6.2.4Additional lessons
Acids with Reactive Metals — IB Chemistry HL Revision Notes & Topical Questions
5 min read 5 parts Lesson 135 of 172
Curriculum Equation Key قوانين الرقم الهيدروجيني والاتزان الأيوني - pH & Acid-Base Equilibrium FormulasFast Exam Solution
pH = -log[H⁺] | pOH = -log[OH⁻] | pH + pOH = 14 | [H⁺][OH⁻] = 10⁻¹⁴
Word Equation & Conditions: الرقم الهيدروجيني = -لوغاريتم تركيز أيون الهيدروجين | pH + pOH = 14
Location & Specifications: الاتزان الأيوني، كيمياء 3 ثانوي، التحصيلي، و AP Chemistry.
Part 1 of 5The General Reaction
The metal is oxidised and hydrogen ions are reduced.
Word equation
- Word equation A reactive metal and an acid react to give a salt and hydrogen gas.
Example
- Example Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g) shows magnesium chloride and hydrogen being formed.
Ionic equation
- Ionic equation Mg(s) + 2H⁺(aq) → Mg²⁺(aq) + H₂(g), leaving out the spectator chloride ions.
Observations
- Observations Bubbles of colourless gas appear, the metal dissolves and the test tube becomes warm.
Part 2 of 5Redox Explanation
Redox Explanation
Oxidation
- Oxidation Magnesium loses two electrons and its oxidation state rises from 0 to +2.
Reduction
- Reduction Each hydrogen ion gains one electron, and its oxidation state falls from +1 to 0 in H₂.
Reducing agent
- Reducing agent The metal is the reducing agent because it donates electrons to the hydrogen ions.
Acid role
- Acid role The acid is the oxidising agent because the hydrogen ions accept the electrons.
Part 3 of 5Which Metals React
1
Metals above hydrogen in the reactivity series, such as Mg, Zn and Fe, react with dilute hydrochloric and sulfuric acid.
2
The reaction rate falls from Mg to Zn to Fe, which matches the decreasing ease of oxidation.
3
Copper, silver and gold lie below hydrogen and do not release hydrogen from dilute acids.
4
Nitric acid is a special case because the nitrate ion is a strong oxidising agent and it usually gives other products than hydrogen.
5
Weak acids such as ethanoic acid react more slowly because they supply fewer H⁺ ions.
Part 4 of 5Worked Example
Question
- 0.500 g of magnesium reacts with excess dilute hydrochloric acid.
- Calculate the volume of hydrogen produced at STP.
- (Ar of Mg = 24.31;
- molar gas volume = 22.7 dm³ mol⁻¹)
- n(Mg) = 0.500 g ÷ 24.31 g mol⁻¹ = 0.02057 mol.
- The equation shows 1 mol Mg gives 1 mol H₂, so n(H₂) = 0.02057 mol.
- V(H₂) = 0.02057 mol × 22.7 dm³ mol⁻¹ = 0.467 dm³.
Answer 0.467 dm³ (467 cm³) of hydrogen
Part 5 of 5Exam Checklist & Tips
6.2.4 – Key Points for the Exam
- Salt An ionic compound formed when the H⁺ of an acid is replaced by a metal ion.
- Spectator ion An ion that is unchanged and is left out of the ionic equation.
- Molar gas volume At STP one mole of gas occupies 22.7 dm³.
- Reactive metal A metal that readily loses electrons and lies above hydrogen in the series.
Common Mistakes
- Writing H₂O or H as a product instead of hydrogen gas, H₂.
- Claiming copper reacts with dilute hydrochloric acid to release hydrogen.
- Leaving the chloride ions in an ionic equation instead of removing spectators.
- Forgetting that the number of moles of H₂ is not the same as the moles of acid.
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