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1.2.1Physical Chemistry

Ionisation Energy — Edexcel AS Chemistry Revision Notes & Topical Questions

5 min read 5 parts Lesson 5 of 42

📚 Edexcel AS Chemistry Hub / Topical Revision
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Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
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Section 1 of 5Definitions and Equations

Ionisation energy measures how strongly an atom holds on to its outer electrons.

First ionisation energy
  • First ionisation energy The energy needed to remove one electron from each atom in one mole of gaseous atoms to form one mole of gaseous 1+ ions.
Equation
  • Equation For sodium: Na(g) → Na⁺(g) + e⁻, with state symbols showing that the atoms and ions are gaseous.
Second ionisation energy
  • Second ionisation energy The energy to remove one mole of electrons from one mole of gaseous 1+ ions, for example Mg⁺(g) → Mg²⁺(g) + e⁻.
Units
  • Units Ionisation energies are measured in kJ mol⁻¹ and are always positive because energy must be supplied.

Section 2 of 5Factors Affecting Ionisation Energy

Factors Affecting Ionisation Energy
Nuclear charge
  • Nuclear charge A larger number of protons attracts the outer electron more strongly, increasing the ionisation energy.
Atomic radius
  • Atomic radius The further the outer electron is from the nucleus, the weaker the attraction and the lower the ionisation energy.
Shielding
  • Shielding Inner shell electrons repel outer electrons and reduce the attraction felt from the nucleus, lowering the ionisation energy.
Down a group
  • Down a group First ionisation energy decreases because added shells increase both distance and shielding more than the extra nuclear charge matters.

Section 3 of 5Successive Ionisation Energies

1
Removing each further electron is harder because the remaining electrons are held by the same nuclear charge but with less repulsion between them.
2
Successive ionisation energies therefore increase steadily within a shell.
3
When the next electron comes from an inner, lower shell closer to the nucleus, there is a very large jump.
4
The position of the large jump shows how many electrons are in the outer shell, and so the group of the element.
5
Plotting the logarithm of the ionisation energy against the electron number shows the shells as steps in the graph.
Mg ionisationValue / kJ mol⁻¹Comment
1st738Outer 3s electron
2nd1451Second 3s electron
3rd7733Large jump: inner shell
4th10540Inner shell continues

Section 4 of 5Worked Example

Question

  • The ionisation energies of an element X in kJ mol⁻¹ are 738, 1451, 7733, 10540.
  • State its group and write the equation for its second ionisation energy.

  1. The large jump comes between the second and third values, from 1451 to 7733.
  2. So two electrons are in the outer shell, and the third is taken from a closer inner shell.
  3. Two outer electrons means the element is in Group 2; the data are those of magnesium.
  4. Second ionisation energyX⁺(g) → X²⁺(g) + e⁻, which for magnesium is Mg⁺(g) → Mg²⁺(g) + e⁻.

Answer

  • Group 2 (magnesium);
    • equation: Mg⁺(g) → Mg²⁺(g) + e⁻.

Section 5 of 5Exam Checklist & Tips

1.2.1 – Key Points for the Exam

  • First ionisation energy Energy to remove one electron from each of one mole of gaseous atoms.
  • Successive ionisation energy The energy for each further electron removed, from the ion formed in the previous step.
  • Shielding Repulsion of outer electrons by inner electrons, reducing the effective nuclear attraction.
  • Gaseous state Atoms are gaseous so that no energy is used to overcome forces between particles.

Common Mistakes

  • Leaving out state symbols from the ionisation energy equation.
  • Writing the equation with a negative sign for the electron or as an exothermic change.
  • Explaining a trend using only nuclear charge and ignoring distance and shielding.
  • Using atoms instead of 1+ ions in the equation for the second ionisation energy.

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