1.4.2Physical Chemistry
Calorimetry — Oxford AQA International A Level Chemistry Revision Notes & Topical Questions
5 min read 6 parts Lesson 23 of 63
Part 1 of 6The Heat Equation

q = mcΔT
- The heat energy transferred, q, equals the mass of water heated, times its specific heat capacity, times the temperature rise.
Mass
- Use the mass of water (or solution) that is heated, in grams, with 1 cm³ of water taken as 1 g.
Specific heat capacity, c
- Water has c = 4.18 J g⁻¹ K⁻¹, the energy needed to raise 1 g by 1 K.
Temperature change
- ΔT is the final minus the initial temperature, which has the same size in °C and in K.
Part 2 of 6From q to ΔH
1
Calculate q in joules using q = mcΔT and convert to kJ by dividing by 1000.
2
Find the moles of the reactant or fuel that caused the temperature change, using n = m/M.
3
Divide q in kJ by the moles, to get the energy per mole.
4
Assign the sign: the temperature of the water rose so the reaction is exothermic and ΔH is negative.
5
State the answer in kJ mol⁻¹ with an appropriate number of significant figures.
Part 3 of 6Combustion Calorimetry
Combustion Calorimetry
Apparatus
- A spirit burner containing the fuel heats a metal can of water, with the burner weighed before and after.
Measurements
- Record the initial and highest water temperatures and the mass of fuel burned.
Precautions
- Use a draught shield, stir the water, and place the flame close to the base of the can.
Error
- Much heat is lost to the surroundings and combustion may be incomplete, so the measured value is usually less exothermic than the data book.
Part 4 of 6Assumptions
Heat capacity
- The solution is assumed to have the same specific heat capacity and density as water.
No heat loss
- All the heat is assumed to pass to the water and none to the apparatus or surroundings.
Complete reaction
- The fuel is assumed to burn completely, forming carbon dioxide and water only.
Effect
- These assumptions mean the measured enthalpy change is usually smaller in magnitude than the true one.
Part 5 of 6Worked Example
Question
- 0.230 g of ethanol (Mr = 46.0) is burned and heats 150 g of water from 20.0 °C to 28.0 °C.
- Calculate the enthalpy change of combustion of ethanol from these results.
- q = mcΔT = 150 × 4.18 × 8.0 = 5016 J = 5.016 kJ.What the symbols mean: E, Q or q = energy transferred (J) · m = mass (kg; g in chemistry calorimetry) · c = specific heat capacity (J kg−1 °C−1; water 4.18 J g−1 °C−1) · ΔT or Δθ = temperature change (°C or K)
- n(ethanol) = 0.230 / 46.0 = 0.00500 mol.
- Energy per mole = 5.016 / 0.00500 = 1003 kJ mol⁻¹.
- The reaction is exothermic, so ΔH is negative.
Answer ΔcH ≈ −1.00 × 10³ kJ mol⁻¹ (less exothermic than the data book value because of heat loss).
Part 6 of 6Exam Checklist & Tips
1.4.2 – Key Points for the Exam
- Specific heat capacity The energy required to raise the temperature of 1 g of a substance by 1 K.
- Calorimetry The measurement of heat energy changes using the temperature change of a substance.
- Spirit burner A small container of liquid fuel with a wick, used in combustion experiments.
- Heat loss Energy transferred to the surroundings instead of the water.
Common Mistakes
- Using the mass of the fuel rather than the mass of the water in q = mcΔT.
- Forgetting to convert joules to kilojoules before giving ΔH in kJ mol⁻¹.
- Giving a positive value for a combustion enthalpy that is exothermic.
- Using the wrong number of moles because Mr of the fuel was miscalculated.
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