
Initial reading
  • Initial reading Measuring the initial temperature before mixing gives the baseline for the temperature change.

Part 4 of 5Worked Example

Question

  • In an investigation, 25.0 cm³ of water in a calorimeter has an initial temperature of 21.0 °C.
  • Ammonium nitrate is added and the lowest temperature reached is 16.5 °C.
  • Calculate the temperature change and classify the process.

  1. Temperature change ΔT = final − initial = 16.5 − 21.0 = −4.5 °C.
  2. The temperature fell, so heat was taken in from the surroundings.
  3. A fall in temperature shows an endothermic process.

Answer

  • ΔT = −4.5 °C.
  • Dissolving ammonium nitrate is endothermic.

Part 5 of 5Exam Checklist & Tips

3.1.6 – Key Points for the Exam

  • Simple calorimeter An insulated container with a lid, used to measure temperature changes.
  • Exothermic A process that releases heat energy and causes a temperature rise.
  • Endothermic A process that takes in heat energy and causes a temperature fall.
  • Control variable A factor kept the same to make a fair comparison between experiments.

Common Mistakes

  • Recording the temperature of the chemicals after the reaction is complete, rather than the highest or lowest value reached.
  • Classifying a temperature fall as exothermic; a fall means the process is endothermic.
  • Changing the volumes or concentrations between processes, which makes the comparison unfair.
  • Omitting the lid, which allows heat to be lost and gives a smaller temperature change.

Last updated:

\n