1.8.3Physical Chemistry
Calorimetry — Edexcel AS Chemistry Revision Notes & Topical Questions
5 min read 6 parts Lesson 35 of 42
Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
Part 1 of 6The Heat Equation
Formula
- Formula q = mcΔT, where q is heat energy in J, m is mass in g, c is specific heat capacity and ΔT is the temperature change.
Specific heat capacity
- Specific heat capacity Water has c = 4.18 J g⁻¹ K⁻¹, and dilute aqueous solutions are assumed to have the same value.
Mass of solution
- Mass of solution Assume that 1.00 cm³ of dilute solution has a mass of 1.00 g.
Enthalpy change
- Enthalpy change ΔH = −q ÷ n for an exothermic reaction, converted to kJ mol⁻¹.
Part 2 of 6Calorimetry Procedure
1
Measure the volume of each solution and record the starting temperatures.
2
Mix the solutions in an insulated polystyrene cup with a lid and stir.
3
Record the highest or lowest temperature reached, using a graph if heat loss is significant.
4
Calculate q using the total mass of solution and the temperature change.
5
Divide by the moles of the limiting reactant to find the enthalpy change per mole and attach the correct sign.
Part 3 of 6Combustion Calorimetry
Combustion Calorimetry
Setup
- Setup A spirit burner containing the fuel heats a known mass of water in a metal can.
Measurements
- Measurements Record the water temperature rise and the mass of burner before and after burning.
Calculation
- Calculation Find q from the water, then divide by the moles of fuel burned to get ΔcH.
Typical error
- Typical error Much of the heat is lost to the surroundings and the fuel burns incompletely, so the result is less exothermic than the data book value.
| Source of error | Effect on measured ΔH |
|---|---|
| Heat lost to surroundings | Smaller magnitude |
| Incomplete combustion | Smaller magnitude |
| Heat absorbed by apparatus | Smaller magnitude |
Part 4 of 6Reducing Errors
Insulation
- Insulation Use a lid and an insulated cup to reduce heat loss.
Extrapolation
- Extrapolation Plot temperature against time and extrapolate to the moment of mixing for a better ΔT.
Windshield
- Windshield Shield the burner from draughts in combustion experiments.
Repeat
- Repeat Take repeat readings and calculate a mean to reduce random error.
Part 5 of 6Worked Example
Question
- 25.0 cm³ of 1.00 mol dm⁻³ HCl is mixed with 25.0 cm³ of 1.00 mol dm⁻³ NaOH and the temperature rises by 6.8 K.
- Calculate the enthalpy of neutralisation.
- (c = 4.18 J g⁻¹ K⁻¹)
- Mass of solution = 50.0 g.
- q = 50.0 × 4.18 × 6.8 = 1421 J = 1.42 kJ.
- Moles of water formed = 0.0250 dm³ × 1.00 = 0.0250 mol.
- ΔH = −1.42 ÷ 0.0250 = −56.8 kJ mol⁻¹.
Answer ΔH ≈ −57 kJ mol⁻¹
Part 6 of 6Exam Checklist & Tips
1.8.3 – Key Points for the Exam
- Specific heat capacity Heat needed to raise 1 g of a substance by 1 K.
- Calorimeter Apparatus used to measure heat changes.
- Neutralisation Reaction of an acid with an alkali to form a salt and water.
- Extrapolation Extending a graph line to estimate a value outside the data.
Common Mistakes
- Using the mass of the reactant instead of the mass of the solution in q = mcΔT.
- Leaving q in joules while giving ΔH in kJ mol⁻¹.
- Forgetting the negative sign for an exothermic reaction.
- Dividing by moles of the excess reagent instead of the limiting reagent.
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