3.6.3Stoichiometry
Magnification — Cambridge IGCSE Chemistry 0620 Revision Notes & Topical Questions
5 min read 5 parts Lesson 14 of 28 Unit quiz
Section 1 of 5The Magnification Equation
Magnification compares the size of the image with the size of the object.
Definition
- Definition Magnification is the image height divided by the object height, so it tells how many times larger the image is than the object.
No units
- No units Magnification is a ratio with no units, so the object and image heights must be measured in the same unit before dividing.
Magnified
- Magnified A magnification greater than 1 means the image is larger than the object.
Diminished
- Diminished A magnification less than 1 means the image is smaller than the object, as happens for a distant object seen through a camera lens.
| Object height | Image height | Magnification | Image size |
|---|---|---|---|
| 4.0 cm | 10.0 cm | 2.5 | Magnified |
| 4.0 cm | 2.0 cm | 0.5 | Diminished |
| 4.0 cm | 4.0 cm | 1.0 | Same size |
Section 2 of 5Rearranging the Equation
1
Write the equation as magnification = image height ÷ object height, and substitute the known values with the same units.
2
To find an image height, multiply the magnification by the object height.
3
To find an object height, divide the image height by the magnification.
4
Check the answer by confirming that a magnification above 1 gives an image taller than the object.
Section 3 of 5Factors Affecting Magnification
Factors Affecting Magnification
Object distance
- Object distance Moving the object closer to a converging lens, within its focal length, increases the magnification of the image formed.
Lens power
- Lens power A stronger lens with a shorter focal length gives a greater magnification for the same object distance.
Measuring
- Measuring Measure both heights from the same scale drawing or photograph, using the same ruler units throughout.
Accuracy
- Accuracy Measure the image height at its widest point, and check that the object height is measured at the same scale.
Section 4 of 5Worked Example
Question
- A magnifying glass forms an image of a 4.0 cm long insect.
- The image is 10.0 cm long.
- Calculate the magnification and state whether the image is magnified.
- Step 1: Write magnification = image height ÷ object height.
- Step 2: Substitute the values with the same units: 10.0 cm ÷ 4.0 cm.
- Step 3: Calculate 10.0 ÷ 4.0 = 2.5, with no units.
Answer The magnification is 2.5, so the image is magnified.
Section 5 of 5Exam Checklist & Tips
3.6.3 – Key Points for the Exam
- Magnification The ratio of image height to object height, with no units.
- Image height The height of the image, measured in the same unit as the object height.
- Object height The height of the object being imaged, measured in the same unit as the image height.
- Magnified image An image with a magnification greater than 1.
- Diminished image An image with a magnification less than 1.
Common Mistakes
- Dividing the object height by the image height, which gives the reciprocal of the magnification.
- Using mixed units, such as centimetres for the image and millimetres for the object, without converting first.
- Giving magnification a unit such as cm, when it is a ratio with no units.
- Stating that a magnification of 0.5 means the image is magnified; it means the image is diminished.
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Cambridge 9700 AS Biology
Core Formula
Magnification Triangle & Unit Conversion
Formula: M = I / A ⇔ A = I / M ⇔ I = M × A
Units: 1 mm = 1,000 μm = 1,000,000 nm.
Rule: Convert Image size (ruler mm) to μm by ×1,000 before dividing by Actual size.