1.4.5Additional lessons
Avogadro’s Law — IB Chemistry HL Revision Notes & Topical Questions
5 min read 5 parts Lesson 18 of 172
Curriculum Equation Key قوانين المول والحسابات الكيميائية - Moles & Stoichiometry FormulasFast Exam Solution
n = m / M_r | N = n × N_A (6.022 × 10²³) | M = n / V | V_gas = n × 22.4 L (STP)
Word Equation & Conditions: عدد المولات = الكتلة بالجرام ÷ الكتلة المولية | عدد الجسيمات = عدد المولات × عدد أفوجادرو
Location & Specifications: كيمياء التحصيلي وثانوي وبكالوريا و Cambridge IGCSE Chemistry.
Section 1 of 5The Law
Equal volumes of different gases contain equal numbers of molecules under the same conditions.
Statement
- Statement At the same temperature and pressure, equal volumes of all gases contain the same number of particles.
Proportion
- Proportion Volume is directly proportional to amount of gas, so V ∝ n, or V ÷ n is constant.
Condition
- Condition Temperature and pressure must be constant and the same for all the gases compared.
Reason
- Reason Gas particles are far apart, so the volume depends on how many there are rather than on their size.
Section 2 of 5Applying to Reactions
For gases at the same temperature and pressure, volume ratios equal mole ratios.
1
Write the balanced equation, including state symbols, to see the mole ratio of the gases.
2
Replace mole ratio by volume ratio, since each mole occupies the same volume.
3
Use the ratio to find the volume of a gaseous product or a reagent needed.
4
For 2H₂(g) + O₂(g) → 2H₂O(g), 20 cm³ of hydrogen needs 10 cm³ of oxygen and gives 20 cm³ of steam.
5
Ignore liquids and solids, because the law applies only to gases.
Section 3 of 5Limits and Uses
Limits and Uses
Real gases
- Real gases The law is exact for an ideal gas and is a good approximation for real gases at low pressure and high temperature.
Molar volume
- Molar volume The same volume per mole means one value can be used for any gas under given conditions.
Comparison
- Comparison Samples of different gases of equal volume may differ greatly in mass.
Reaction yields
- Reaction yields The law lets gas volumes in reactions be compared without knowing the actual number of moles.
Section 4 of 5Worked Example
Question
- 30 cm³ of methane is burned in excess oxygen: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).
- What volume of oxygen reacts and what volume of CO₂ forms, measured under the same conditions?
- Mole ratio CH₄O₂ : CO₂ = 1 : 2 : 1.
- Volume of O₂ = 2 × 30 = 60 cm³.
- Volume of CO₂ = 30 cm³; water is a liquid so it does not count.
Answer 60 cm³ of O₂ reacts and 30 cm³ of CO₂ forms
Section 5 of 5Exam Checklist & Tips
1.4.5 – Key Points for the Exam
- Avogadro's law At constant temperature and pressure the volume of a gas is proportional to its amount.
- Ideal gas A model gas whose particles have no volume and no forces between them.
- Gas volume ratio The ratio of gas volumes in a reaction at the same temperature and pressure.
- Stoichiometry The quantitative relationship between reactants and products in an equation.
Common Mistakes
- Applying the volume ratio to a liquid product such as water at room temperature.
- Assuming equal volumes of gases have equal masses.
- Using the law when temperature or pressure differs between the gases.
- Using mass ratios from the equation as if they were volume ratios.
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