Curriculum
Course: Science — Second Preparatory
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Curriculum

Science — Second Preparatory

Text lesson

Changes of State

Science — Second Preparatory

Changes of State

Applications and worked examples

Applications and worked examples

Key points
Example 1: heat needed to melt ice.How much heat is needed to melt 0.2 kg of ice at 0 °C?
Solutionuse Q = m × L, where m is the mass and L is the latent heat of fusion.

Q = 0.2 × 336 = 67.2 kJ

Comparison aspectMain ideaKeywords
Example 2: heating water.How much heat is needed to raise the temperature of 0.5 kg of water from 20 °C to 80 °C? The specific heat capacity of water is 4200 J/(kg·°C)muchneededraisetemperature
Solution
  • use Q = m × c × ΔT
  • where ΔT is the change in temperature
changetemperature

ΔT = 80 − 20 = 60 °C

Q = 0.5 × 4200 × 60 = 126000 J = 126 kJ
Example 3: boiling water.How much heat is needed to turn 0.1 kg of water at 100 °C into steam at 100 °C?
SolutionQ = m × L = 0.1 × 2260 = 226 kJ
Simple experiment→Put a few drops of alcohol on the back of your hand. You will feel cold as it evaporates. The evaporation takes heat from your skin, and the same effect happens when your body sweats.
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