Curriculum
Course: Applied Mathematics — Second Secondary
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Curriculum

Applied Mathematics — Second Secondary

Unit 1: Statics

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Unit 2: Solid and Analytic Geometry

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Text lesson

Volume of the Right Pyramid and Cone

Applied Mathematics — Second Secondary

Volume of the Right Pyramid and Cone

Lesson summary

Lesson summary

  • Volume of a pyramid = ⅓ × area of the base × perpendicular height.
  • Volume of a right circular cone = ⅓ π r² h, which is one third of the volume of the cylinder with the same base and height.
  • Area of the base depends on its shape a² for a square, √3 ÷ 4 × a² for an equilateral triangle, and π r² for a circle.
  • When the volume and one dimension are known, substitute into the rule and solve for the unknown.
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