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Chapter 1 - Electric Current, Ohms Law and Kirchhoffs Laws

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Chapter 3 - Electromagnetic Induction and AC Dynamo and Transformer

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Chapter 5 - Dual Nature of Wave and Particle

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Chapter 7 - Lasers and Principles

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Quiz

Lesson 1: Faradays Law of Induction, Lenzs Law and EMF in a Moving Wire — Picture questions (exam style)

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  • Questions count: 17
  • Passing grade: 60%
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1.
A rod 0.3 m long moves right at 5 m/s on rails joined by 1 Ω in a 0.2 T field into the page (figure). Which option is correct?
A rod 0.3 m long moves right at 5 m/s on rails joined by 1 Ω in a 0.2 T field into the page (figure). Which option is correct?
downwards in the rod, I = 0.300 A, force for constant speed = 0.300 N
downwards in the rod, I = 1.00 A, force for constant speed = 0.0900 N
upwards in the rod, I = 0.300 A, force for constant speed = 0.0180 N
downwards in the rod, I = 0.300 A, force for constant speed = 0.0900 N
2.
The graph shows the flux through a coil of 100 turns. Which option is correct?
The graph shows the flux through a coil of 100 turns. Which option is correct?
emf in stage 1 = 0.5 V, current in the last stage is the same as the first, e₃ : e₁ = 1 : 2
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 4 : 1
emf in stage 1 = 50 V, current in the last stage is opposite to the first, e₃ : e₁ = 2 : 1
emf in stage 1 = 0.5 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 4
3.
Which statement is NOT correct by Faraday’s and Lenz’s laws?
Which statement is NOT correct by Faraday’s and Lenz’s laws?
the induced current aids the change in flux
when a N pole approaches a coil, the near face becomes a N pole
a magnet falls more slowly through a copper tube than freely
no current is induced when a wire moves parallel to the field lines
4.
A coil (200 turns, 10.0 cm2) with its plane perpendicular to a 0.8 T field is turned a quarter-turn in 0.2 s so its plane is parallel to the field. Average e.m.f.?
A coil (200 turns, 10.0 cm²) with its plane perpendicular to a 0.8 T field is turned a quarter-turn in 0.2 s so its plane is parallel to the field. Average e.m.f.?
1.60 V
4.00×10−3 V
0.0320 V
0.800 V
5.
A coil (100 turns, 40.0 cm2, total resistance 8 Ω) is perpendicular to a field varying as tabulated. Find the charge that flows between t = 0.1 s and t = 0.4 s.
A coil (100 turns, 40.0 cm², total resistance 8 Ω) is perpendicular to a field varying as tabulated. Find the charge that flows between t = 0.1 s and t = 0.4 s.
1.28 C
0.0500 C
0.0200 C
2.00 C
6.
The graph shows the flux through a coil of 100 turns. Which option is correct?
The graph shows the flux through a coil of 100 turns. Which option is correct?
emf in stage 1 = 50 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 1
emf in stage 1 = 50 V, current in the last stage is the same as the first, e₃ : e₁ = 1 : 2
emf in stage 1 = 50 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 2
emf in stage 1 = 0.5 V, current in the last stage is the same as the first, e₃ : e₁ = 2 : 1
7.
The graph shows the flux through a coil of 200 turns. Which option is correct?
The graph shows the flux through a coil of 200 turns. Which option is correct?
emf in stage 1 = 600 V, current in the last stage is opposite to the first, e₃ : e₁ = 2 : 1
emf in stage 1 = 1200 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 1
emf in stage 1 = 1200 V, no current in the last stage, e₃ : e₁ = 1 : 2
emf in stage 1 = 600 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 1
8.
The graph shows the flux through a coil of 200 turns. Which option is correct?
The graph shows the flux through a coil of 200 turns. Which option is correct?
emf in stage 1 = 200 V, current in the last stage is opposite to the first, e₃ : e₁ = 8 : 1
emf in stage 1 = 200 V, current in the last stage is the same as the first, e₃ : e₁ = 1 : 16
emf in stage 1 = 200 V, current in the last stage is opposite to the first, e₃ : e₁ = 4 : 1
emf in stage 1 = 1 V, no current in the last stage, e₃ : e₁ = 1 : 16
9.
The graph shows the flux through a coil of 200 turns. Which option is correct?
The graph shows the flux through a coil of 200 turns. Which option is correct?
emf in stage 1 = 1 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 1
emf in stage 1 = 200 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 1
emf in stage 1 = 200 V, current in the last stage is the same as the first, e₃ : e₁ = 2 : 1
emf in stage 1 = 400 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 1
10.
The graph shows the flux through a coil of 100 turns. Which option is correct?
The graph shows the flux through a coil of 100 turns. Which option is correct?
emf in stage 1 = 1 V, current in the last stage is the same as the first, e₃ : e₁ = 2 : 1
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 2
emf in stage 1 = 100 V, no current in the last stage, e₃ : e₁ = 1 : 4
emf in stage 1 = 100 V, no current in the last stage, e₃ : e₁ = 2 : 2
11.
The graph shows the flux through a coil of 100 turns. Which option is correct?
The graph shows the flux through a coil of 100 turns. Which option is correct?
emf in stage 1 = 200 V, no current in the last stage, e₃ : e₁ = 1 : 4
emf in stage 1 = 1 V, current in the last stage is opposite to the first, e₃ : e₁ = 2 : 2
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 4 : 1
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 2 : 1
12.
The graph shows the flux through a coil of 100 turns. Which option is correct?
The graph shows the flux through a coil of 100 turns. Which option is correct?
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 1
emf in stage 1 = 1 V, current in the last stage is the same as the first, e₃ : e₁ = 1 : 1
emf in stage 1 = 200 V, current in the last stage is the same as the first, e₃ : e₁ = 1 : 1
emf in stage 1 = 200 V, no current in the last stage, e₃ : e₁ = 1 : 2
13.
Which statement is NOT correct by Faraday’s and Lenz’s laws?
Which statement is NOT correct by Faraday’s and Lenz’s laws?
the induced current opposes the change in flux causing it
a magnet falls more slowly through a copper tube than freely
on breaking a solenoid circuit the induced current flows in the original direction
the induced current aids the change in flux
14.
The graph shows the flux through a coil of 100 turns. Which option is correct?
The graph shows the flux through a coil of 100 turns. Which option is correct?
emf in stage 1 = 400 V, current in the last stage is the same as the first, e₃ : e₁ = 2 : 2
emf in stage 1 = 200 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 2
emf in stage 1 = 200 V, current in the last stage is the same as the first, e₃ : e₁ = 2 : 2
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 2
15.
The graph shows the flux through a coil of 50 turns. Which option is correct?
The graph shows the flux through a coil of 50 turns. Which option is correct?
emf in stage 1 = 200 V, current in the last stage is the same as the first, e₃ : e₁ = 1 : 4
emf in stage 1 = 100 V, no current in the last stage, e₃ : e₁ = 2 : 1
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 2 : 1
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 2 : 2
16.
The graph shows the flux through a coil of 200 turns. Which option is correct?
The graph shows the flux through a coil of 200 turns. Which option is correct?
emf in stage 1 = 300 V, current in the last stage is opposite to the first, e₃ : e₁ = 2 : 1
emf in stage 1 = 1.5 V, current in the last stage is opposite to the first, e₃ : e₁ = 2 : 2
emf in stage 1 = 300 V, current in the last stage is opposite to the first, e₃ : e₁ = 1 : 4
emf in stage 1 = 600 V, current in the last stage is the same as the first, e₃ : e₁ = 1 : 4
17.
The graph shows the flux through a coil of 200 turns. Which option is correct?
The graph shows the flux through a coil of 200 turns. Which option is correct?
emf in stage 1 = 100 V, no current in the last stage, e₃ : e₁ = 1 : 16
emf in stage 1 = 100 V, current in the last stage is the same as the first, e₃ : e₁ = 16 : 1
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 4 : 1
emf in stage 1 = 100 V, current in the last stage is opposite to the first, e₃ : e₁ = 16 : 1
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