| • | - The emf is maximum when the wire moves perpendicular to the field (θ = 90°) and zero when it moves along the field (θ = 0°)
- because then it does not cut any lines
| maximumwiremovesperpendicular |
| • | - If the wire is part of a closed circuit of resistance R
- the induced current is I = emf / R
| wirepartclosedcircuit |
| Example 1. | A 0.6 m metal rod moves at 3 m/s perpendicular to a 0.25 T field. emf = 0.25 × 0.6 × 3 = 0.45 V | metalmovesperpendicularfield |
| Example 2. | A coil of 50 turns has its flux changed from 0.04 Wb to 0.01 Wb in 0.1 s. |emf| = 50 × 0.03 / 0.1 = 15 V | coilturnsfluxchanged |
| Example 2a. | A rod of length 45 cm moves at 2 m/s in a direction making 30° with a field of 0.5 T. emf = 0.5 × 0.45 × 2 × sin 30° = 0.225 V | lengthmovesdirectionmaking |
| Example 2b. | - An aircraft with a wingspan of 40 m flies horizontally at 250 m/s where the vertical component of the Earth’s field is 4×10−5 T. The emf between the wing tips is 4×10−5 × 40 × 250 = 0.40 V. (It cannot light a lamp
- because no complete circuit exists.)
| aircraftwingspanflieshorizontally |
| Example 2c — finding the speed. | A 25 cm rod in a 0.4 T field has an emf of 0.15 V between its ends when moved perpendicular to the field. v = emf / (B L) = 0.15 / (0.4 × 0.25) = 1.5 m/s | fieldbetweenendsmoved |