5.3.1Tools
Applying General Mathematics in Biology — IB Biology HL Revision Notes & Topical Questions
5 min read 5 parts Lesson 7 of 10
Part 1 of 5Number Skills

Decimals and fractions
- Quantities such as cell size are often decimals or fractions,
- and answers should be given to a sensible number of significant figures.
Ratios
- A ratio such as 3 : 1 compares quantities, and can be used to scale up expected numbers from a cross.
Percentages
- A percentage expresses a part as a fraction of 100, for example percentage cover in a quadrat.
Scientific notation
- Very large or small numbers are written as a × 10ⁿ, so 0.000 002 5 m is 2.5 × 10⁻⁶ m.
Estimation
- Rounding values before a calculation gives a quick check that the final answer is of a sensible size.
Part 2 of 5Averages, Spread and Change
Averages, Spread and Change
Mean, median and mode
- The mean is the sum divided by the number of values, the median is the middle value and the mode is the most frequent value.
Range and quartiles
- The range is the largest minus the smallest value, and quartiles divide ordered data into four equal parts.
Percentage change
- Percentage change = (final − initial) ÷ initial × 100, where a negative answer shows a decrease.
Rate of change
- Rate = change in quantity ÷ time taken, found from a graph by the gradient of a tangent for curves.
Data types
- Discrete data are counts of separate items, whereas continuous data are measurements that can take any value within a range.
| Data | Type | Example |
|---|---|---|
| Number of leaves | Discrete | 6 leaves |
| Leaf length | Continuous | 7.4 cm |
| Blood group | Categorical | AB |
Part 3 of 5Choosing Statistical Tests
Chi-squared test
- It compares observed and expected counts in categories, for example offspring phenotypes.
t-test
- It compares the means of two sets of continuous data to decide if they are significantly different.
Correlation
- The correlation coefficient measures how strongly two variables vary together, but correlation does not prove cause.
Significance
- A probability below 0.05 means the difference is unlikely to be due to chance alone.
Part 4 of 5Worked Example
Question
- The mass of a plant is 5.2 g at the start of an experiment and 6.5 g at the end.
- Calculate the percentage change in mass.
- Change = final − initial = 6.5 − 5.2 = 1.3 g.
- Divide by the initial mass1.3 ÷ 5.2 = 0.25.
- Multiply by 100 to give a percentage: 25%.
Answer The mass increases by 25%.
Part 5 of 5Exam Checklist & Tips
5.3.1 – Key Points for the Exam
- Mean The sum of the values divided by the number of values.
- Percentage change The change as a percentage of the initial value.
- Discrete data Data that can take only separate values, such as counts.
- Continuous data Data that can take any value in a range, such as measurements.
Common Mistakes
- Dividing by the final value instead of the initial value when finding percentage change.
- Applying a t-test to categorical counts.
- Treating a correlation as proof that one variable causes the other.
- Giving answers to too many or too few significant figures.
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