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1.1.8Electricity, Energy and Waves

Electrical Power — WJEC GCSE Science (Double Award) - Physics Revision Notes & Topical Questions

5 min read 9 parts Lesson 9 of 36

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Section 1 of 9Power

Power
Power the rate at which energy is transferred by an appliance.
P
E / t
What the symbols mean: P = power (W = J s−1) · W or E = work done / energy transferred (J) · t = time (s) · F = force (N) · v = velocity (m s−1)
  • P is power (W), E is energy (J) and t is time (s).
Work done
  • Work done power can also be written P = W / t, since work done equals energy transferred.
Unit
  • Unit the watt (W) is one joule per second.
  • Larger units are the kilowatt (1 kW = 1000 W) and megawatt (1 MW = 106 W).

Section 2 of 9Electrical power equations

P = I V
  • P = I V the power dissipated by a component equals current times p.d.
Using V = I R
  • Using V = I R this gives P = I2R and P = V2 / R.
Same current
  • Same current use P = I2R, so a thick low-resistance cable stays cool.
Same p.d.
  • Same p.d. use P = V2 / R, as for appliances in parallel on the mains.

Section 3 of 9Power ratings

Meaning
  • Meaning a label of 230 V, 2000 W means the device transfers 2000 J each second at 230 V.
Normal current
  • I = P / V = 2000 / 230 = 8.7 A.
Lower voltage
  • Lower voltage the device would draw less current and have less power.
Comparing
  • Comparing a 100 W lamp transfers energy ten times as fast as a 10 W lamp.
Power and energy
  • Power and energy a higher power means more energy each second, but total energy also depends on how long the device is on.

Section 4 of 9Choosing a fuse

1
Find the power rating of the appliance and the mains p.d.
2
Calculate the normal current with I = P / V.
3
List the standard fuse ratings: 3 A, 5 A and 13 A.
4
Choose the rating just above the normal current.
Too low
  • Too low the fuse blows during normal use.
Too high
  • Too high it does not protect the flex from overheating.

Section 5 of 9Comparing appliances on the mains

Same p.d.
  • Same p.d. appliances on the mains have 230 V across them, so their currents are proportional to their power ratings.
  • A 1 kW toaster draws about 4.3 A and a 2 kW kettle about 8.7 A.
Overloading
  • Overloading plugging many high-power devices into one socket adds their currents and can overload the cable and fuse.
Series resistors
  • Series resistors the common current means the larger resistor dissipates more power.
Parallel resistors
  • Parallel resistors the common p.d. means the smaller resistor dissipates more power.

Section 6 of 9Power loss in transmission

Loss
  • Loss the power lost in cables is I2R.
Reducing loss
  • Reducing loss transmit at a high voltage and low current, because P = I V lets a given power be sent with a small current if V is large.
Halving the current
  • Halving the current it cuts the heating loss to a quarter.

Section 7 of 9More from the specification

More from the specification
Coulombic repulsion between charges
  • Coulombic repulsion between charges identical charges repel each other with electrostatic force, dissipating electrical power when moved through resistive circuits.
Electrostatic repulsion and power dissipation
  • Electrostatic repulsion and power dissipation driving charges against repulsive forces requires electrical energy, dissipating electric power across resistive heating elements.
Static Electricity and Charging by Friction
  • When insulating materials like a polythene rod are rubbed with a cloth, friction transfers negative electrons, leaving the polythene negatively charged and the cloth with an equal positive charge.
Electric Charge (Q) and Current (I)
  • Electric current is the rate of flow of charge carriers around a closed circuit, defined by the formula I = ΔQ / Δt and measured in amperes (A),
  • where 1 coulomb equals 1 ampere-second.
Potential Difference and Voltage Measurement
  • Potential difference (voltage) is the electrical energy transferred per unit charge between two points in a circuit (V = W / Q), measured in volts using a high-resistance voltmeter in parallel.
Electrical Power in Circuits
  • The rate at which electrical energy is transformed in a circuit component is electrical power P, calculated using P = IV = I²R = V² / R,
  • and measured in watts (W) or joules per second.
Electromotive force
  • Energy transferred from other forms to electrical energy per unit charge.
Gold-leaf electroscope
  • A device in which a charged gold leaf falls when photoelectrons discharge the plate.
Mains supply
  • Domestic a.c. supply, rated 230 V rms at 50 Hz in the UK.
Charge
  • Quantity of electricity in coulombs, Q = It.
    What the symbols mean: Q = charge (C) · I = current (A) · t = time (s)
Electroscope
  • Instrument with a metal cap, stem and gold leaf used to detect charge.
Conductor
  • Material that allows current to flow.
Terminal
  • Connection point of a cell, labelled + or −.
Insulator
  • Material that does not allow current to flow.
Electric field
  • Region of space in which a charge experiences a force.
Alternating current
  • Current that continually reverses direction.
Field lines
  • Lines showing the direction and strength of a magnetic field.

Section 8 of 9Key terms

TermMeaning
PowerRate of energy transfer, P = E / t.
WattOne joule per second.
Power ratingPower and voltage marked on an appliance.
FuseThin wire that melts when the current exceeds its rating.
I2R lossPower lost as heat in a conductor.

Section 9 of 9Exam technique

1
Mixing power and energy — a high-power device does not use more energy if it is on only briefly.
2
Using the e.m.f. instead of the p.d. across the component in P = V2/R.
3
Choosing a fuse far above the working current — it never protects the circuit.
4
Forgetting to change kW to W in calculations with joules.

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