Resistance
At constant temperature the resistance of a uniform wire depends on:
Combining the three factors:
R = ρ L / A
L in metre, A in m2, R in Ω, so ρ is in Ω·m.
For a round wire A = π r2 = π d2 / 4, so doubling the diameter divides the resistance by 4 (same length and material). Reading the formula the other way: a wire with half the diameter has four times the resistance.
If a wire is stretched (or drawn) to a new length, its volume stays constant: L₁A₁ = L₂A₂. So when the length is multiplied by k, the area is divided by k and the resistance is multiplied by k2.
| Comparison aspect | Main idea | Keywords |
|---|---|---|
| Worked example 1.3 (resistivity). |
| nichromewirelengthdiameter |
| Step 1 | radius = 0.20 mm = 2.0 × 10−4 m | radius |
| Step 2 | A = π r2 = 3.14 × (2.0 × 10−4)2 = 1.257 × 10−7 m2 | |
| Step 3 | R = ρ L / A = 1.1 × 10−6 × 5 / 1.257 × 10−7 = 43.8 Ω | |
| Worked example 1.4 (ratio problem). |
| Wirelengthdiametermade |
| • |
| Samematerial |
| • |
| Area |
| • | Hence R₂ / R₁ = (L₂ / L₁) × (A₁ / A₂) = 3 × 4 = 12 | Hence |
| • | So R₂ : R₁ = 12 : 1 | |
| Worked example 1.5 (stretching). |
| wireresistancedrawnuniformly |
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