5.3.7Energy Transfers In and Between Organisms (A Level only)
Primary and Secondary Productivity — AQA A Level Biology 7402 Revision Notes & Topical Questions
5 min read 8 parts Lesson 19 of 30 1 quiz
5.3.7 Primary and Secondary Productivity — AQA A Level Biology 7402 notes: Distinguish primary and secondary productivity and use equations to calculate net production at consumer levels.Productivity is the rate at which energy is stored in biomass.Primary productivity applies to…
- N = I − (F + R)
- Food quality and digestibility
- Body temperature regulation
- Age and growth stage
- Environmental conditions
- Exam-style question 1
Section 1 of 8Production and productivity
Productivity is the rate at which energy is stored in biomass.
Section 2 of 8Net production of consumers
The same logic as NPP applies to consumers. A consumer takes in chemical energy as food, but only part is turned into body mass.
N = I − (F + R)
where N is net production (energy stored in new consumer biomass), I is the chemical energy in ingested food, F is the energy lost in faeces and urine, and R is the energy lost in respiration.
The net production of a consumer is the energy available to the next trophic level, and to decomposers when it dies.
Section 3 of 8Factors affecting secondary productivity
Farmers exploit these in intensive rearing by restricting movement and keeping animals warm, which lowers respiratory loss and raises net production.
Section 4 of 8Data handling
When data on energy in a food chain are given, check carefully which quantity is which.
| Symbol | Quantity |
|---|---|
| I | Energy in ingested food |
| F | Energy lost in faeces and urine |
| R | Energy lost in respiration |
| N | Net production = I − (F + R) |
Section 5 of 8Worked example and extended application
A herbivore population in a field receives plant material containing 8 000 kJ m-2 year-1.
Note how secondary productivity relates to farming: the aim is to maximise N.
You should also be able to explain why detritivores and decomposers matter: they feed on the energy locked in faeces, urine and dead bodies, and in doing so release nutrients, so that mineral ions return to the soil for uptake by producers.
Section 6 of 8Exam-style questions
A cow ingests 40 000 kJ per day of grass. It loses 14 000 kJ in faeces and urine and 22 000 kJ in respiration. Calculate its net production per day and the percentage of ingested energy that this represents. [3]3 marks
N = 40 000 − (14 000 + 22 000) = 4 000 kJ per day. Percentage = 4 000 / 40 000 × 100 = 10%.
Explain why net production in a farmed chicken kept in a warm barn is higher than in a free-range chicken. [3]3 marks
Warm conditions mean less energy is used in respiration for maintaining body temperature. Restricted movement reduces energy spent in activity. More of the absorbed energy is therefore converted to biomass.
Section 7 of 8Key terms
| Term | Meaning |
|---|---|
| Productivity | Rate of energy storage in biomass per unit area per unit time. |
| Secondary productivity | Rate at which consumers convert absorbed food energy into new biomass. |
| Ingestion | Taking food into the body. |
| Assimilation | Absorption of digested food and its use to build body tissue or release energy. |
| Net production | Energy retained in new biomass. |
Section 8 of 8Exam technique
Marked practiceQuizzes for this lesson
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