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Mathematics — First Preparatory
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Curriculum
Mathematics — First Preparatory
Unit 1: Numbers
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Ratio and Proportion
Text lesson
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Ratio and Proportion — Lesson quiz
5 questions
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Applications of Ratio and Proportion
Text lesson
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Applications of Ratio and Proportion — Lesson quiz
5 questions
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Sets and Operations on Sets
Text lesson
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Sets and Operations on Sets — Lesson quiz
5 questions
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Operations on Integers
Text lesson
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Operations on Integers — Lesson quiz
5 questions
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Operations on Rational Numbers
Text lesson
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Operations on Rational Numbers — Lesson quiz
5 questions
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Unit 2: Algebra
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Algebraic Expressions and Formulas
Text lesson
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Algebraic Expressions and Formulas — Lesson quiz
5 questions
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Linear Equations
Text lesson
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The linear equation
Rules for solving an equation
Worked examples
Common mistakes
Lesson summary
Linear Equations — Lesson quiz
5 questions
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Unit 3: Statistics
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Organizing Data
Text lesson
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Organizing Data — Lesson quiz
5 questions
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The Arithmetic Mean
Text lesson
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The Arithmetic Mean — Lesson quiz
5 questions
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Pie Charts
Text lesson
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Pie Charts — Lesson quiz
5 questions
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Unit 4: Geometry
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Types of Angles and Their Relations
Text lesson
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Types of Angles and Their Relations — Lesson quiz
5 questions
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Quadrilaterals
Text lesson
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Quadrilaterals — Lesson quiz
5 questions
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Polygons
Text lesson
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Polygons — Lesson quiz
5 questions
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Text lesson
Linear Equations
Mathematics — First Preparatory
Linear Equations
Explanation
Practice
Rules for solving an equation
Rules for solving an equation
We solve an equation by doing the same operation to both sides, which keeps the two sides equal.
In this way we isolate the variable on one side:
Add or subtract the same number on both sides to remove a constant term.
Multiply or divide both sides by the same number to remove a coefficient.
Remove brackets first, and simplify each side before solving.
If there are fractions, multiply both sides by the common denominator.
If the variable appears on both sides, collect the terms with the variable on one side and the numbers on the other side.
An equation with fractions
To solve (x + 1) ÷ 2 + x ÷ 3 = 4, multiply both sides by the common denominator 6.
This gives 3(x + 1) + 2x = 24.
Remove the bracket to get 3x + 3 + 2x = 24, so 5x = 21 and x = 21 ÷ 5 = 4.2.
Check: (4.2 + 1) ÷ 2 + 4.2 ÷ 3 = 2.6 + 1.4 = 4.
Notice that the solution may be a decimal or a fraction
and it does not have to be a whole number.
Linear Equations · 2 / 5
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