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3.6.4Organic Chemistry

Infrared Spectroscopy

5 min read 6 parts Lesson 27 of 55 Virtual lab

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Part 1 of 6Principle of Infrared Spectroscopy

3.6.4 Infrared Spectroscopy

Covalent bonds behave like springs that vibrate at set frequencies.

1
Infrared radiation is passed through the sample and bonds absorb radiation that matches the frequency of their vibrations.
2
Absorption occurs only if the vibration changes the dipole of the bond, so polar bonds give strong peaks.
3
The detector measures the radiation transmitted, so absorption appears as a downward peak on a plot of transmittance.
4
The horizontal axis shows wavenumber in cm⁻¹, which is proportional to the frequency of the radiation.
5
Different bonds absorb at different wavenumbers, so the peaks reveal which functional groups are present.

Part 2 of 6Absorption Data

The table below gives typical wavenumber ranges taken from standard data.

Alcohols
  • A broad absorption near 3300 cm⁻¹ shows a hydrogen-bonded O–H group.
Carboxylic acids
  • They show a very broad O–H band and a C=O band, so both features together point to –COOH.
Carbonyls
  • A strong, sharp peak between 1680 and 1750 cm⁻¹ indicates C=O in aldehydes, ketones, acids and esters.
Absence of peaks
  • The lack of a broad O–H band and of C=O helps to rule out alcohols, acids and carbonyl compounds.
BondWavenumber range / cm⁻¹Appearance
O–H (alcohol)3230–3550Broad
O–H (carboxylic acid)2500–3000Very broad
C=O1680–1750Strong, sharp
C=C1620–1680Medium
C–O1000–1300Strong
C≡N2220–2260Medium

Part 3 of 6Fingerprint Region

Fingerprint Region
Location
  • The region below about 1500 cm⁻¹ contains many overlapping peaks from complex vibrations of the whole molecule.
Uniqueness
  • Each compound has its own pattern there, so two isomers can have the same functional group peaks but different fingerprints.
Identification
  • An unknown spectrum is compared with a database spectrum, and an exact match confirms identity.
Purity
  • Extra peaks that do not belong to the known spectrum can show that a sample is contaminated.

Part 4 of 6Infrared and Global Warming

Infrared and Global Warming
Greenhouse effect
  • The Earth’s surface re-emits absorbed energy as infrared radiation, and some of it is absorbed by gases in the atmosphere.
Absorbing gases
  • Carbon dioxide (C=O), methane (C–H) and water vapour (O–H) all have bonds that absorb infrared radiation.
Warming
  • The absorbed energy is re-radiated in all directions, so less escapes to space and the lower atmosphere warms.
Human impact
  • Burning fuels increases CO₂ and agriculture increases methane, strengthening the effect and contributing to global warming.

Part 5 of 6Worked Example

Question

  • A compound with formula C₃H₆O₂ shows a very broad absorption from 2500 to 3000 cm⁻¹ and a strong sharp peak at 1710 cm⁻¹.
  • Identify the functional group and one possible compound.

  1. The peak at 1710 cm⁻¹ lies in the C=O range 1680–1750 cm⁻¹, so a carbonyl group is present.
  2. A very broad band over 2500–3000 cm⁻¹ is typical of the O–H group in a carboxylic acid.
  3. Together these show a –COOH group.
  4. A compound with formula C₃H₆O₂ containing –COOH is propanoic acid, CH₃CH₂COOH.

Answer

  • The compound contains a carboxylic acid group;
    • it could be propanoic acid.

Part 6 of 6Exam Checklist & Tips

3.6.4 – Key Points for the Exam

  • Wavenumber The reciprocal of wavelength, measured in cm⁻¹, used to describe infrared absorptions.
  • Transmittance The fraction or percentage of radiation passing through the sample.
  • Fingerprint region The part of an infrared spectrum below about 1500 cm⁻¹ that is unique to each molecule.
  • Greenhouse gas A gas that absorbs infrared radiation in the atmosphere.

Common Mistakes

  • Reading the broad O–H peak of an alcohol as a sharp C=O peak, or the reverse.
  • Using infrared alone to name an unknown compound, when it only shows the groups present.
  • Stating that the fingerprint region identifies functional groups;
    • it identifies the whole molecule by matching.
  • Saying greenhouse gases absorb visible light rather than infrared radiation.
Try it in the virtual labColorimetry: Beer–Lambert law \n