1.5.3Electricity, Energy and Waves
Wave Equations — WJEC GCSE Science (Double Award) - Physics Revision Notes & Topical Questions
5 min read 9 parts Lesson 31 of 36
Section 1 of 9The wave equation
The speed of a wave is the distance a crest travels each second. In one period T a crest travels one wavelength λ, so the speed is v = λ / T. Since f = 1 / T, this becomes the wave equation:
v = f λ
It applies to all wavessound, water, light and the rest of the electromagnetic spectrum.
Section 2 of 9Rearranging
f = v / λ and λ = v / f.
The speed of a wave is the distance divided by the time as for any speed, so v = d / t also applies to wave pulses, for example finding the speed of sound from an echo.
Section 3 of 9What decides the speed, frequency and wavelength
The frequency of a wave is set by the source and does not change when the wave moves into a new medium.
Typical speedssound in air about 340 m s−1, sound in water about 1500 m s−1, sound in steel about 5000 m s−1, and electromagnetic waves in a vacuum 3.0 × 108 m s−1.
Section 4 of 9Using the equation on graphs
For a fixed wave speed, a graph of wavelength against 1/frequency is a straight line through the origin with gradient v.
Section 5 of 9Measuring wave speed in practice
In a ripple tank, you can count the waves passing a mark in a known time, or use a stroboscope to freeze the pattern, measure the wavelength over several waves for accuracy, and calculate v = f λ.
Section 6 of 9Common exam problem types
Wave equation problems come in a few standard forms.
- which combines v = d / t with the fact that the sound travels there and back,
- so the distance to the reflector is half the total distance travelled.
An example of the third typea ship's sonar sends a pulse and receives the echo 0.60 s later.
Fourth, the dependence on a graph
- if you plot v against f for a fixed wavelength, you get a straight line through the origin with gradient λ.
- Check that you can read the gradient and give it a unit of metres.
Section 7 of 9Worked examples
A ripple tank wave has frequency 8.0 Hz and wavelength 2.5 cm. Calculate its speed.
λ = 2.5 cm = 0.025 m.
v = f λ = 8.0 × 0.025 = 0.20 m s−1.
A radio station broadcasts at 98 MHz. The speed of radio waves is 3.0 × 108 m s−1. Find the wavelength.
f = 98 × 106 Hz.
λ = v / f = 3.0 × 108 / 98 × 106 = 3.06 m (about 3.1 m).
A sound wave of frequency 680 Hz travels at 340 m s−1 in air and then enters water where its speed is 1500 m s−1. Find the wavelength in each.
In air: λ = 340 / 680 = 0.50 m.
In water the frequency is unchanged: λ = 1500 / 680 = 2.2 m.
Section 8 of 9Key terms
| Term | Meaning |
|---|---|
| Wave equation | v = f λ; links speed, frequency, wavelength |
| Wave speed | Distance travelled by the wave each second |
| Hertz | Unit of frequency |
| Medium | Material that sets the wave speed |
| Inverse relationship | As one quantity doubles, the other halves |
Section 9 of 9Exam technique
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