4.1.2Linear Momentum
Rate of Change of Momentum — AP PHYSICS 1 Revision Notes & Topical Questions
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Lesson summary
4.1.2 Rate of Change of Momentum — AP PHYSICS 1 notes: Express Newton's second law as net force equals rate of change of momentum and use it to find average forces.Fnet = Δp/Δt — the net external force equals the rate of change of momentum of an object or system.Fnet in N, Δp in …
- Original form
- Constant mass
- Variable mass
- Momentum–time graph
- Definition
- Stopping only
Section 1 of 8Newton's second law in momentum form
Fnet
Δp/Δt
- the net external force equals the rate of change of momentum of an object or system.
- Fnet in N, Δp in kg·m/s, Δt in s.
Original form
- Newton's second law was originally postulated in terms of momentum.
Constant mass
- Δp = mΔv, so Fnet = m(Δv/Δt) = ma.
Variable mass
- Variable mass the momentum form still applies when the mass is not constant.
Section 2 of 8Interpreting the equation
Same Δp
- Same Δp a large force for a short time or a small force for a long time gives the same change in momentum.
Direction
- Direction the change in momentum points along the net force.
Momentum–time graph
- Momentum–time graph a straight line with gradient Fnet for constant force; a curve means the force varies,
- and the tangent gradient gives the force at that moment.
Section 3 of 8Calculating Δp
Definition
- Δp = pf − pi = mvf − mvi, with signs.
Rebound
- Rebound the velocity reverses sign, so |Δp| is nearly double the incoming momentum;
- a ball rebounding at the same speed has Δp = −2mv.
Stopping only
- Δp has magnitude mv, so a rebound needs a larger force for the same contact time.
Two dimensions
- Two dimensions find Δp separately for x and y components.
Sign convention
- Sign convention take the initial direction as positive unless told otherwise.
Section 4 of 8Variable mass: rain, jets and rockets
Variable mass: rain, jets and rockets
Rain or sand arriving with no horizontal velocity
- Rain or sand arriving with no horizontal velocity needs a horizontal force F = v(Δm/Δt) even at steady speed.
Water jet on a wall
- Water jet on a wall force equals the mass per second times the speed lost.
Rocket thrust
- Rocket thrust equals the rate at which momentum is given to the exhaust gases.
System
- System define the mass stopped or accelerated in Δt;
- the forces on the water and on the wall are equal and opposite.
Section 5 of 8Why it matters
Why it matters
Safety devices
- Safety devices air bags, crumple zones, padded dashboards and bent knees spread the same Δp over a longer Δt, reducing the average force.
Short contact
- Short contact a hammer blow or karate chop uses a short time to create a large force.
Measurement
- Measurement average force can be found from video analysis using Δp from the speeds and Δt from the frame times.
Systems
- Systems internal forces cancel in pairs by Newton's third law, so the total momentum changes only through the net external force.
Section 6 of 8More from the specification
More from the specification
Momentum-time graph slope
- Momentum-time graph slope the instantaneous tangent slope on a momentum-versus-time graph equates directly to the resultant external net force.
Inertia
- Resistance of an object to changes in its motion.
Force-time graph
- A graph whose area is the impulse.
Linear momentum
- The product of mass and velocity.
Final velocity
- Velocity at the end, v.
Kinetic energy
- K = ½mv2, energy of motion.
Impulse
- J = FΔt = Δp.What the symbols mean: F = force (N) · Δt = time the force acts (s) · Δp = change in momentum (kg m s−1); FΔt is the impulse (N s)
Collision
- Short interaction with large internal forces.
Vector
- Quantity with magnitude and direction.
Section 7 of 8Key terms
| Term | Meaning |
|---|---|
| Net force | Vector sum of external forces, equal to Δp/Δt. |
| Δp | Change in momentum, final minus initial. |
| Average force | Total change in momentum divided by the time interval. |
| Contact time | Duration over which two objects exert force on each other. |
| Crumple zone | Car structure that lengthens collision time and lowers force. |
Section 8 of 8Exam technique
1
Forgetting that a rebound reverses the velocity, so Δp is larger than mv.
2
Using the final momentum instead of the change in momentum in F = Δp/Δt.
3
Ignoring signs — define a positive direction first.
4
Thinking larger momentum means larger force — it is the rate of change that matters.
5
Applying the equation to a single object when the force given is an internal force of the system.
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