1.1.2Physical Chemistry
Mass Number and Isotopes — AQA AS Chemistry Revision Notes & Topical Questions
5 min read 6 parts Lesson 2 of 102
Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
Part 1 of 6What Is an Isotope?
Atoms of the same element can have different masses.
Definition
- Definition Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons.
Mass number
- Mass number Different neutron numbers give different mass numbers, as in carbon-12 and carbon-14.
Notation
- Notation Isotopes are written with their mass number, for example ³⁵Cl and ³⁷Cl, or chlorine-35 and chlorine-37.
Same atomic number
- Same atomic number All isotopes of an element have the same atomic number because that number defines the element.
Part 2 of 6Chemical and Physical Properties
Chemical and Physical Properties
Chemical
- Chemical Isotopes have the same electron configuration, so they react in the same way and form the same compounds.
Physical
- Physical Differences in mass cause differences in density, melting point, boiling point and rate of diffusion.
Diffusion
- Diffusion Heavier isotopes diffuse more slowly than lighter ones at the same temperature.
Example
- Example Hydrogen has isotopes with 0, 1 and 2 neutrons, all of which form water with the same chemical behaviour.
Part 3 of 6Relative Atomic Mass from Abundance
Ar is the weighted mean of the isotopic masses.
1
List each isotope’s mass number and its percentage abundance.
2
Multiply each mass number by its percentage abundance.
3
Add all of these products together to give a single total for the sample.
4
Divide the total by 100 (or by the sum of the abundances if they are given as relative amounts).
5
Quote the answer to a sensible number of significant figures, and remember relative atomic mass has no units.
Part 4 of 6Reading Data
Percentages
- Percentages If the abundances are given as percentages, they must add up to 100 as a quick check.
Ratios
- Ratios If a mass spectrum shows relative peak heights, use the heights in place of percentages and divide by their total.
Check
- Check The answer must lie between the lightest and heaviest isotope mass numbers, and nearer the more abundant isotope.
Not whole numbers
- Not whole numbers Most Ar values are not whole numbers because they are averages over several isotopes.
Part 5 of 6Worked Example
Question
- Boron has two isotopes: ¹⁰B (19.9 %) and ¹¹B (80.1 %).
- Calculate the relative atomic mass of boron to 3 significant figures.
- Multiply10 × 19.9 = 199.0 and 11 × 80.1 = 881.1.
- Add the products199.0 + 881.1 = 1080.1.
- Divide by 100: 1080.1 ÷ 100 = 10.801.
- Round to 3 significant figures.
Answer Ar of boron = 10.8
Part 6 of 6Exam Checklist & Tips
1.1.2 – Key Points for the Exam
- Isotopes Atoms of the same element with the same atomic number but different mass numbers.
- Relative atomic mass The weighted mean mass of an atom of an element compared with one-twelfth of the mass of a carbon-12 atom.
- Percentage abundance The proportion of atoms of an element that are a particular isotope.
- Nucleon A particle in the nucleus, that is a proton or a neutron.
Common Mistakes
- Saying isotopes have different numbers of protons; they differ only in neutrons.
- Claiming isotopes react differently, when their identical electron arrangements give the same chemical behaviour.
- Forgetting to divide by 100 after multiplying mass numbers by percentages.
- Giving relative atomic mass units such as grams or g mol⁻¹.
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