4.2.2Additional lessons
Hess’s Law — IB Chemistry HL Revision Notes & Topical Questions
5 min read 5 parts Lesson 74 of 172
Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
Part 1 of 5The Law
Statement
- Statement The enthalpy change of a reaction is the same regardless of the route taken, provided initial and final conditions are the same.
Reason
- Reason Enthalpy is a state function, so it depends only on the start and end states, and energy is conserved.
Use
- Use Reactions that are hard to measure directly can be found by combining reactions whose enthalpy changes are known.
Cycle
- Cycle An enthalpy cycle shows the direct route as one arrow and the indirect route as arrows going through other substances.
Equality
- Equality The enthalpy change of the direct route equals the sum of the changes along the indirect route.
Part 2 of 5Common Cycles
1
A formation cycle uses elements as the common point, so ΔH = ΣΔHf°(products) − ΣΔHf°(reactants).
2
A combustion cycle uses combustion products as the common point, so ΔH = ΣΔHc°(reactants) − ΣΔHc°(products).
3
Arrows pointing in the direction of the route give a positive contribution; moving against an arrow changes the sign.
4
Multiply a value by the number of moles shown in the balanced equation before adding.
5
Check that the cycle closes, meaning that both routes start and end at the same substances.
| Data type | Formula for ΔH |
|---|---|
| Formation | Σ products − Σ reactants |
| Combustion | Σ reactants − Σ products |
Part 3 of 5Rules for Manipulating Equations
Rules for Manipulating Equations
Reverse
- Reverse Reversing a reaction changes the sign of ΔH, so −393.5 becomes +393.5.
Multiply
- Multiply Multiplying all coefficients by a factor multiplies ΔH by the same factor.
Add
- Add Adding reactions adds their enthalpy changes, and species on both sides cancel.
State
- State State symbols must be the same for species that cancel.
Part 4 of 5Worked Example
Question Use ΔHc°(C₂H₄) = −1411, ΔHc°(H₂) = −286 and ΔHc°(C₂H₆) = −1560 kJ mol⁻¹ to find ΔH for C₂H₄(g) + H₂(g) → C₂H₆(g).
- Use the combustion formulaΔH = Σ ΔHc°(reactants) − Σ ΔHc°(products).
- Σ reactants = −1411 + (−286) = −1697.
- Σ products = −1560.
- ΔH = −1697 − (−1560) = −137 kJ mol⁻¹.
Answer ΔH = −137 kJ mol⁻¹
Part 5 of 5Exam Checklist & Tips
4.2.2 – Key Points for the Exam
- Hess's law The overall enthalpy change is independent of the pathway.
- State function A property that depends only on the current state of the system.
- Enthalpy cycle A diagram connecting reactants and products by alternative routes.
- Direct route The reaction path going straight from reactants to products.
Common Mistakes
- Forgetting to change the sign when a reaction is reversed.
- Using the formation formula for combustion data (or vice versa).
- Not multiplying the enthalpy values by the number of moles.
- Ignoring state symbols such as H₂O(l) and H₂O(g).
Last updated:
\n