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1.7.4Physical Chemistry

Yield and Atom Economy — Edexcel AS Chemistry Revision Notes & Topical Questions

5 min read 6 parts Lesson 32 of 42

📚 Edexcel AS Chemistry Hub / Topical Revision
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Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
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Part 1 of 6Percentage Yield

Theoretical yield
  • Theoretical yield The maximum mass of product predicted from the balanced equation and the limiting reagent.
Actual yield
  • Actual yield The mass of product actually collected in the experiment.
Formula
  • Formula Percentage yield = actual yield ÷ theoretical yield × 100.
Why yield is below 100%
  • Why yield is below 100% Reactions may be reversible, side reactions occur, and product is lost during transfer, filtering or purifying.

Part 2 of 6Atom Economy

Atom Economy
Definition
  • Definition Atom economy measures how much of the mass of the reactants ends up in the desired product.
Formula
  • Formula Atom economy = (molar mass of desired product ÷ sum of molar masses of all products) × 100.
High atom economy
  • High atom economy Means little waste is made, such as in addition reactions that form only one product.
Low atom economy
  • Low atom economy Occurs in reactions that produce large amounts of by-products, like substitution or elimination.
Reaction typeTypical atom economy
Addition100%
SubstitutionLess than 100%
EliminationLess than 100%

Part 3 of 6Yield versus Atom Economy

1
Yield tells you how well the experiment went in practice for a particular reaction.
2
Atom economy tells you how efficient the reaction design is, whatever the experimental skill.
3
A reaction can have a high yield but poor atom economy if it makes useful product plus much waste.
4
High atom economy reduces raw material use, waste disposal costs and environmental harm.
5
Industry also considers energy use, hazards and whether by-products can be sold or recycled.

Part 4 of 6Improving Sustainability

Choose addition routes
  • Choose addition routes Reactions with only one product have 100% atom economy.
Use catalysts
  • Use catalysts Catalysts let reactions run at lower temperature and pressure, saving energy.
Recycle by-products
  • Recycle by-products Selling or reusing the waste stream increases the effective efficiency of a process.
Recycle reagents
  • Recycle reagents Unreacted starting materials can be separated and fed back into the reactor.

Part 5 of 6Worked Example

Question

  • 10.0 g of calcium carbonate is heated: CaCO₃(s) → CaO(s) + CO₂(g).
  • 5.00 g of calcium oxide is collected.
  • Calculate the percentage yield and atom economy for CaO.
  • (Mr CaCO₃ = 100.1, CaO = 56.1, CO₂ = 44.0)

  1. Moles of CaCO₃ = 10.0 ÷ 100.1 = 0.0999 mol.
  2. Theoretical moles of CaO = 0.0999 mol, so theoretical mass = 0.0999 × 56.1 = 5.60 g.
  3. Percentage yield = 5.00 ÷ 5.60 × 100 = 89.2%.
  4. Atom economy = 56.1 ÷ (56.1 + 44.0) × 100 = 56.0%.

Answer Yield = 89.2%; atom economy = 56.0%

Part 6 of 6Exam Checklist & Tips

1.7.4 – Key Points for the Exam

  • Theoretical yield Maximum possible mass of product from the equation.
  • Percentage yield Actual yield as a percentage of theoretical yield.
  • Atom economy Percentage of reactant mass that becomes useful product.
  • By-product An unwanted substance made along with the desired product.

Common Mistakes

  • Using the mass of the excess reagent to calculate theoretical yield.
  • Calculating atom economy with only one product in the denominator.
  • Quoting a percentage yield above 100% without commenting on impurities.
  • Confusing yield with atom economy; one depends on the experiment, the other on the equation.

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