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Explanation – Lesson 1 – Density, Liquid Pressure and Pascal Principle

Physics

Explanation – Lesson 1 – Density, Liquid Pressure and Pascal Principle

مقدمة الدرس

مقدمة الدرس

  • Fluids are materials that can flow, so both liquids and gases are fluids.
  • Liquids resist compression almost entirely and have a definite volume, while gases occupy any space available to them.
  • This lesson studies fluids at rest (hydrostatics).
  • It covers density, the pressure a liquid exerts at each point within it, and Pascal’s principle with its applications.
  • By the end of this lesson, you should be able to:
  • Recognize density and some of its medical applications.
  • Measure the pressure at a point inside a liquid.
  • Determine the relative density of oil using a practical method.
  • Solve problems related to density and pressure.
  • Explain Pascal’s principle and apply it to the hydraulic press.
Explanation – Lesson 1 – Density, Liquid Pressure and Pascal Principle · 1 / 6
المفاهيم والمصطلحات الأساسية

المفاهيم والمصطلحات الأساسية

Comparison aspectMain ideaKeywords
FluidA material that can flow. Liquids and gases are both fluidsmaterialflowLiquidsgases
Density (ρ)The mass per unit volume of a substance, ρ = m / V. Its SI unit is kg/m3.massunitvolumesubstance
Relative density, The ratio of the density of a material to the density of water at 4 °C, which is 1000 kg/m3. Relative density has no unit.ratiomaterialwater1000
Incompressible liquidA liquid that resists compression almost entirelyresistscompressionalmostentirely
Pressure at a point, The average force acting perpendicularly on a unit area surrounding that point, P = F / A. Its unit is the newton per square metre (N/m2).averageforceactingperpendicularly
Pascal (unit of pressure)1 Pascal = 1 N/m2.
Hydraulic press
  • A device with a small piston and a large piston
  • with a suitable liquid filling the space between them. A force on the small piston produces a larger force on the large piston
devicesmallpistonlarge
Pascal’s principle→, A pressure applied to a confined liquid spreads equally to every point of the liquid and to the walls of the container.
Explanation – Lesson 1 – Density, Liquid Pressure and Pascal Principle · 2 / 6
الشرح والتفصيل العلمي الشامل

الشرح والتفصيل العلمي الشامل

Density

  • Density is a basic property of any material. It is the mass per unit volume, ρ = m / V, with SI unit kg/m3.
  • Density differs from one material to another because of two factors: the difference in the atomic or molecular mass of the substance, and the difference in the spaces between its atoms or molecules.
  • An object with lower density floats on a liquid with higher density.
  • Density can be measured directly with one instrument, the hydrometer.
  • It can also be measured indirectly: the mass is measured with a balance and the volume with a graduated cylinder, then the mass is divided by the volume.

Density in medicine

  • Density is used in medical science to measure the density of blood and urine.
  • Normal blood density ranges from 1040 kg/m3 to 1060 kg/m3.
  • A higher density indicates a higher concentration of blood cells, while a lower density indicates a lower concentration, which may suggest anemia.
  • Urine density is typically about 1020 kg/m3, and certain diseases that increase salt excretion raise it.

Pressure at a point

  • Pressure at a point is the average force acting perpendicularly on a unit area surrounding that point.
  • If a force F acts perpendicularly on a surface of area A, the pressure is P = F / A, measured in N/m2.
  • Because pressure depends on area, a pointed heel can exert a greater pressure on the ground than an elephant’s foot, since the area of the pointed heel is extremely small.

Pressure inside a liquid

  • Consider a horizontal plate of area A at depth h below the surface of a liquid of density ρ.
  • The plate is the base of a column of liquid.
  • The force on the plate equals the weight of this liquid column, because the liquid is incompressible.
  • The volume of the column is Ah and its mass is Ahρ, so its weight is Fg = Ahρg, where g is the acceleration due to gravity.
  • Dividing this force by the area A gives the pressure due to the liquid alone:

P = hρg (N/m2)

  • If the free surface of the liquid is exposed to the atmospheric pressure Pa, the total pressure at a point inside the liquid is:

P = Pa + hρg

  • Observations show that the pressure at a point increases as its depth increases, and that the pressure increases with the density of the liquid at the same depth.
  • From this relation:
  • All points on the same horizontal level inside a liquid have the same pressure.
  • In connected vessels whose bases are at the same horizontal level, the liquid rises to the same level in every section, regardless of the geometric shape of each section. Thus, the sea level is the same for all interconnected seas.
  • Dams are built with thicker bases to withstand the increasing pressure with depth.
  • Divers wear suits and helmets to protect themselves from the pressure at great depths.

Immiscible liquids in a U-shaped tube

  • Water and oil do not mix, and they form a separating level in a U-shaped tube.
  • Let ho be the height of the oil above the separating level, and hw the height of the water above it.
  • The pressures at the two points on the separating level are equal:
  • Pa + ρogho = Pa + ρwghw, so ρoho = ρwhw, and ρo / ρw = hw / ho
  • By measuring ho and hw, the relative density of oil can be found.
  • Since the density of water is known, the density of the oil can then be found.

Pascal’s principle

  • Take a liquid in a glass container with a piston on top.
  • The pressure at a point at depth h is P = P1 + hρg, where P1 is the pressure at the liquid surface directly under the piston.
  • If an extra pressure ΔP is applied by placing an additional weight on the piston, the piston does not move inward, because the liquid is incompressible.
  • The pressure at the point A, at depth h, also increases by ΔP, so it becomes P = P1 + hρg + ΔP.
Pascal’s result can be summarized this way→a pressure applied to a confined liquid spreads equally to every point of the liquid and to the container walls. If the pressure rises to a certain limit, the container may break.

The hydraulic press

  • A hydraulic press has a small piston of cross-sectional area a and a large piston of cross-sectional area A, with a suitable liquid between them.
  • A force f on the small piston produces a force F on the large piston, and the pressures are equal:

f / a = F / A

  • The mechanical advantage of the press is η = F / f = A / a.
  • When the area ratio a : A is 1 : 100, a force from a 1 kg weight on the small piston balances a force from 100 kg on the large piston.
  • The large piston moves a smaller distance than the small piston, since f y1 = F y2.
  • Applications of Pascal’s principle
Comparison aspectMain ideaKeywords
Hydraulic brakes
  • A small force on the brake pedal over a relatively long distance creates a large force on the piston in the master brake cylinder. This pressure is transmitted through the brake fluid to the wheel cylinders
  • which push the brake shoes against the brake drum (rear brakes) or the brake pads against the disc (front brakes). The friction stops the wheel. The brake shoes or pads move only a small distance because the transmitted force is large
smallforcepedalover
Hydraulic liftA fluid is used to lift cars in gas stationsfluidusedcarsstations
Hydraulic excavatorThe machine relies on Pascal’s principlemachinereliesPascalprinciple
Explanation – Lesson 1 – Density, Liquid Pressure and Pascal Principle · 3 / 6
المقارنات وخريطة المفاهيم الجوهرية

المقارنات وخريطة المفاهيم الجوهرية

  • Definitions and basic concepts
  • Pressure at a point is the force acting perpendicularly on a unit area around that point. Its unit is the newton per square metre (N/m2).
  • All points on one horizontal level within a stationary fluid have the same pressure.
  • Density is the mass per unit volume. Relative density is the ratio of a material’s density to the density of water at 4 °C.
  • Pascal’s principle a pressure applied to a confined fluid spreads equally through the fluid and onto the walls of the container holding it.
  • Comparison of the main relations
Quantity Relation Notes
Density (ρ) ρ = m / V SI unit kg/m3
Relative density Density of material / density of water at 4 °C No unit; water is 1000 kg/m3
Pressure at a point P = F / A Unit N/m2 (Pascal)
Pressure due to the liquid alone at depth h P = hρg Depends on depth, density and g
Total pressure at depth h P = Pa + hρg Free surface exposed to atmospheric pressure Pa
Immiscible liquids in a U-tube ρoho = ρwhw Used to find the relative density of oil
Hydraulic press f / a = F / A Small piston a, large piston A
Mechanical advantage η = F / f = A / a Ratio of the two piston areas
Explanation – Lesson 1 – Density, Liquid Pressure and Pascal Principle · 4 / 6
أمثلة ومسائل محلولة بالخطوات

أمثلة ومسائل محلولة بالخطوات

  • Example 1 Total pressure and force on the bottom of a tank
  • Find the total pressure and the total force acting on the bottom of a tank containing saltwater of density 1030 kg/m3.
  • The base area is 1000 cm2, the water height is 1 m, the water surface is exposed to the atmosphere, g = 10 m/s2, and Pa = 1.013 × 105 N/m2.
Total pressureP = Pa + ρgh = 1.013 × 105 + 1030 × 10 × 1 = (1.013 + 0.103) × 105 = 1.116 × 105 N/m2
Convert the area1000 cm2 = 1000 × 10-4 m2
Total forceF = P × A = 1.116 × 105 × 1000 × 10-4 = 1.116 × 104 N
  • Example 2 Maximum and minimum pressure of a solid block
  • A solid rectangular block with dimensions 5 cm × 10 cm × 20 cm and density 5000 kg/m3 is placed on a horizontal surface.
  • Find the maximum and minimum pressure it exerts, with g = 10 m/s2.
Volume5 × 10 × 20 cm3 = 1000 cm3 = 10-3 m3
Force of the blockF = Vρg = 10-3 × 5000 × 10 = 50 N
Maximum pressurethe block rests on its smallest face, 5 cm × 10 cm = 5 × 10-3 m2. P = 50 / (5 × 10-3) = 104 N/m2
Minimum pressurethe block rests on its largest face, 10 cm × 20 cm = 2 × 10-2 m2. P = 50 / (2 × 10-2) = 2500 N/m2
  • Example 3 Hydraulic press
  • A hydraulic press has a small piston of cross-sectional area 10 cm2, acted on by a force of 100 N.
  • The large piston has an area of 800 cm2.
  • Take g = 10 m/s2.
Comparison aspectMain ideaKeywords
Largest mass that the large piston can lift
  • F = f × A / a = 100 × 800 / 10 = 8 × 103 N. Since F = mg
  • m = 8 × 103 / 10 = 800 kg
Since
Mechanical advantageη = A / a = 800 / 10 = 80
•Distance the small piston must travel for the large piston to rise 1 cm: f y1 = F y2, so y1 = 8000 × 1 / 100 = 80 cmDistancesmallpistonmust
Explanation – Lesson 1 – Density, Liquid Pressure and Pascal Principle · 5 / 6
تريكات الامتحان وكبسولة التفوق الوزاري

تريكات الامتحان وكبسولة التفوق الوزاري

  • Common student questions
Comparison aspectMain ideaKeywords
Which exerts more pressure, an elephant’s foot or a human heel?
  • Pressure is force divided by area. An elephant’s foot has a large area
  • while a pointed heel has a very small area
  • so the pointed heel can exert a greater pressure on the ground than the elephant’s foot
forcedividedarealarge
Does the shape of a container change the pressure at a given depth?
  • The formula P = hρg contains only the depth
  • the density and g. It does not contain the area or the shape of the container. Connected vessels with a horizontal base still hold the liquid at the same level
  • whatever their shapes
formulacontainsdensityarea
•Exam tipsExamtips
  • Use SI units density in kg/m3, pressure in N/m2, and area in m2. To convert cm2 to m2, multiply by 10-4.
  • Use P = Pa + hρg for the total pressure at a point inside a liquid whose free surface is exposed to the atmosphere. Use P = hρg only for the pressure due to the liquid alone.
  • Relative density has no unit.
  • In a hydraulic press, use f / a = F / A and η = F / f = A / a. The large piston moves a smaller distance than the small piston.
  • Pascal’s principle concerns the transmission of pressure. The force on the large piston is larger because its area is larger.
  • 1 Pascal = 1 N/m2. Standard atmospheric pressure is 1.013 × 105 N/m2, which equals 1.013 bar or 760 mm Hg.
  • Essay practice
  • Prove that the pressure at a point inside a liquid at depth h is P = Pa + ρgh.
  • What is Pascal’s principle? Explain one of its applications.
Explanation – Lesson 1 – Density, Liquid Pressure and Pascal Principle · 6 / 6