1.8.5Physical Chemistry
Changes Which Affect the Equilibrium — AQA AS Chemistry Revision Notes & Topical Questions
5 min read 5 parts Lesson 49 of 102
Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
Part 1 of 5Le Chatelier's Principle
If a system at equilibrium is disturbed, the position shifts to oppose the change and partly cancel its effect.
Le Chatelier's Principle
Concentration
- Concentration Adding a reactant shifts the position towards products, while removing a product has the same effect by pulling the reaction forward.
Pressure
- Pressure Raising pressure shifts the position towards the side with fewer gas moles, which reduces the pressure again.
Temperature
- Temperature Raising temperature shifts the position in the endothermic direction, absorbing the added heat energy.
Catalyst
- Catalyst A catalyst speeds up forward and reverse rates equally, so equilibrium is reached sooner but the position is unchanged.
Part 2 of 5Effects on Position and on Kc
Only temperature alters Kc
- Only temperature alters Kc Concentration and pressure changes move the position, but the ratio of concentrations restores to the same Kc.
Why Kc changes with temperature
- Why Kc changes with temperature The new equilibrium has different proportions of products and reactants, so the ratio defining Kc is different.
Equal gas moles
- Equal gas moles If both sides have the same number of gas moles, pressure changes do not shift the position at all.
| Change | Effect on position | Effect on Kc |
|---|---|---|
| Increase concentration of a reactant | Moves to the right | None |
| Increase total pressure | Moves to side with fewer gas moles | None |
| Increase temperature (exothermic forward reaction) | Moves to the left | Decreases |
| Increase temperature (endothermic forward reaction) | Moves to the right | Increases |
| Add a catalyst | No change | None |
Part 3 of 5Industrial Compromise
Industry balances yield against rate and cost, as in the Haber process: N₂(g) + 3H₂(g) ⇌ 2NH₃(g), ΔH = −92 kJ mol⁻¹.
1
The forward reaction is exothermic, so a low temperature would give a higher equilibrium yield of ammonia.
2
A low temperature makes the reaction far too slow, so a compromise of around 450 °C is used to achieve a reasonable rate.
3
Four gas moles become two, so high pressure favours ammonia, but very high pressure needs expensive plant, so about 200 atm is used.
4
An iron catalyst increases the rate at the chosen temperature without changing the equilibrium yield, saving energy and cost.
5
Unreacted nitrogen and hydrogen are recycled after ammonia is liquefied and removed, which raises the overall conversion.
Part 4 of 5Worked Example
Question
- CO(g) + 2H₂(g) ⇌ CH₃OH(g), ΔH = −91 kJ mol⁻¹.
- State and explain the effect on the equilibrium yield of methanol of (a) raising the pressure and (b) raising the temperature.
- Count gas molesthe left side has 1 + 2 = 3 mol and the right side has 1 mol.
- (a) Higher pressure favours the side with fewer gas moles, so the position shifts right and the yield of methanol increases.
- The forward reaction is exothermic (ΔH negative), so the reverse reaction is endothermic.
- (b) Raising the temperature favours the endothermic direction, so the position shifts left, the yield falls and Kc decreases.
Answer
- (a) yield increases;
- (b) yield decreases and Kc decreases.
Part 5 of 5Exam Checklist & Tips
1.8.5 – Key Points for the Exam
- Le Chatelier's principle When a change is applied to a system at equilibrium, the position shifts to oppose that change.
- Position of equilibrium The relative proportions of reactants and products present at equilibrium.
- Exothermic A reaction that releases heat energy to the surroundings and has a negative ΔH.
- Catalyst A substance that increases reaction rate by providing an alternative pathway with lower activation energy, without being used up.
Common Mistakes
- Saying a catalyst increases the yield; it only helps equilibrium to be reached faster.
- Claiming that a change in pressure or concentration alters Kc, when only temperature does.
- Forgetting to count only gaseous moles when deciding which side pressure favours.
- Writing that the equilibrium shifts to cancel the change completely, rather than only partly oppose it.
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3 & IGCSE —
Kc
- : Kc! (ΔH < 0) Kc. (ΔH > 0) Kc.
- : ( ).
- : Kc .