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6.1.4Additional lessons

The pH Scale — IB Chemistry HL Revision Notes & Topical Questions

5 min read 5 parts Lesson 119 of 172

📚 IB Chemistry HL Hub / Topical Revision
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Curriculum Equation Key pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: pH + pOH = 14
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Part 1 of 5Definition

6.1.4 The pH Scale

The pH scale turns very small hydrogen ion concentrations into convenient numbers.

Formula
  • pH = −log₁₀[H⁺], where [H⁺] is the hydrogen ion concentration in mol dm⁻³.
Reverse
  • The concentration is found from pH using [H⁺] = 10⁻ᵖᴴ mol dm⁻³.
Neutral
  • At 298 K, a neutral solution has pH 7, an acid has pH below 7 and an alkali has pH above 7.
Range
  • Typical values run from 0 to 14, though very strong acids and bases can be outside these limits.

Part 2 of 5A Logarithmic Scale

A Logarithmic Scale
Tenfold change
  • A decrease of one pH unit means the hydrogen ion concentration is ten times greater.
Two units
  • A solution of pH 3 has 100 times the [H⁺] of a solution of pH 5.
Significant figures
  • The number of decimal places in a pH equals the number of significant figures in [H⁺].
Measuring
  • pH is measured with a pH meter, or approximated with universal indicator which gives a colour for each range.
[H⁺] / mol dm⁻³pHNature
1.0 × 10⁻¹1.0Strongly acidic
1.0 × 10⁻⁷7.0Neutral
1.0 × 10⁻¹³13.0Strongly alkaline

Part 3 of 5Calculations

Calculators and logarithms are used for the following steps.

1
To find pH from concentration, enter the value of [H⁺] and take −log₁₀ with a calculator.
2
To find [H⁺] from pH, calculate 10 raised to the power of minus the pH.
3
For a strong monoprotic acid, [H⁺] is equal to the acid concentration because it dissociates completely.
4
For a strong diprotic acid, remember that two moles of H⁺ can be released per mole of acid.
5
Always round the final answer to the number of decimal places that matches the data.

Part 4 of 5Worked Example

Question Calculate the pH of 0.025 mol dm⁻³ HCl, and the [H⁺] of a solution with pH 3.5.

  1. HCl is a strong monoprotic acid, so [H⁺] = 0.025 mol dm⁻³.
  2. pH = −log₁₀(0.025) = 1.60.
  3. For pH 3.5: [H⁺] = 10⁻³·⁵ = 3.2 × 10⁻⁴ mol dm⁻³.

Answer pH = 1.60; [H⁺] = 3.2 × 10⁻⁴ mol dm⁻³

Part 5 of 5Exam Checklist & Tips

6.1.4 – Key Points for the Exam

  • pH The negative logarithm to base 10 of the hydrogen ion concentration.
  • Neutral solution
    • One in which [H⁺] equals [OH⁻];
      • at 298 K the pH is 7.
  • Hydrogen ion concentration The amount of H⁺ per dm³ of solution in mol dm⁻³.
  • Logarithmic scale A scale in which each unit corresponds to a tenfold change.

Common Mistakes

  • Saying that pH 3 is twice as acidic as pH 6; it is 1000 times as acidic.
  • Taking the pH of a strong acid to be −log of the acid concentration even for a diprotic acid.
  • Forgetting the negative sign in the formula.
  • Quoting too many decimal places for a pH.

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