| Comparison aspect | Main idea | Keywords |
|---|---|---|
| Example 1 |
| trianglemediancentroidlies |
| Solution |
| Check |
| Example 2 |
| coordinateplaneverticestriangle |
| Solution | The midpoint of BC is M(3, 3). The centroid is G = ((0 + 6 + 0) ÷ 3, (0 + 0 + 6) ÷ 3) = (2, 2). The length AM = √(32 + 32) = √18, and AG = √(22 + 22) = √8. Since √8 = (2/3) × √18, the property holds. | midpointcentroidlengthSince |
| Example 3 |
| Findcoordinatescentroidtriangle |