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1.1.4Dynamics

Motion Relationships

5 min read 5 parts Lesson 4 of 22 Virtual lab

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Part 1 of 5The Speed Relationship

1.1.4 Motion Relationships

Most motion questions at National 5 use one simple relationship, but it must be used with consistent units.

Equation
  • Average speed is found from d = v t, where d is distance in metres, v is average speed in m/s and t is time in seconds.
Rearranging
  • Rearranging gives v = d ÷ t for speed and t = d ÷ v for the time taken, so any one quantity can be found from the other two.
Displacement form
  • With vectors the same equation applies as s = v t, where s is displacement and v is the average velocity, with direction.
Units
  • Keep SI units
    • metres, seconds and m/s;
      • convert kilometres by multiplying by 1000 and hours by multiplying by 3600.

Part 2 of 5Average and Instantaneous Speed

Average and Instantaneous Speed
Average speed
  • This is the total distance divided by the total time, so it smooths out any speeding up and slowing down on the journey.
Instantaneous speed
  • This is the speed at one particular moment, like the reading on a car speedometer at that second.
Constant speed
  • If the speed never changes, the average speed and the instantaneous speed are the same at every moment.
Journey with stops
  • Time spent stationary must be included in the total time when calculating the average speed of the whole journey.
QuantitySymbolUnitType
distancedmscalar
displacementsmvector
speedvm/sscalar
timetsscalar

Part 3 of 5Solving Problems

1
Write down the quantities you know and the one you need, with their units.
2
Convert every quantity into metres, seconds or m/s before calculating.
3
Choose the correct arrangement of d = v t and substitute the values.
4
Calculate, then give the answer with a sensible number of significant figures and the correct unit.
5
Check the answer is realistic, for example a walking speed near 1.5 m/s or a car near 25 m/s.

Part 4 of 5Worked Example

Question

  • A train travels 180 km in 2.0 hours.
  • Calculate its average speed in m/s.
  • How far does a car travelling at a steady 15 m/s go in 40 s?

  1. Convert180 km = 180 000 m and 2.0 h = 7200 s.
  2. v = d ÷ t = 180 000 ÷ 7200 = 25 m/s.
    What the symbols mean: v = speed (m s−1) · d or s = distance (m) · t = time (s)
  3. For the card = v t = 15 × 40 = 600 m.

Answer Train 25 m/s; car 600 m.

Part 5 of 5Exam Checklist & Tips

1.1.4 – Key Points for the Exam

  • Average speed Total distance divided by total time taken.
  • Instantaneous speed The speed of an object at one particular instant.
  • Average velocity Displacement divided by time, including direction.
  • m/s The SI unit of speed, metres per second.

Common Mistakes

  • Using kilometres and hours in a formula that needs metres and seconds.
  • Leaving out stationary time when working out the average speed of a whole journey.
  • Writing the unit as m or s instead of m/s for speed.
  • Assuming the speedometer reading gives average speed rather than instantaneous speed.
Try it in the virtual labMotion graphs with a ticker timer
Physics 0625 & 9702 SUVAT Mastery Graph Interpretation

Constant Acceleration Equations (SUVAT) & Slopes

v = u + at  |  s = ut + ½at2  |  v2 = u2 + 2as  |  s = ½(u + v)t

  • Displacement-Time Graph: Gradient = Velocity (curve = accelerating).
  • Velocity-Time Graph: Gradient = Acceleration; Area under curve = Distance travelled / Displacement.
  • Free Fall in vacuum: a = g ≈ 9.81 m/s2 downwards (air resistance negligible).
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