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3.2.1Additional lessons

Representing Formulas of Organic Compounds — IB Chemistry HL Revision Notes & Topical Questions

5 min read 5 parts Lesson 59 of 172

📚 IB Chemistry HL Hub / Topical Revision
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Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
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Section 1 of 5Types of Formula

Empirical
  • Empirical The simplest whole-number ratio of atoms of each element, such as CH₂ for ethene and for hex-1-ene.
Molecular
  • Molecular The actual number of atoms of each element in one molecule, such as C₆H₁₂ for hex-1-ene.
Full structural
  • Full structural Shows every atom and every bond, so the arrangement of atoms in a molecule is clear.
Condensed structural
  • Condensed structural Writes groups along the chain, such as CH₃CH₂CH₂OH, leaving out bond lines.
Skeletal
  • Skeletal Uses a zigzag line for the carbon chain with atoms assumed at each vertex and end, and only the functional groups shown.
CompoundMolecularCondensed
EthanolC₂H₆OCH₃CH₂OH
Propanoic acidC₃H₆O₂CH₃CH₂COOH
ButaneC₄H₁₀CH₃CH₂CH₂CH₃

Section 2 of 5Writing and Reading

1
Count the carbon atoms along the longest chain, then add branches, which are alkyl groups such as –CH₃.
2
Each carbon in a saturated structure forms four bonds, so hydrogen atoms complete the valence of each carbon.
3
Functional groups such as –OH, –COOH and C=O are written at the position where they are attached.
4
In a skeletal formula, each line end and each bend is a carbon atom, and hydrogen atoms attached to carbon are not shown.
5
The molecular formula is found by counting all atoms, and the empirical formula by dividing by the highest common factor.

Section 3 of 5Choosing the Right Representation

Choosing the Right Representation
Isomers
  • Isomers Different structural formulas with the same molecular formula show that isomers exist, such as ethanol and methoxymethane.
3D features
  • 3D features Wedge and dash bonds show the three-dimensional shape around a carbon atom in stereochemistry.
Analysis
  • Analysis Combustion analysis gives mass percentages, which lead to empirical formulas before mass spectrometry gives the molecular formula.
Clarity
  • Clarity A skeletal formula is quickest for large molecules, but a full structural formula is clearest for showing bond types.

Section 4 of 5Worked Example

Question

  • A compound contains 54.5% C, 9.1% H and 36.4% O by mass and has a relative molecular mass of 88.
  • Find its empirical and molecular formulas.

  1. Divide by atomic masses
    • C 54.5 ÷ 12.01 = 4.54;
      • H 9.1 ÷ 1.008 = 9.03;
      • O 36.4 ÷ 16.00 = 2.28.
  2. Divide by the smallest value (2.28): C 1.99, H 3.97, O 1.00, giving the ratio 2 : 4 : 1.
  3. Empirical formula is C₂H₄O, with Mᵣ = 44.
  4. 88 ÷ 44 = 2, so the molecular formula is C₄H₈O₂.

Answer Empirical C₂H₄O; molecular C₄H₈O₂

Section 5 of 5Exam Checklist & Tips

3.2.1 – Key Points for the Exam

  • Empirical formula The simplest whole-number ratio of atoms of each element in a compound.
  • Molecular formula The actual number of each type of atom in one molecule.
  • Structural formula A formula showing how atoms are connected.
  • Skeletal formula A simplified drawing in which carbon and hydrogen atoms are implied.
  • Functional group An atom or group of atoms that determines characteristic reactions.

Common Mistakes

  • Counting a bend or end of a skeletal structure as a missing atom rather than a carbon atom.
  • Giving the empirical formula when the question asks for the molecular formula.
  • Writing CH₃COH instead of CH₃CHO for ethanal.
  • Forgetting hydrogen atoms attached to carbon when counting atoms from a skeletal drawing.

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