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Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength

Physics

Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength

Overview

Overview

🌳 Concept tree

Lesson 2→The Photoelectric Effect, Compton Scattering and De Broglie Wavelength

├── Why electrons stay inside a metal

  • ├── Thermionic emission and the cathode-ray tube (CRT)

├── The photoelectric effect

├── Einstein's explanation (1905)

├── Stopping potential and the graphs

├── Using the energy unit eV

├── Worked examples (Lesson 2)

├── The Compton effect

├── Properties of the photon

├── Radiation force (light pressure)

├── Macroscopic and microscopic models of light

├── Reflection or transmission of photons

├── Worked examples (Lesson 3)

├── De Broglie's idea (1923)

  • ├── Why do we not notice the wave nature of a ball?

├── Wavelength of an accelerated electron

├── The electron microscope

├── Comparison→optical and electron microscope

├── Worked examples (Lesson 4)

├── Chapter summary (key points)

└── Common mistakes to avoid

Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 1 / 23
Why electrons stay inside a metal

Why electrons stay inside a metal

  • A metal contains fixed positive ions and free electrons that move randomly inside it.
  • In the interior, the pulls of the ions on a free electron cancel out in all directions.
  • At the surface, however, an electron that tries to leave feels a net pull from the ions behind it, directed inward.
  • This restraining force forms the surface potential barrier.
  • An electron can escape only if it receives enough energy to overcome the barrier.
  • The energy can be supplied as heat (thermionic emission) or as light (photoelectric emission).
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 2 / 23
Thermionic emission and the cathode-ray tube (CRT)

Thermionic emission and the cathode-ray tube (CRT)

  • When a metal cathode is heated by a filament, some electrons gain enough thermal energy to leave the surface: this is thermionic emission.
  • This is the working principle of the cathode-ray tube found in old televisions and monitors.
  • Main parts of a CRT:
Comparison aspectMain ideaKeywords
Electron gun (E-gun)
  • a heated cathode emits electrons
  • a grid (negative voltage) controls how many electrons pass
  • so it controls the brightness
  • the anodes (positive) accelerate the electrons and focus them into a thin beam
heatedcathodeemitselectrons
Deflecting plates (X and Y)(or magnetic coils): electric or magnetic fields bend the beam so that it scans the screen point by point in lines (a "raster")magneticcoilselectricfields
Fluorescent screen
  • when the electrons strike it
  • it emits light. The brightness of each spot follows the signal applied to the grid
  • so the image is built up point by point. The screen is connected to the anode
  • so the electrons that arrive complete a circuit and give a current
electronsstrikeemitslight
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 3 / 23
The photoelectric effect

The photoelectric effect

  • If light of suitable frequency falls on the cathode (instead of heating it), electrons are also released and an electric current flows in the circuit of a photocell.
  • The release of electrons from a metal surface when light falls on it is called the photoelectric effect; the emitted electrons are called photoelectrons.
  • What the classical (wave) theory predicts.
  • Light is an electromagnetic wave whose energy is spread evenly over the wave front.
  • According to this picture:
  1. Bright light carries more energy, so the photoelectrons should leave with greater kinetic energy as the intensity increases.
  2. The number of released electrons (the current) should depend on the intensity, whatever the frequency.
  3. Even very weak light of any frequency should eventually free electrons, after it has shone long enough for the electrons to collect the required energy (a time delay).
  • What experiment actually shows.
  1. There is a critical (threshold) frequency νc. If the frequency of the light is below νc, no electrons are emitted, however intense the light is and however long it shines.
  2. If ν > νc, a photocurrent flows, and its value is proportional to the intensity of the light (more photons per second release more electrons per second).
  3. The maximum kinetic energy (and speed) of the photoelectrons depends on the frequency of the light and not on its intensity; it rises as the frequency rises.
  4. The emission is instantaneous (about 10−9 s), even for very weak light, provided ν > νc.
  • The wave theory fails on all four points.
  • That is why it is said that the photoelectric effect cannot be explained by classical physics.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 4 / 23
Einstein’s explanation (1905)

Einstein’s explanation (1905)

  • Einstein adopted Planck’s idea and applied it to light itself: light travels as photons, each photon carrying energy E = hν.
  • The explanation is:
  • One photon gives all of its energy to one electron, in a single instantaneous event (this explains the absence of delay).

    • A certain minimum energy is needed to free an electron from the metal surface.
    • This minimum energy is called the work function, Ew (also written Φ or W).
    • It depends on the type of metal only.
    • Electrons deeper in the metal or more tightly bound need more energy.
  • The threshold frequency is the frequency whose photon energy exactly equals the work function:

    Ew = h νc (5-1) and the threshold wavelength λc = c/νc = hc/Ew.

  • If hν < Ew the electron is not released, whatever the intensity (many weak photons cannot combine their energies because each electron interacts with one photon).
  • If hν = Ew the photon just frees the electron, with zero kinetic energy.
  • If hν > Ew the electron is freed and the extra energy appears as its kinetic energy.
  • Einstein’s photoelectric equation:
  • hν = Ew + KEmax , that is, ½ m v2_max = h ν − h νc (5-2)
  • Here KEmax is the maximum kinetic energy electrons emitted from the surface layer need only Ew; electrons coming from deeper layers lose some energy on the way, so they emerge with less.
  • What the equation tells us:
  • KEmax depends on the frequency ν (and on the metal through νc). It does not depend on the intensity.
  • Doubling the intensity doubles the number of photons per second, so it doubles the number of photoelectrons per second (the current), but each electron still has the same maximum kinetic energy.
  • The threshold frequency depends on the material only; it does not depend on the intensity of the light, the time of exposure, or the potential difference between cathode and anode.
  • Einstein received the 1921 Nobel Prize in Physics for this explanation.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 5 / 23
Stopping potential and the graphs

Stopping potential and the graphs

  • If the anode is made negative relative to the cathode, it repels the photoelectrons.
  • The reverse voltage that just stops the fastest electrons (making the current zero) is the stopping potential Vs:
  • e Vs = KEmax = hν − Ew.
  • Important graphs (for a given metal):
Comparison aspectMain ideaKeywords
Photocurrent versus light intensity(ν > νc): a straight line through the origin; the current is proportional to the intensity. (For ν < νc the current is zero for every intensity.)straightlinethroughorigin
KEmax versus frequencya straight line. It cuts the frequency axis at νc (KE = 0), its slope equals Planck’s constant h, and its extension cuts the KE axis at −Ew. Different metals give parallel lines (same slope h), displaced along the frequency axis because their νc differ.straightlinecutsaxis
Photocurrent versus voltageat positive voltage the current rises to a saturation value (all emitted electrons are collected). The saturation current is larger for greater intensity. At negative voltage the current falls to zero at −Vs; the value of Vs is the same for two beams of the same frequency, whatever their intensities.positiverisessaturationvalue
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 6 / 23
Using the energy unit eV

Using the energy unit eV

  • The electron-volt is the kinetic energy gained by an electron accelerated through a potential difference of 1 volt: 1 eV = 1.6 × 10−19 J.
  • It is the natural unit for photon and atomic energies.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 7 / 23
Worked examples (Lesson 2)

Worked examples (Lesson 2)

  • Example 2.1 — Threshold wavelength. The work function of a metal is 4.5 eV. Find the threshold frequency and wavelength.
  • νc = Ew/h = (4.5 × 1.6 × 10−19)/(6.63 × 10−34) = 1.09 × 1015 Hz.
  • λc = c/νc = 3 × 108/1.09 × 1015 = 2.76 × 10−7 m = 276 nm (ultraviolet). Visible light cannot free electrons from this metal.
  • Example 2.2 — Kinetic energy and speed. Light of wavelength 300 nm falls on a metal of work function 2.1 eV. Find KEmax, the speed of the fastest electron and the stopping potential.
  • Photon energy = 1240/300 = 4.14 eV. KEmax = 4.14 − 2.1 = 2.04 eV = 3.27 × 10−19 J.
  • v = √(2 KE/m) = √(2 × 3.27 × 10−19 / 9.1 × 10−31) = 8.5 × 105 m/s.
  • Vs = KE/e = 2.04 V.
  • Example 2.3 — Effect of intensity. In a photocell, light of frequency above νc gives a photocurrent of 3 μA. The source is replaced by one of the same frequency but twice as intense. What happens to the current and to the kinetic energy of the electrons?
  • Twice as many photons arrive per second, so twice as many electrons are released: current = 6 μA.
  • The maximum kinetic energy is unchanged, because it depends on the frequency only.

✍️ Worked examples

  • Example 2.4 — Same intensity, higher frequency.
  • The frequency of the light in Example 2.3 is raised (still the same number of photons per second).
  • Compare current and KE.
  • The current stays about the same (same photon rate), but KEmax increases because each photon has more energy.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 8 / 23
The Compton effect

The Compton effect

  • When X-rays or gamma rays (high-energy photons) fall on a free electron (or a loosely bound one):
  • the frequency of the scattered radiation is lower than that of the incident radiation (the photon has lost energy), and its direction changes;
  • the electron recoils its speed increases from rest and it moves off in another direction.
  • The wave theory cannot explain this, because a wave would simply make the electron vibrate and re-radiate at the same frequency.
  • The effect is explained easily if light is treated as particles.
  • The photon collides with the electron like one billiard ball hitting another, and two conservation laws apply:
Conservation of energy(photon energy + electron energy) before the collision = (photon energy + electron energy) after.
Conservation of linear momentumthe vector sum of the momenta before the collision equals that after.
  • For these laws to be usable, the photon must have momentum just as the electron has.
  • The Compton effect therefore proves that a photon is a particle that has energy and momentum.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 9 / 23
Properties of the photon

Properties of the photon

  1. From all the experiments above (black-body radiation
  2. photoelectric effect
  3. Compton effect):
  1. A photon is a small "packet" of energy concentrated in a very tiny volume.
  2. E = hν = hc/λ.
  3. It always moves at the speed of light c, whatever its frequency. (It cannot be at rest.)
  4. It has zero rest mass, but a moving photon has an equivalent (relativistic) mass and a linear momentum.
  5. It carries no electric charge; it is not deflected by electric or magnetic fields.
Comparison aspectMain ideaKeywords
Equivalent mass.Einstein’s mass-energy relation is E = mc2: a loss of mass appears as energy. (This is the principle behind the atomic bomb and nuclear energy: a very small loss of mass is converted into a very large energy because c2 = 9 × 1016 m2/s2 is huge.) The laws of conservation of mass and conservation of energy are therefore merged into one law: conservation of mass-energyEinsteinenergyrelationloss
•Setting mc2 = hν gives the equivalent mass of a photonSettinggivesequivalentmass
m = hν/c2 = h/(cλ)(5-3)
Momentum of a photon.Momentum = mass × velocity = (hν/c2) × c, so
p = hν/c = h/λ(5-4)
The wavelength of a photon is therefore λ = h/pPlanck’s constant divided by its linear momentum. A photon’s "size" is of the order of its wavelength.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 10 / 23
Radiation force (light pressure)

Radiation force (light pressure)

  1. When photons strike a surface they transfer momentum to it
  2. so they exert a force. Force = change of momentum per second.
  • A photon that is reflected straight back changes its momentum from +p to −p; the change is 2p = 2mc.

  • If Φ photons per second are reflected, the force is F = 2mc·Φ. Since Pw = Φ·mc2 is the power of the beam (in watts):

    F = 2 Pw / c (reflected beam), (5-5)

    and for a beam that is completely absorbed, F = Pw / c.

  • The force is extremely small.
  • For a 1 W beam reflected by a wall: F = 2 × 1/(3 × 108) = 6.7 × 10−9 N, which has no visible effect on a wall.
  • But the same photons hitting a free electron (tiny mass, tiny size) can knock it away; that is exactly what happens in the Compton effect.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 11 / 23
Macroscopic and microscopic models of light

Macroscopic and microscopic models of light

Comparison aspectMain ideaKeywords
Microscopic model (the photon model)
  • light consists of photons
  • each with energy hν
  • momentum h/λ and the speed c. It is used when light interacts with an electron or an atom
  • i.e. when the obstacle or the region of interaction has dimensions comparable with λ (photoelectric effect
  • Compton effect
  • emission and absorption by atoms)
lightconsistsphotonsenergy
Macroscopic model (the wave model)
  • the beam is described as an electromagnetic wave with electric and magnetic fields perpendicular to each other and to the direction of propagation. The intensity of the wave (the square of the field strength) measures the concentration of photons. It is used when the obstacle is much larger than λ (reflection
  • refraction
  • interference
  • diffraction by ordinary slits). The two models describe the same light and are connected: the wave motion accompanies a very large number of photons
beamdescribedelectromagneticelectric
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 12 / 23
Reflection or transmission of photons

Reflection or transmission of photons

  • Whether a beam is reflected or passes through a medium depends on comparing λ with the distance between the atoms of the medium.
  • If λ is much larger than the spacing, the photons "see" a continuous surface and are reflected as in wave theory.
  • If λ is close to or smaller than the spacing, the photons pass between the atoms; this is how X-rays pass through many materials.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 13 / 23
Worked examples (Lesson 3)

Worked examples (Lesson 3)

  • Example 3.1 — Photon of 500 nm. Find the energy (in eV), equivalent mass and momentum.
  • E = 1240/500 = 2.48 eV = 3.97 × 10−19 J.
  • m = E/c2 = 3.97 × 10−19 / 9 × 1016 = 4.4 × 10−36 kg.
  • p = h/λ = 6.63 × 10−34 / 5 × 10−7 = 1.33 × 10−27 kg·m/s. (Check: p = mc = 4.4 × 10−36 × 3 × 108 = 1.33 × 10−27 ✓.)
  • Example 3.2 — Force of a laser beam. A beam of power 300 W is perfectly reflected by a mirror. Find the force on the mirror, and the force if the beam is completely absorbed.
  • Reflected F = 2P/c = 600/3 × 108 = 2 × 10−6 N. Absorbed: F = P/c = 1 × 10−6 N.
  • Example 3.3 — Comparing two photons. An X-ray photon has λ = 0.1 nm and a radio photon has λ = 3 m. Compare their momenta.
  • p ∝ 1/λ, so p(X)/p(radio) = 3/0.1 × 10−9 = 3 × 1010.
  • The X-ray photon is 30 billion times more "forceful"; this is why X-rays can eject electrons and radio waves cannot.
Example 3.4 — Rate of photons.→A radio station radiates 50 kW at 100 MHz. Energy of one photon = hν = 6.63 × 10−34 × 108 = 6.63 × 10−26 J. Rate = 5 × 104 / 6.63 × 10−26 = 7.5 × 1029 photons/s. The enormous number explains why the quantum nature of radio waves is never noticed: radio photons are individually undetectable and the signal appears perfectly smooth.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 14 / 23
De Broglie’s idea (1923)

De Broglie’s idea (1923)

  • Nature loves symmetry.
  • If waves (light) can behave as particles, why should particles not behave as waves?
  • In 1923 Louis de Broglie proposed that every moving particle is accompanied by a wave whose wavelength is given by an equation of exactly the same form as the photon relation:
  • λ = h / p = h / (m v) (5-6)
  • where p = mv is the linear momentum of the particle.
  • The wave is called the de Broglie wave or the wave accompanying the particle.
  • What does it mean?
  • A beam of light is a huge collection of photons whose collective behaviour (propagation, reflection, refraction, interference, diffraction) is described by a wave, and the intensity of the wave tells us how concentrated the photons are.
  • In the same way a beam of electrons is a huge collection of electrons; each electron carries its own charge, mass, spin and momentum, but their collective behaviour (spreading, interference, diffraction) is described by the accompanying wave.
  • The wave is a probability wave where the wave is strong, the electrons are more likely to be found.
  • Electron beams really do diffract and interfere (for example, when passed through a thin crystal or a double slit they produce bright and dark fringes), which confirms the wave nature of electrons.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 15 / 23
Why do we not notice the wave nature of a ball?

Why do we not notice the wave nature of a ball?

  • λ = h/(mv).
  • For large masses the wavelength is incredibly small.
  • A 140 kg object moving at 40 m/s has λ = 6.63 × 10−34 / (140 × 40) = 1.2 × 10−38 m, far smaller than anything measurable, so ordinary bodies show no wave effects.
  • For an electron (m = 9.1 × 10−31 kg) the same speed gives λ = 6.63 × 10−34 / (9.1 × 10−31 × 40) = 1.8 × 10−5 m, which is large enough to matter.
  • The wave nature becomes important when λ is comparable to the sizes of the obstacles, i.e. for atoms and subatomic particles.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 16 / 23
Wavelength of an accelerated electron

Wavelength of an accelerated electron

  • An electron starting from rest and accelerated through a potential difference V gains kinetic energy equal to the work done by the field:
  • e V = ½ m v2 (5-7), so v = √(2eV/m).
  • Therefore λ = h/√(2 m e V). Numerically (for V in volts): λ ≈ 1.23/√V nm (for example V = 150 V gives 0.10 nm).
  • The larger the accelerating voltage, the faster the electron and the shorter its wavelength. (At very high voltages relativistic corrections are needed, but they are not required here.)
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 17 / 23
The electron microscope

The electron microscope

  • The electron microscope is the practical proof that electrons behave as waves.
  • It is similar in layout to the optical microscope but:
  • it uses a beam of electrons instead of a light beam,
  • the lenses are magnetic (or electric) lenses the field of a coil focuses the electron beam, studied under "electron optics",
  • the electrons are accelerated by a high potential difference (tens of kilovolts) in a vacuum.
  • Resolving power. The smallest detail that a microscope can distinguish is of the order of the wavelength it uses. Visible light has λ ≈ 400–700 nm, so an optical microscope cannot resolve details much smaller than about 200 nm. Electrons accelerated by only a few tens of kilovolts have wavelengths of about 0.005–0.01 nm, which is about a thousand times or more shorter than visible light (or even 104–105 times). Consequently the electron microscope has a much greater resolving power and a much greater useful magnification: it can show viruses, fine structure of cells and surfaces, and even rows of atoms.
  • Why must the electron microscope work in a vacuum?
  • Air molecules would scatter the electrons and the beam would not travel in a straight line.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 18 / 23
Comparison: optical and electron microscope

Comparison: optical and electron microscope

Comparison aspect Optical microscope Electron microscope
Radiation used visible light (photons) beam of electrons
Wavelength 400–700 nm about 0.005–0.01 nm (depends on voltage)
Lenses glass lenses magnetic (or electric) lenses
Resolving power low very high
Image seen by eye on a fluorescent screen or detector
Medium air high vacuum
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 19 / 23
Worked examples (Lesson 4)

Worked examples (Lesson 4)

  • Example 4.1 — A moving electron. Find the de Broglie wavelength of an electron moving at 2 × 106 m/s.
  • λ = h/(mv) = 6.63 × 10−34 / (9.1 × 10−31 × 2 × 106) = 3.64 × 10−10 m = 0.36 nm, which is of the order of atomic spacing in crystals, so such electrons are diffracted by crystals.
  • Example 4.2 — An accelerated electron. An electron is accelerated from rest by 4 × 104 V in an electron microscope. Find its speed and wavelength.
  • ½mv2 = eV → v = √(2 × 1.6 × 10−19 × 4 × 104 / 9.1 × 10−31) = 1.19 × 108 m/s (about 40 % of c, so the non-relativistic result is only approximate).
  • λ = h/(mv) = 6.63 × 10−34 / (9.1 × 10−31 × 1.19 × 108) = 6.1 × 10−12 m = 0.0061 nm.
  • Compare with green light, 550 nm the ratio is about 9 × 104.
  • Example 4.3 — Photon against electron with the same wavelength. A photon and an electron both have wavelength 0.2 nm. Compare their momenta, then energies.
  • Same λ → same momentum p = h/λ = 3.3 × 10−24 kg·m/s.
  • Photon energy = pc = 3.3 × 10−24 × 3 × 108 = 9.9 × 10−16 J = 6.2 keV.
  • Electron energy = p2/2m = (3.3 × 10−24)2 / (2 × 9.1 × 10−31) = 6.0 × 10−18 J = 37 eV.
  • The photon has about 170 times more energy.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 20 / 23
Chapter summary (key points)

Chapter summary (key points)

  1. Classical physics cannot explain phenomena in which light or electromagnetic radiation interacts with electrons and atoms.
  2. Radiation consists of photons of energy E = hν = hc/λ, where h = 6.63 × 10−34 J·s.
  3. Planck curve; Wien’s law λmax ∝ 1/T; Planck solved the problem by quantizing the energy of oscillators (E = nhν).
  4. no emission below the threshold frequency; current ∝ intensity (above threshold); KEmax depends on the frequency, not the intensity; emission is instantaneous. Equation: hν = Ew + ½mv2_max, Ew = hνc.
  5. A photon has equivalent mass m = hν/c2, momentum p = h/λ, and travels at c. It exerts a very small force on a wall (F = 2Pw/c for reflection) but can throw away a free electron.
  6. The Compton effect (scattered photon of lower frequency, recoiling electron) proves the particle nature of photons through conservation of energy and momentum.
  7. A wave describes the collective behaviour of photons; its intensity measures photon concentration.
  8. any particle has a wave with λ = h/mv. The electron microscope is the proof; it has very high resolving power because accelerated electrons have extremely short wavelengths.
  9. eV = ½mv2.
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 21 / 23
Common mistakes to avoid

Common mistakes to avoid

  • Intensity changes the number of photoelectrons, not their maximum kinetic energy.
  • Threshold frequency depends only on the metal, not on the intensity or the applied voltage.
  • Do not confuse the photon’s equivalent mass (hν/c2) with a rest mass: its rest mass is zero.
  • Use consistent units convert nm to m and eV to J (or use hc = 1240 eV·nm).
  • In the radiation-force formula remember the factor 2 for reflection, factor 1 for absorption.
  • .egp-ex{margin:18px 0;border:1px solid rgba(79,63,224,.2);border-radius:16px;overflow:hidden;background:#fff}.egp-ex-h{padding:10px 16px;font-weight:800;background:linear-gradient(90deg,#4f3fe0,#22c1c3);color:#fff}.egp-ex-tabs{display:flex;flex-wrap:wrap;gap:6px;padding:10px 12px;background:#f7f6ff}.egp-ex-b{border:1px solid rgba(79,63,224,.3);background:#fff;border-radius:20px;padding:5px 14px;font-weight:700;cursor:pointer}.egp-ex-b.on{background:#4f3fe0;color:#fff}.egp-ex-p{padding:12px 16px}
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 22 / 23
Part 23

Part 23

  • 📖

🔍 In-Depth Explanations, Deductions & Multi-Book Insights:

Physics (Thanaweya Amma 2026/2027)

  • Lesson 2 – The Photoelectric Effect, Compton Scattering and De Broglie Wavelength
  • Albert Einstein explained the Photoelectric Effect using light quanta, proving photon particle behavior.
  • Arthur Compton proved photon-electron collisions obey conservation of energy and momentum.
  • Louis de Broglie hypothesized the wave-particle duality for all matter (λ = h / pL), enabling the Electron Microscope.

🌳 Conceptual Hierarchy Tree

Particle Properties and Wave-Particle Duality

├── 1. Einstein's Photoelectric Effect
│ ├── Work Function (Ew = h · νc)Minimum energy required to liberate an electron from metal surface
│ ├── Threshold Frequency (νc)Minimum frequency required for emission
│ └── Einstein EquationKE_max = E – Ew = h(ν – νc) = 1/2 m v2

├── 2. Compton Scattering Effect

Comparison aspectMain ideaKeywords
•│ ├── High-energy X-ray/gamma photon collides with stationary free electronHighenergygammaphoton
│ ├── Scattered photon
  • Lower frequency
  • longer wavelength
  • decreased energy
Lowerfrequencylongerwavelength
│ ├── Recoiling electronIncreased velocity and kinetic energyIncreasedvelocitykineticenergy
│ └── Proof of ConservationTotal energy and total linear momentum are conservedTotalenergylinearmomentum
•└── 3. De Broglie Matter Waves & Electron MicroscopeBroglieMatterWavesElectron
├── De Broglie relationshipλ = h / (m · v)
└── Electron Microscope
  • Fast electrons accelerated by high potential difference V have extremely short λ
  • resolving tiny viruses
Fastelectronsacceleratedhigh

📋 Master Teacher's Blackboard Secrets

Comparison aspectMain ideaKeywords
RULE 1
  • In the photoelectric effect: If light frequency ν < νc
  • NO electrons are emitted regardless of light intensity or illumination duration!
photoelectriceffectlightfrequency
RULE 2
  • If ν > νc: Increasing light intensity increases the NUMBER (rate) of emitted electrons
  • but DOES NOT affect their maximum kinetic energy
Increasinglightintensityincreases
RULE 3Increasing light frequency increases the KINETIC ENERGY and SPEED of emitted electronsIncreasinglightfrequencyincreases
RULE 4
  • In the Electron Microscope: eV = 1/2 m v2 → v = √(2eV/m). Therefore
  • increasing accelerating potential V decreases electron wavelength λ
  • increasing resolving power
ElectronMicroscopeThereforeincreasing
📊 MatrixComparative Synthesis: Photon Behavior in Photoelectric vs. Compton EffectsComparativeSynthesisPhotonBehavior
Feature Photoelectric Effect Compton Scattering Effect
Incident Photon Type Visible light or low UV photons High-energy X-ray or Gamma ray photons
Target Particle Bound conduction electrons in metal surface Free or loosely bound outer-shell electron
Fate of Incident Photon Completely absorbed (Disappears) Scattered with lower frequency and longer wavelength
Key Conservation Proven Conservation of Energy Conservation of both Energy and Momentum (Particle proof)
Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength · 23 / 23