Skip to content
Dabour HubLEARN · PRACTICE · EXPLORESign inStudent

1.4.2Dynamics

Newton’s Laws and Unbalanced Forces — SQA National 5 Physics Revision Notes & Topical Questions

5 min read 6 parts Lesson 12 of 22

📚 SQA National 5 Physics Hub / Topical Revision
🩺
100% Curriculum Specification Match Lesson Doctor Verified
The only platform with 100% curriculum specification match and verified interactive question banks.
Curriculum Equation Key Newton Laws of Motion FormulasFast Exam Solution
F = m × a | W = m × g | F₁₂ = -F₂₁
Word Equation & Conditions: Force = Mass × Acceleration
0%read

Part 1 of 6Newton's Second Law

1.4.2 Newton's Laws and Unbalanced Forces

Newton's first law tells us what happens when forces balance; the second law tells us exactly what happens when they do not.

Statement
  • When a resultant force acts on an object it accelerates in the direction of the force.
Equation
  • The relationship is F = m a, where F is the resultant force in newtons, m is the mass in kg and a is the acceleration in m/s².
Proportionality
  • For a fixed mass, doubling the resultant force doubles the acceleration.
Mass
  • For a fixed force, doubling the mass halves the acceleration, so heavier objects are harder to accelerate.

Part 2 of 6Finding the Resultant First

Finding the Resultant First
Step one
  • Identify all the horizontal forces such as the driving force and friction acting on the object.
Step two
  • Subtract the smaller from the larger when they oppose each other, to get the unbalanced force.
Step three
  • Divide this resultant force by the mass to find the acceleration, using a = F ÷ m.
Direction
  • The acceleration is in the same direction as the resultant force, so a force opposite to motion gives a deceleration.
QuantitySymbolUnit
resultant forceFN
massmkg
accelerationam/s²

Part 3 of 6Investigating the Relationship

1
Fix a trolley on a runway and pull it with a known force from a newton balance or weights on a string.
2
Use light gates to measure the acceleration for each force while keeping the mass the same.
3
Plot acceleration against force and observe a straight line through the origin showing direct proportionality.
4
Then keep the force the same and add mass to the trolley, noticing that acceleration decreases as mass increases.

Part 4 of 6Exam Technique

Exam Technique
Draw a diagram
  • Sketch the object and label every force with an arrow before choosing which forces to combine.
Resultant first
  • Always work out the resultant force before using F = m a, since the equation applies to the unbalanced force only.
Units
  • Use kilograms for mass; a mass given in grams must be divided by 1000 before substituting.
Check direction
  • A resultant force opposing the direction of motion gives a negative acceleration, meaning the object is slowing down.

Part 5 of 6Worked Example

Question

  • A car of mass 1200 kg has an engine force of 3000 N while friction and air resistance total 600 N.
  • Find its acceleration.
  • What resultant force gives a 0.50 kg trolley an acceleration of 4.0 m/s²?

  1. Resultant force = 3000 − 600 = 2400 N.
  2. a = F ÷ m = 2400 ÷ 1200 = 2.0 m/s².
  3. TrolleyF = m a = 0.50 × 4.0 = 2.0 N.
    What the symbols mean: F = resultant force (N) · m = mass (kg) · a = acceleration (m s−2)

Answer Car 2.0 m/s²; trolley needs 2.0 N.

Part 6 of 6Exam Checklist & Tips

1.4.2 – Key Points for the Exam

  • Resultant force The overall unbalanced force acting on an object.
  • Newton The force that gives a 1 kg mass an acceleration of 1 m/s².
  • Mass
    • The amount of matter in an object;
      • a measure of its inertia.
  • Direct proportionality When doubling one quantity doubles the other.

Common Mistakes

  • Using one of the forces instead of the resultant in F = m a.
  • Forgetting to subtract friction from the driving force.
  • Using weight in newtons where mass in kilograms is needed.
  • Writing the acceleration unit as N or kg instead of m/s².

Last updated:

\n