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4.2.2Linear Momentum

Momentum of a System — AP PHYSICS 1 Revision Notes & Topical Questions

5 min read 8 parts Lesson 9 of 13 1 quiz

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Lesson summary

4.2.2 Momentum of a System — AP PHYSICS 1 notes: Calculate the total momentum of a system of objects and relate it to the motion of its centre of mass.System — any collection of objects treated together (two carts, a cannon and shell, a planet–moon pair).Total momentum — psys = Σ…

  • One dimension
  • Two dimensions
  • Momentum link
  • No external force
  • Separation example
  • Fnet,ext = Δpsys/Δt = Macm

Section 1 of 8Total momentum of a system

Total momentum of a system
System
  • System any collection of objects treated together.
    • (two carts, a cannon and shell, a planet–moon pair)
Total momentum
  • Total momentum psys = Σmivi = m1v1 + m2v2 + …, a vector sum.
One dimension
  • One dimension opposite directions have opposite signs.
Two dimensions
  • Two dimensions add x and y components separately.

Section 2 of 8Centre of mass

Centre of mass
Centre of mass the point that moves as if all the mass were there and all external forces acted on it.
Position
  • Position xcm = Σmixi / Σmi.
Velocity
  • Velocity vcm = Σmivi / Σmi.
Momentum link
  • Momentum link psys = Mvcm, with M the total mass.
No external force
  • No external force the centre of mass moves at constant velocity whatever the internal interactions.
Separation example
  • Separation example a shuttle and rocket separating in free space keep the same vcm.

Section 3 of 8Net external force

Net external force
Fnet,ext
Δpsys/Δt = Macm
  • the net external force sets the rate of change of total momentum.
Skaters pushing apart on ice
  • Skaters pushing apart on ice zero external force,
    • so total momentum stays zero, the skaters gain equal and opposite momenta and the centre of mass stays still.
System including Earth
  • System including Earth gravity is internal; a falling ball and Earth gain equal and opposite momentum.

Section 4 of 8Momentum and energy in systems

Momentum and energy in systems
Energy can change at constant momentum
  • Energy can change at constant momentum internal forces do work, so skaters' kinetic energy rises from zero as chemical energy is converted.
Momentum can change at constant energy
  • Momentum can change at constant energy a ball in uniform circular motion has constant kinetic energy but changing momentum.
    • (external impulse)

Section 5 of 8Bookkeeping

Bookkeeping
Table
  • Table columns for mass, initial velocity and final velocity of each object, then compute each momentum and sum.
Bar chart
  • Bar chart total bar before equals total after for an isolated system;
    • otherwise an external impulse or an error is present.
Object at rest
  • Object at rest the total momentum is that of the moving object, and vcm = m1v1/(m1 + m2).
Perfectly inelastic collision
  • Perfectly inelastic collision both objects move at vcm, since a collision cannot change vcm.
More objects
  • More objects keep adding terms; track which mass is in the system at each instant.

Section 6 of 8More from the specification

More from the specification
Centre of mass velocity speed
  • Centre of mass velocity speed isolating colliding bodies preserves total momentum, ensuring the system centre of mass maintains constant speed.
Vertical component
  • F sin θ for an angle θ to the horizontal.
Explosion
  • Interaction pushing parts of a system apart.

Section 7 of 8Key terms

TermMeaning
SystemChosen group of objects analysed together.
Total momentumVector sum of all momenta in the system.
Centre of massPoint that moves as if all mass and external forces were there.
Net external forceVector sum of forces from outside the system.

Section 8 of 8Exam technique

1
Adding speeds instead of signed velocities.
2
Assuming total momentum is zero whenever the centre of mass is at rest without checking external force.
3
Using the mass of only one object in Mvcm.
4
Including internal forces when finding the net external force.
5
Leaving out an object that moves in the system.

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