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Lesson 2: The Photoelectric Effect, Compton Scattering and De Broglie Wavelength — Picture questions (exam style)

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1.
Light of photon energy 3 eV falls on a metal of work function 2.0 eV (circuit shown). What is the effect of doubling the light intensity?
Light of photon energy 3 eV falls on a metal of work function 2.0 eV (circuit shown). What is the effect of doubling the light intensity?
number of photoelectrons decreases, stopping potential decreases
number of photoelectrons unchanged, stopping potential increases
number of photoelectrons increases, stopping potential unchanged
number of photoelectrons decreases, stopping potential unchanged
2.
Particle 1 (an proton) is accelerated from rest through 200 V; particle 2 (a alpha particle) through 200 V. What is λ₁ : λ₂ (de Broglie)? (mp ≈ 1836 me)
Particle 1 (an proton) is accelerated from rest through 200 V; particle 2 (a alpha particle) through 200 V. What is λ₁ : λ₂ (de Broglie)? (mp ≈ 1836 me)
λ₁ : λ₂ = 0.354
λ₁ : λ₂ = 2.83
λ₁ : λ₂ = 8
λ₁ : λ₂ = 1.68
3.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
6.76 eV
5.60 eV
2.80 eV
4.14×10−15 eV
4.
Light of wavelength 450 nm falls on the four metals in the table. From how many are photoelectrons emitted?
Light of wavelength 450 nm falls on the four metals in the table. From how many are photoelectrons emitted?
3
1
2
4
5.
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 5.00×1013 Hz, what is the new stopping potential?
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 5.00×10¹³ Hz, what is the new stopping potential?
3.10 V
2.81 V
5.20 V
2.60 V
6.
An X-ray photon is scattered through 120° by a free electron (Compton effect). Find the increase in its wavelength.
An X-ray photon is scattered through 120° by a free electron (Compton effect). Find the increase in its wavelength.
-1.21×10−12 m
2.43×10−12 m
3.64×10−12 m
7.28×10−12 m
7.
Particle 1 (an proton) is accelerated from rest through 400 V; particle 2 (a alpha particle) through 400 V. What is λ₁ : λ₂ (de Broglie)? (mp ≈ 1836 me)
Particle 1 (an proton) is accelerated from rest through 400 V; particle 2 (a alpha particle) through 400 V. What is λ₁ : λ₂ (de Broglie)? (mp ≈ 1836 me)
λ₁ : λ₂ = 8
λ₁ : λ₂ = 1.68
λ₁ : λ₂ = 0.354
λ₁ : λ₂ = 2.83
8.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
11.3 eV
9.40 eV
4.70 eV
4.14×10−15 eV
9.
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.00×1014 Hz, what is the new stopping potential?
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.00×10¹⁴ Hz, what is the new stopping potential?
1.51 V
2.10 V
1.10 V
2.20 V
10.
An X-ray photon is scattered through 60° by a free electron (Compton effect). Find the increase in its wavelength.
An X-ray photon is scattered through 60° by a free electron (Compton effect). Find the increase in its wavelength.
1.21×10−12 m
2.43×10−12 m
2.11×10−12 m
2.56×10−12 m
11.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
5.79 eV
4.14×10−15 eV
2.40 eV
4.80 eV
12.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
0.700 J
1.12×10−19 J
2.24×10−19 J
4.38×1018 J
13.
A photon of wavelength 2.00×10−11 m is scattered through 45° by a free electron. What is the scattered wavelength?
A photon of wavelength 2.00×10⁻¹¹ m is scattered through 45° by a free electron. What is the scattered wavelength?
1.93×10−11 m
2.07×10−11 m
2.00×10−11 m
2.24×10−11 m
14.
What stopping potential is needed for incident light of frequency 1.13×1015 Hz?
What stopping potential is needed for incident light of frequency 1.13×10¹⁵ Hz?
1.08 V
4.68 V
1.73×10−19 V
3.60 V
15.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
5.00×1018 J
1.28×10−19 J
0.800 J
2.56×10−19 J
16.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
1.00 J
1.60×10−19 J
6.25×1018 J
3.20×10−19 J
17.
A photon of wavelength 2.00×10−11 m is scattered through 90° by a free electron. What is the scattered wavelength?
A photon of wavelength 2.00×10⁻¹¹ m is scattered through 90° by a free electron. What is the scattered wavelength?
1.76×10−11 m
3.90×10−11 m
2.24×10−11 m
2.00×10−11 m
18.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
1.20 J
1.92×10−19 J
3.84×10−19 J
7.50×1018 J
19.
What stopping potential is needed for incident light of frequency 1.87×1015 Hz?
What stopping potential is needed for incident light of frequency 1.87×10¹⁵ Hz?
5.52×10−19 V
3.45 V
7.75 V
4.30 V
20.
A photon of wavelength 2.00×10−11 m is scattered through 30° by a free electron. What is the scattered wavelength?
A photon of wavelength 2.00×10⁻¹¹ m is scattered through 30° by a free electron. What is the scattered wavelength?
2.24×10−11 m
1.97×10−11 m
2.00×10−11 m
2.03×10−11 m
21.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
1.12×1019 J
5.76×10−19 J
1.80 J
2.88×10−19 J
22.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
4.32×10−19 J
2.70 J
1.69×1019 J
8.64×10−19 J
23.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
4.14×10−15 eV
9.89 eV
4.10 eV
8.20 eV
24.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
1.88×1019 J
3.00 J
9.60×10−19 J
4.80×10−19 J
25.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
2.10 J
1.31×1019 J
3.36×10−19 J
6.72×10−19 J
26.
What stopping potential is needed for incident light of frequency 7.20×1014 Hz?
What stopping potential is needed for incident light of frequency 7.20×10¹⁴ Hz?
0.984 V
2.00 V
2.98 V
1.57×10−19 V
27.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
5.20 eV
2.60 eV
6.27 eV
4.14×10−15 eV
28.
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.00×1014 Hz, what is the new stopping potential?
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.00×10¹⁴ Hz, what is the new stopping potential?
1.40 V
0.814 V
0.800 V
0.400 V
29.
Using the graph, what is the threshold frequency?
Using the graph, what is the threshold frequency?
5.13×1033 Hz
8.21×1014 Hz
1.31×1015 Hz
4.10×1014 Hz
30.
Using the graph, what is the threshold frequency?
Using the graph, what is the threshold frequency?
5.28×1033 Hz
8.45×1014 Hz
4.22×1014 Hz
1.35×1015 Hz
31.
What stopping potential is needed for incident light of frequency 1.54×1015 Hz?
What stopping potential is needed for incident light of frequency 1.54×10¹⁵ Hz?
6.38 V
3.18 V
5.09×10−19 V
3.20 V
32.
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.00×1014 Hz, what is the new stopping potential?
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.00×10¹⁴ Hz, what is the new stopping potential?
3.30 V
4.60 V
2.30 V
2.71 V
33.
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.50×1014 Hz, what is the new stopping potential?
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.50×10¹⁴ Hz, what is the new stopping potential?
1.50 V
3.00 V
2.12 V
3.69 V
34.
What stopping potential is needed for incident light of frequency 1.40×1015 Hz?
What stopping potential is needed for incident light of frequency 1.40×10¹⁵ Hz?
4.64×10−19 V
2.90 V
5.80 V
5.05 V
35.
A photon of wavelength 1.00×10−12 m is scattered through 180° by a free electron. What is the scattered wavelength?
A photon of wavelength 1.00×10⁻¹² m is scattered through 180° by a free electron. What is the scattered wavelength?
-3.85×10−12 m
1.00×10−12 m
3.43×10−12 m
5.85×10−12 m
36.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
5.00 eV
4.14×10−15 eV
2.50 eV
6.03 eV
37.
What stopping potential is needed for incident light of frequency 9.60×1014 Hz?
What stopping potential is needed for incident light of frequency 9.60×10¹⁴ Hz?
2.84×10−19 V
1.78 V
3.98 V
2.20 V
38.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
4.60 eV
4.14×10−15 eV
2.30 eV
5.55 eV
39.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
4.14×10−15 eV
3.30 eV
6.60 eV
7.96 eV
40.
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
The graph shows max kinetic energy of photoelectrons against frequency for a metal. What is the work function?
5.07 eV
4.14×10−15 eV
4.20 eV
2.10 eV
41.
Using the graph, what is the maximum kinetic energy of the photoelectrons?
Using the graph, what is the maximum kinetic energy of the photoelectrons?
2.56×10−19 J
1.60 J
5.12×10−19 J
1.00×1019 J
42.
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 5.00×1013 Hz, what is the new stopping potential?
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 5.00×10¹³ Hz, what is the new stopping potential?
1.10 V
0.600 V
1.20 V
0.807 V
43.
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.50×1014 Hz, what is the new stopping potential?
The graph shows photocurrent against voltage for light of frequency f₁. If the frequency is increased by 1.50×10¹⁴ Hz, what is the new stopping potential?
1.30 V
2.60 V
2.80 V
1.92 V
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