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4.3.4Electricity and Magnetism

Combined Resistance — Cambridge IGCSE Physics 0625 Revision Notes & Topical Questions

5 min read 9 parts Lesson 40 of 65 1 quiz

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Lesson summary

4.3.4 Combined Resistance — IGCSE PHYSICS notes: Calculate the combined resistance of resistors in series and in parallel and apply the results to circuit problems.Rtotal = R1 + R2 + R3 + … — the combined resistance is the sum of the individual resistances.What the symbols mean: …

  • Adding a resistor
  • Equal resistors
  • 1 / R = 1 / R1 + 1 / R2
  • Two different resistors in parallel
  • Making values
  • Potential dividers

Part 1 of 7Resistors in series

Rtotal
R1 + R2 + R3 + …
  • the combined resistance is the sum of the individual resistances.
    What the symbols mean: RT = total resistance of resistors in series (Ω) · R1, R2 = the separate resistances (Ω)
Why
  • Why the same current passes through each, and the p.d.s add, so I R = I R1 + I R2 + …
Size
  • Size the total is greater than the largest individual resistance.
Adding a resistor
  • Adding a resistor it always increases the resistance and reduces the current.

Part 2 of 7Resistors in parallel

1Size
  • Size the combined resistance is less than the smallest individual resistance.
2Equal resistors
  • Equal resistors two equal resistors in parallel give half the resistance of one.
31 / R
1 / R1 + 1 / R2
  • the combined resistance of two resistors in parallel (Extended).
    What the symbols mean: RT = total resistance of resistors in parallel (Ω), always smaller than the smallest one · R1, R2 = the separate resistances (Ω)
  • Product over sumR = R1R2 / (R1 + R2).
  • For n identical resistors R, Rtotal = R / n.
4Adding a resistor in parallel
  • Adding a resistor in parallel it always decreases the total resistance, even a large one.

Part 3 of 7Method for parallel resistors

Method for parallel resistors
Add 1/R1 and 1/R2 to find 1/R.
Use the reciprocal button on the calculator to find R.
Check that the answer is smaller than the smallest resistor.

Part 4 of 7Mixed circuits

1
Identify the groups that are clearly in parallel or in series.
2
Replace each parallel group with its single equivalent resistance.
3
Add the series resistances to get the total.
4
Use I = V / Rtotal to find the supply current.
5
Use the p.d. and current rules to find the values in each part.

Part 5 of 7Reasons for the rules

Reasons for the rules
Series
  • Series the electrons squeeze through each resistor in turn, so the opposition adds.
Parallel
  • Parallel electrons have several routes, like extra checkout tills, so the overall opposition falls.
Two different resistors in parallel
  • Two different resistors in parallel most of the current goes through the smaller one.

Part 6 of 7Applications

Making values
  • Making values two 100 Ω resistors in parallel give 50 Ω, and 100 Ω in series with that pair gives 150 Ω.
Potential dividers
  • Potential dividers combinations of series resistors are used to divide a supply.
Household circuits
  • Household circuits adding an appliance in parallel lowers the total resistance and raises the current from the mains,
    • so overloading a socket is a fire risk.

Part 7 of 7More from the specification

More from the specification
Equivalent circuit resistance
  • Equivalent circuit resistance calculating series and parallel resistance combinations provides an algebraic means to determine total network current.
Series Resistors Calculation
  • When resistors are connected in series, total resistance is the algebraic sum of individual values (R = R₁ + R₂),
  • and identical current flows through all components.
Parallel Resistors Calculation
  • When resistors are connected in parallel, the reciprocal of total resistance equals the sum of reciprocals,
    • (1/R = 1/R₁ + 1/R₂)
  • reducing total circuit resistance below any single branch.
Kirchhoff's Current Rule at Junctions
  • In parallel circuits, total current from the power source divides among branches at each junction and re-combines before returning to the source.
Electrical Safety and Fuses
  • Fuses and earth wires protect appliances by interrupting excessive current to prevent overheating, protecting users and preventing high power dissipation faults.
Current at a junction
  • Current at a junction electric current dividing into parallel branches recombines so total current entering any junction remains conserved.
Potential difference across branches
  • Potential difference across branches components connected in parallel across a voltage source experience identical potential differences.
Electrical safety fuses
  • Electrical safety fuses fuses melt to break electrical circuits when excessive current threatens connected components or appliances.
Components
  • Perpendicular parts of a vector that add to give the vector.
Source
  • Reservoir at TH providing heat QH
Branch
  • Path connecting two junctions.
Junction
  • Place where a pipe splits or joins; flow rates add.
Insulation
  • Material that reduces thermal energy transfer.
Component
  • Part of a vector along one axis.
Circuit diagram
  • Drawing of a circuit using standard symbols.

Key terms

TermMeaning
Combined resistanceSingle resistance equivalent to several resistors.
Series ruleRtotal = R1 + R2 + …
Parallel rule1/R = 1/R1 + 1/R2 + …
ReciprocalThe value 1/x; the calculator button is x−1.
Equivalent resistanceResistance that replaces a group of resistors.

Avoid these mistakes

1
Adding the reciprocals but forgetting to invert at the end — 1/R is not R.
2
Thinking that adding a resistor in parallel increases resistance — it decreases it.
3
Giving a parallel total larger than the smallest resistor.
4
Using the series rule for branches that are in parallel.

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